(a)
Interpretation:
The stability of the given configuration (a) has to be given.
Concept Introduction:
The bond order can be calculated as,
Bond order
Where,
(a)
Explanation of Solution
The given configuration is,
There are 3 electrons in the bonding and two electrons in the antibonding orbitals.
The bond order can be calculated as,
Bond order
Bond order
The bond order is 0.5, which is stable configuration. There is no dissociation of excited molecules.
(b)
Interpretation:
The stability of the given (b) configuration has to be given.
Concept Introduction:
Refer to part (a).
(b)
Explanation of Solution
The given configuration is,
There are 3 electrons in the bonding and 3 electrons in the antibonding orbitas.
The bond order can be calculated as,
Bond order
Bond order
The bond order is 0 which is unstable configuration. It would results in the dissociation of molecule.
(c)
Interpretation:
The stability of the given (c) configuration has to be given.
Concept Introduction:
Refer to part (a).
(c)
Explanation of Solution
The given configuration is,
There are 8 electrons in the bonding orbital and 5 electrons in the antibonding orbital.
The bond order can be calculated as,
Bond order
Bond order
The bond order is 1.5, which is stable configuration, and there would no dissociation of excited molecules.
(d)
Interpretation:
The stability of the given (d) configuration has to be given.
Concept Introduction:
Refer to part (a).
(d)
Explanation of Solution
The given configuration is,
There are 8 electrons in the bonding and nine electrons in the antibonding orbitals.
The bond order can be calculated as,
Bond order
Bond order
The bond order is -0.5 which is unstable configuration. It would results in the dissociation of the molecule.
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