9Q4-17/ An agricultural farm is cultivated in OCTOBER. The available dataare:Latitude 55° North.518 ateb oldalievodT (yabduo2 ch obucits. IFor OCTOBER (31 day)/Tmax 1860 CºTmin= 1395 Cºbre "O 90€l = 13 язамахои 10925.1=0 (m) 2.0 = sb ((cretos) 21=A18.01=(w)Calculate value of Consumptive Use of the plants cultivated in the FarmET (mm of water depth/day) during OCTOBER.(b)(b).THbag\5)BOSLIQ4-18/ An agricultural farm is cultivated by plants. The available data are:(dw) = 80 (mm of water depth/ each Irrigation process),SLIWANA(dw)A = 20 (mm of water depth/ each Irrigation process). 18w lo mum) = TCalculate values of the followings:-8.01 = (w), 15 = $1(vw),092E=n(da) (mm of water depth/ each Irrigation process) and Ea%.120.0= ^(wb)Q4-190 An agricultural farm is cultivated by plants. The available data are:A = 150000 (m²), (dw) 300 (mm of water depth/ each irrigation process)and Q = 3 (m³/s).Я чамауоиCalculate value of Teach Irrigation process.22required to operate the pumps (hr.) during b)лзамауоиQ4-20 An agricultural farm is cultivated by plants in JUNE (30 day). Theavailable data are: ЯЗЕМЕУОИ gnisub (a2000igal dose (b) = fA = 500000 (m²), (dw); = 100 (mm of water depth/ each Irrigation process)during July, ET = 13 (mm of water depth/ d) during July and LR = 35%.Calculate values of/MEMVOM gairub 19uw beniszb to in) 02302= s(V)0204=A(Y)sualuzinge A CS-4ons steb oldalisvssiroki 0 obrtjusu(dw) and (dw)A. (m of water depth/ each irrigation process).(Dw)d, (Dw)A and (Dw)i (m of water depth/JUNE)(VW)As (VW)A, (vw)d and (vw)i (m3 of water / JUNE).ANSWER/(dw)a= 0.035 (m of water depth/ each irrigation process) during June. To(dw)A= 0.065 (m of water depth/ each irrigation process) during June.olIc=5 (d/each irrigation process) during Juneobotaw to mm) Til mig!N₁ = 6 (Irrigation process/June) bolevilus ei mas lautiusings na ES-40(Dw)d = 0.21 (m of water depth/ June)Te stab oldalieve adT(Dw)A = 0.39 (m of water depth/ June). (n) 0b (garsil) 01 - A(Dw)i = 0.6 (m of water depth/ June).buo? Op abusita.l(Vw)a= 105000 (m³ of water / June).0221TUUA 10²4(VW)A = 195000 (m³ of water / June).(Vw)i = 300000 (m³ of water / June).7730 souls taluple)(b), (b), A(wb).TE

*Note: As per Bartleby's guidelines we are supposed to answer only first question. Kindly repost…

(9 Q4-17/ An agricultural farm is cultivated in OCTOBER. The available data are: Latitude 55° North. 1918 stab oldaliava odT (yab duo2 ch obucite. I For OCTOBER (31 day)/ ETmax 1860 Cº : bne 5 90€l = 13 язамахои 109 25.10(m) 2.0 = b ((tos) 21-A = ΣTmin= 1395 Cº Calculate value of Consumptive Use of the plants cultivated in the Farm I ET (mm of water depth/day) during OCTOBER. itub),(b). (b).TH ‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒ in an ninh 1001

(9 Q4-17/ An agricultural farm is cultivated in OCTOBER. The available data are: Latitude 55° North. 1918 stab oldaliava odT (yab duo2 ch obucite. I For OCTOBER (31 day)/ ETmax 1860 Cº : bne 5 90€l = 13 язамахои 109 25.10(m) 2.0 = b ((tos) 21-A = ΣTmin= 1395 Cº Calculate value of Consumptive Use of the plants cultivated in the Farm I ET (mm of water depth/day) during OCTOBER. itub),(b). (b).TH ‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒‒ in an ninh 1001

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The value of A is Blank 1 meters D ... ROADWORK AHEAD 80 60 Direction of Travel Work Area PREPARE 80 60 то 2D D STOP D A B C ROADWORK AHEAD
A 200-Kip l0ad P is applied to the Pin-ended rectongular lumber colomn Shown below. The column is braced in the weak direction Shown below. The lumber used has an allowable Stress in compresston Gal=150u psi and Ez 450 x 10° psi find the smablest cross section that can. be used ; factor of safety of 2.5 d-ab 7 ft 8 ft
Sind the mexm Sherr streer on the Ped Shown hor ziker 100 ら%/ 25T 15 20 300 * ち。 oちm 3m 15 10 10
ANSWER KEY:Elev Sta. B= 700.3994mElev Sta. C= 243.2945m∆hAB= 458.8394m∆hBC= 457.1049m∆hCA =1.7345mthese are the exact answer, please show the right solution. Thankyou :)
of permabulity তা पह श प्०्ड ल S9 wrgे तेP ल 20cm Date in క గా the diamete f lke standpipie amp The voate level in tho stndlppe 18cm and a soil sample 7.3cm n damstar and A falling Head parmacod itg tzst beas wocn
Find the area of parcel ABCD where measurements are done using orthogonal method. Do not write unit (m- or m2) to the answer box. Round the area to 2 decimal place. a=16.76 m b=27.82 m c=38,91 m h1%3D10.17m h23D13.49m Answer 767.75 Please enter your answer without using the thousand Separator.(). 0.00
2. Combined mechanical analysis of a given sample of soil was carried out. The total weight of soil used in the analysis was 350 g. The sample was divided into coarser and finer fractions by washing it through a 75 microns sieve The finer traction was 125 g. The coarser fraction was used for the sieve analysis and 50 g of the finer fraction was used for the hydrometer analysis. The test results were as given below: Sieve analysis: Particle size Mass retained g Particle size Mass retained g 4.75mm 9.0 355 A 24.5 2 00 mm 155 180H 49.0 140) ml 10.5 125- 28.0 1.00 mm 105 75 p 43.0 500 L 35.0
What are the radian and degree–minute–second equivalents for the followingangles given in grads: i.) 132.2222 grads, ii.) 82.2222 grads, iii.) 62.2222 grads.(Note: You must show all the calculations, providing answer without any calculation isnot acceptable
i need ans very very fast in 20 min and thank you | ᴅʏʙᴀʟᴀ ?✨؛
abled: Exam 2 6 Saved Select all that apply. Which of the following equilibria will shift to the right when H, is added? 2CO + 02 = 2CO, 2NAHCO3 = Na,CO3 + H,O + CO2 2H2 + O2 = 2H20 0ɔ +0°H÷0ɔ+ H_ O Stop sharing Proctorio is sharing your screen, < Pre
IP,AK/s a ".ll Asiacell earning7.uokufa.edu.iq سؤال 7 غير مجاب عليه بعد الدرجة من 10 P علم هذا السؤال What is the area of the below figure if you know x=34.1? (use Simpson's rule) 33 27 30 32 28 31 الجواب: الصفحة التالية الصفحة السابقة >> O O D
For major loss I got 9.81 as my answer not 40.77 How come?