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(a)
Interpretation: The structure of the substituent (methyl, bromomethyl, trichloromethyl and ethyl)needs to be determined and they need to be arranged in descending priority order.
Concept Introduction: The priority number of groups is decided by the
(b)
Interpretation:The structures of the substituents 2-methyl-propyl (isobutyl), 1-methylethyl (isopropyl), cyclohexyl)need to be drawn and they need to be arranged in descending priority order.
Concept Introduction: The priority number of groups is decided by the atomic number. Highest atomic number group gets the highest priority number. Hydrogen atom gets the lowest priority number.
(c)
Interpretation: The structures of the substituents butyl, 1-methylpropyl (sec-butyl), 2-methylpropyl (isobutyl), 1,1-dimethylethyl (tert-butyl) needs to be drawn and they should be arranged descending priority order.
Concept Introduction:The priority number of groups is decided by the atomic number. Highest atomic number group gets the highest priority number. Hydrogen atom gets the lowest priority number.
(d)
Interpretation: The structures of the substituents ethyl, 1-chloroethyl, 1-bromoethyl, 2-bromoethyl needs to be drawn and they should be arranged in descending priority order.
Concept Introduction:The highest atomic number group has the highest priority and lowest atomic number gets the lowest priority number. Hydrogen atom gets the lowest priority.
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Chapter 5 Solutions
Organic Chemistry: Structure and Function
- The IUPAC name of the compound H- is (a) 5-formylhex-2-en-3-one (b) 5-methyl-4-oxohex-2-en-5-al (c) 3-keto-2-methylhex-5-enal (d) 3-keto-2-methylhex-4-enal ( The correct statement regarding electrophile is (a) electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from another electrophile (b) electrophiles are generally neutral species and can form a bond by accepting a pair of electrons from a nucleophile (c) electrophile can be either neutral or ar positively charged species and can form a bond by accepting a pair of electrons from a nucleophile (d) electrophile is a negatively charged species and can form a bond by accepting a pair of electrons from a nucleophile.. Which among the given molecules can exhibit tautomerism? Ph Ph I II III (a) III only (c) Both I and II (b) Both I and III (d) Both II and III 1) Which of the following biphenyls is optically active?arrow_forwardDraw the structure of an alkane with molecular formula C7H16 that contains (a) one 4° carbon; (b) only 1° and 2° carbons; (c) 1°, 2°, and 3° hydrogens.arrow_forwardWhich is the structure of 3,4-dimethylhexane? * CH2 (a) CH3- CH, CH- CH- CH3 CH; CH, CH, (b) CH3- CH- CH – CH ČH3 CH2 CH31 ČH3 (c) CH3- CH, CH- CH-CH- CH3 ČH3 CH-CH; (d) CH;- CH- CH,- CH2- CH- CH3 CH3 CH3 (e) CH3- CH- CH- CH CH3 CH3 a b earrow_forward
- (a) A phenyl group has the molecular formula CH- and is represented by the symbol Bn. True False (b) Para substituents occupy adjacent carbons on a benzene ring. (c) True False (e) 3-Bromobenzoic acid can be separated into cis and trans isomers. True O False (d) 1-Phenylcyclohexene is a planar molecule. True False Benzene, naphthalene, and phenanthrene are polynuclear aromatic hydrocarbons (PAHs). Truearrow_forwardPredict which member of each group is most soluble in water, and explain the reasons for your predictions.(a) butan-1-ol, pentan-1-ol, or propan-2-ol(b) chlorocyclohexane, cyclohexanol, or cyclohexane-1,2-diol(c) phenol, cyclohexanol, or 4-methylcyclohexanolarrow_forwardConsider the tricyclic structure A. (a) Label each substituent on the rings as axial or equatorial. (b) Draw a skeletal structure for A, using wedges and dashed wedges to show whether the substituents are located above or below the rings.arrow_forward
- Propose a structural formula for the product(s) when each of the following alkenes is treated with H2O/H2SO4. Why are two products formed in part (b), but only one in parts (a) and (c)? (a) 1-Hexene gives one alcohol with a molecular for- mula of C6H14O. (b) 2-Hexene gives two alcohols, each with a molecu- lar formula of C6H14O. (c) 3-Hexene gives one alcohol with a molecular for- mula of C6H14O.arrow_forwardDraw the structures of the following compounds. (a) 1-isobutyl-4-isopropylcyclohexane; (b) tert-butylcyclopentane;(c) 3,3-diisopropyloctanearrow_forward
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