Q2) Based on data below, draw the S-N curve for fatigue test if the specimen have neck diameter 5mm, and length between applied lode and neck diameter 30mm. Hint : Ix=(pi*D^4)/64 Number of cycle (cycle) Load ( N) 100 1*10^4 90 5*10^4 80 1*1015 60 1*10^6 50 5*10^6 40 1*10^7 a-Find the fatigue strength at 5*10A5 cycle on curve b-Find Endurance limit and show it on curve

Q2) Based on data below, draw the S-N curve for fatigue test if the specimen have neck diameter 5mm, and length between applied lode and neck diameter 30mm. Hint : Ix=(piD^4)/64 Number of cycle (cycle) Load ( N) 100 110^4 90 510^4 80 11015 60 110^6 50 510^6 40 110^7 a-Find the fatigue strength at 510A5 cycle on curve b-Find Endurance limit and show it on curve

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Q1/ The table below shows the values of stress amplitude and life cycles : Fatigue strength Sf (Mpa) Number of cycles (Nf) 474 111 417 496 352 3002 316 7065 290 21930 262 66075 The test were done, to estimate the failure, on un-notched axially load specimens under zero mean stress. Calculate a and b using the stress -life equation.
In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph.
In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10-3 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress, breaking stress, true stress at fracture, limit of proportionality, percentage elongation, percentage reduction in area. The relative density of the steel is 7.8. Draw the straight line graph. Answer: breaking stress,true stress at fracture and limit of proportionality.
In a tensile test on a specimen of black mild steel of 12 mm diameter, the following results were obtained for a gauge length of 60 mm. Load W(kN) 5 10 15 20 25 30 35 40 Extension x (10 mm) 14 27.2 41 54 67.6 81.2 96 112 When tested to destruction. Maximum load = 65 kN; load at fracture = 50 kN, diameter at fracture = 7.5 mm, total extension on gauge length = 17 mm. Find young's modulus, specific modulus, ultimate tensile stress
Table Q4 belowindicates results on a tensile test of a mild steel specimen. 95 kN Proportional Limit load Original diameter Original ga uge length 30 mm 50 mm Yield Point Load 100 kN Extension at proportional limit 0.050 mm Maximum recorded load 160 kN Final length between gauge points 58.8 mm Final minimum diameter 17.9 mm Table Q4 Calculate the following: a. Modulus of Elasticity for the mild steel. b. The proportional limit stress. C. The ultimate tensile strength. d. The percentage elongation. e. The percentage reduction in area.
Question: 8-2. Determine the material's fatigue properties for the given d... 8-2. Determine the material's fatigue properties for the given data. Shown the plots to obtain the properties. Smooth Specimen-Cyclic Data Plastic Strain Amplitude. Ae./2" Total Strain Stress Amplitude. Reversals to Amplitude. Ac/2 As, Δσ A0/2 (ksi) Failure. 2N, Basquin Equation: 2 2E E 0.0393 0.0393 0.02925 0.01975 0.0196 0.01375 162.5 0.0336 50 162 0.0336 0.0238 68 155 143.5 Δε, 122 = 6,(2N,} Coffin-Manson Equation: 0.0147 256 143.5 0.0145 350 2 136.5 130.5 126.5 121 0.00894 488 0.00521 1,364 1.386 3,540 3.590 9.100 35.200 140.000 0.00980 0.00980 0.00655 0.00630 0.00460 0.00360 0.00295 0.00534 0.00229 0.00211 0.00059 119 Δε Δε, 114 %3D 106 84.5 0.00000 2 2E E 0.00000 Ao All information is given
Project 3: Table 4 shows the fatigue data of a ductile cast iron to be used for an automobile axle that rotates at an average rotational speed of 750 revolutions per minute: Tuble 4: Fuligue dula of u duclile cust iron Stress Amplitude (МPa) Cycles to Failure 248 1 X 105 236 ЗX 105 224 1X 106 ЗX 106 1 X 107 3 X 107 1 X 108 3 X 108 213 201 193 193 193 a) Make an S-N plot (stress amplitude versus logarithm cycles to failure). b) What is the fatigue limit for this alloy? c) Determine the fatigue lifetimes at stress amplitudes of 230 MPa and 175 MPa? d) Discuss your results.
Recording Help Stress (MPa) 600 500- 400- 300 200 100- 0 0.00 Tell me what you Exercise 2 Stress (MPa) 0.04 500 400 300 200- 100 0.000 0.002 0.004 0.006 Strain 0.08 Strain 0.12 0.16 0.20 Consider a cylindrical specimen of a steel alloy 10.0 mm in tension. Determine, its elongation when a load of 20,000 N is applied.
A material presents S-N fatigue behaviour shown on the right with the fatigue limit being 100 MPa. If a cylindrical bar made from the material has a diameter of 20 mm is subjected to repeated tensile stress along its axis, calculate the maximum allowable tensile load to ensure no occurrence of fatigue failure. Stress amplitude, S Fatigue limit 103 104 105 106 107 Cycles to failure, N (logarithmic scale) 108 10⁹ 1010
You have been given the S-N plot below for a test material: What is the Fatigue Limit for this test material and what would be its Fatigue Life at a stress of 130 MPa? (This question has only one correct answer) 450 400 350 300 250 200 150 100 50 104 105 106 10 108 10° Cycles to failure Stress Amplitude (MPa)
The fluctuating stresses listed in the table are found at a critical location of a component made of steel with Se = 40 ksi, Sy = 80 ksi, Sut = 110 ksi and f= 0.87. These stresses are applied on the part within 10 s. What is the accumulative damage of this part? What is the life of the part in hours if this stress pattern continues to repeat for the remained of the part's life? Use Goodman criterion and Miner's rule in your solution. Loading order |Omin o max |Number of cycles -20 30 -10 50 1 3. -30 30 1
A strain gauge mounted at a potentially critical point in a steel part has recorded the stress history shown below during 20 seconds of typical use. Identical parts have been fatigue tested under constant amplitude loading with R = -1 to give an endurance limit of 60 ksi and a fatigue strength of 140 ksi at N = 1000 cycles. The steel used has an ultimate strength of 165 ksi. Estimate the fatigue life of the part under typical use. How much will the fatigue life in problem 3 (above) be reduced if a mean stress of 10 ksi is added to the stress history given?