A computer uses a mapping procedure between main and cache memory. If the main memory has 128 blocks (0 - 127) and cache memory has 32 blocks (0 - 31) with four sets (set0 - set3), List the entire block addresses of the main memory used in each of the following situations:
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- A direct-mapped cache consists of 8 blocks. A byte-addressable main memory contains 4K blocks of eight bytes each. Access time for the cache is 20 ns and the time required to fill a cache slot from main memory is 300 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty. c) Compute the effective access time for this program. Show me how to solve using this equation: EAT = H x AccessC + (1 – H) x AccessMM where H is the cache hit rate and AccessC and AccessMM are the access times for cache and main memory, respectively. thanksA direct-mapped cache consists of 16 blocks. A byte-addressable main memory contains 4K blocks of 16 bytes each. Access time for the cache is 30 ns and the time required to fill a cache slot from main memory is 250 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty. a) Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes. b) Compute the hit ratio for a program that loops 4 times from locations 0 to 42 (base 10) in memory. c) Compute the effective access time for this program.A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way set associative. You have byte address 0x8923. Show the word address, block address, tag, and index Show each access being filled in with a note of hit or miss. You are given word address and the access are: 0xff, 0x08, 0x22, 0x00, 0x39, 0xF3, 0x07, 0xc0.
- In a Direct Mapped Cache Memory Physical Address format the Cache line offset field size and word offset field size are same (with word size of one Byte). The number of tag bits in the Physical Address format is equal to the number of blocks in Cache Memory. If the Tag field Size is Mega words. 16 bits, the size of the physical Memory isFor a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many words of data are included in one cache line?For a direct-mapped cache design with a 32-bit address, the following bits of the address are used to access the cache. We assume that each word has 4 bytes. How many entries does the cache have?
- CO. A certain processor uses a fully associative cache of size 16 kB. The cache block size is 16 bytes. Assume that the main memory is byte addressable and uses a 32-bit address. How many bits are required for the Tag and the Index ticlds respectively in the addresses generated by the processor?A 2-way set-associative cache consists of four sets. Main memory contains 2K blocks of 8 bytes each and byte addressing is used.Q.) Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes.Computer Science Consider a direct-mapped cache with 8 lines, each holding 16 bytes of data. The cache is byte-addressable and the main memory consists of 64 KB, which is also byte-addressable. Assume that a program reads 16KB of memory sequentially. Answer the following questions:a) How many bits are required for the tag, index, and offset fields of a cache address?b) What is the cache size in bytes?c) What is the block size in bytes?d) What is the total number of blocks in main memory?e) How many cache hits and misses will occur for the program, assuming that the cache is initially empty?f) What is the hit ratio?g) Give an example virtual address (in BINARY) that will be placed in cache line 5.
- Q: A set-associative cache has a block size of 256 bytes and a set size of 2. The cache can accommodate 32 KB. . The size of main memory is 256 KB. Design the cache structure and show how the processor’s addresses are interpreted. Note: this question is related from coal subject.A direct-mapped cache consists of eight blocks. A byte-addressable main memory contains 4K blocks of eight bytes each. Access time for the cache is 20 ns and the time required to fill a cache slot from main memory is 200 ns. Assume a request is always started in sequential to cache and then to main memory. If a block is missing from cache, the entire block is brought into the cache and the access is restarted. Initially, the cache is empty. Show the main memory address format that allows us to map addresses from main memory to cache. Be sure to include the fields as well as their sizes. Compute the hit ratio for a program that loops 3 times from locations 0 to 65 (base 10) in memory. Compute the effective access time for this program.Q: A set-associative cache has a block size of 256 bytes and a set size of 2. The cache can accommodate 32 KB. . The size of main memory is 256 KB. Design the cache structure and show how the processor’s addresses are interpreted.Note: this question is related from coal subject.