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To graph Problems 59-62, use a graphing calculator and refer to the normal
Graph equation (1) with
(A)
(B)
Graph both in the same viewing window with
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- (6) Find the mean , variance, autocorrelation function P for the following models: a. Y= 0.6Y+e,- 0.4e t-1 1 1 b.Y, = 2+e;-¿e,s*7 4arrow_forwardQuestion 4. The distribution of yield strength of steel bars in batch A is normal with mean 40,000 psi and the coefficient of variation 10% while the yield strength of steel bars in batch B has a lognormal distribution with the same mean and the same of coefficient of variations as those of batch A. If it is specified that the bars with the yield strength less than 30,000 psi are considered defective and cannot be used for construction, which has higher probability to be defective, a bar from batch A or B?arrow_forwardWe analyze a data set with Y = stopping distance of a car and X = speed of the car when the brakes were applied, %3D and after running the data in STATISTICA, we obtain the following results. Std.Err. of b Std.Err. of b* t(61) p-value b* N=63 Intercept Speed -20.2734 3.1366 -6.26038 20.67978 0.000000 0.000000 3.238368 0.935504 0.045238 0.151674 Sums of df Mean p-value Squares Squares 59540.15 Effect 59540.15 427.6534 0.000000 Regress. Residual 1 8492.74 61 139.23 Total 68032.89 Speed X StopDist Y Speed squared StopDist squared Speed StopDist 65853 Total 1195 2471 28719 164951 One of the observations is (X = 39, Y = 138). The value of the internal studentized residual is . (final answer to 2 decimal places e.g. 2.12) Hence, the point (39, 138) an outlier. (choose from is or is not)arrow_forward
- Consider the following scenario for Questions 6 through 9: The City of Bellmore’s police chief believes that maintenance costs on high-mileage police vehicles are much higher than those costs for low-mileage vehicles. If high-mileage vehicles are costing too much, it may be more economical to purchase more vehicles. An analyst in the department regresses yearly maintenance costs (Y) for a sample of 200 police vehicles on each vehicle’s total mileage for the year (X). The regression equation finds: Y = $50 + .030X with a r2 of .90 What is the IV? What is the DV? If the mileage increases by one mile, what is the predicted increase in maintenance costs? If a vehicle’s mileage for the year is 50,000, what is its predicted maintenance costs? What does an r2 of .90 tell us? Is this a strong or weak correlation? How can you tell?arrow_forwardA sample of n = 15 scores ranges from a high of X = 11 to a low of X = 3. If these scores are placed in a frequency distribution table, how many X values will be listed in the first column?arrow_forwardQUESTION 14 Let X represent the width and Y represent the length of rectangular panels used for interior doors (in inches). Suppose X is normally distributed with a mean of 20 inches and standard deviation of 1.2 inches, and Y is normally distributed with a mean of 4 inches and a standard deviation of 0.65 inches. Furthermore, the covariance between X and Y is 0.325. Consider the perimeter of a panel - that is, consider 2 X+2 Y. Which of the computations below is the proper way to calculate the variance? O A. V(2X + 2Y) = (2)(1.2)2 + (2)(0.65)2 + (2)(2)(2)(0.325) O B. V(2X + 2Y) = (2)(1.2)2+(2)(0.65)2 + 0.325 OC. V(2X + 2Y) = (4)(1.2)2 + (4)(0.65)2+(2)(2)(2)(0.325) O D. V(2X + 2Y) = (4)(1.2)2 + (4)(0.65)2 +0.325arrow_forward
- Suppose ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 9, x = 113.3, s₁=5.01, n = 9, y = 129.6, and s₂ = 5.34. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT -21.57 1x ) Does the interval suggest that precise information about the value of this difference is available? Because the interval is so narrow, it appears that precise information is available. Because the interval is so narrow, it appears that precise information is not available. Because the interval is so wide, it appears that precise information is available. Because the interval is so wide, it appears that precise information is not available. x -11.06arrow_forwardQuestion 7.2.9 A chemist has a 5-gallon sample of river water taken downstream from the outflow of a chemical plant. He is concerned about the concentration, c (in parts per million), of a certain toxic substance in the water. He wants to take several measurements, find the mean concentration of the toxic substance for this sample, and have a 95% chance of being within 5 parts per million of the true mean value of c. If the concentration of the toxic substance in all measurements is normally distributed with o = 12.50 parts per million, what is the minimum integer number nof measurements needed to achieve this goal?arrow_forwardSuppose ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 9, x = 113.5, s₁=5.08, n = 9, y = 129.7, and s₂ = 5.34. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALT -22.73 X -10.12 1x )arrow_forward
- Suppose ₁ and ₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. The data follows: m = 9, x = 113.5, s₁ = 5.08, n = 9, y = 129.7, and s₂ = 5.34. Calculate a 95% CI for the difference between true average stopping distances for cars equipped with system 1 and cars equipped with system 2. (Round your answers to two decimal places.) USE SALTarrow_forwardThe following data were collected in the study described in Problem 1 relating hypertensive status measured at baseline to incident stroke over 5 years. Free of Stroke at 5 Years Stroke Baseline: Not Hypertensive 932 58 Baseline: Hypertensive 254 106 Compute the incidence of stroke in this study, overall. 0.294 0.121 0.059 0.879arrow_forwardFor Problem 19.33 , determine the probability (assuming normal distribution) that a bottle would be filled with less than 495 milliliters.arrow_forward
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