Explanation Given info: The given control limits are, LCL = s 2 ¯ χ 0.999 , n − 1 2 n − 1 and UCL = s 2 ¯ χ 0.001 , n − 1 2 n − 1 , where S 2 is the sample variance of a normal random sample, ( n − 1 ) S 2 σ 2 has a chi-square distribution with degrees of freedom n − 1 . It is given that, the lower and upper tail of chi squared critical values for 5 df are 0.210 and 20.515, respectively. Calculation: Variable transformation : Software procedure: Step by step procedure to make variable using MINITAB software is given as, Choose Calc>Calculator . In Store result in variable , enter Square of Standard deviation ( s i 2 ) . In Expression , enter ‘Standard deviation’* ‘Standard deviation’. Click OK . The transformed variable is stored in the column of ‘ s i 2 ’. Mean: Software procedure: Step by step procedure to get obtain mean, standard deviation and range using MINITAB software is given as, Choose Stat > Basic Statistics > Display Descriptive Statistics . In Variables enter the columns Square of Standard deviation ( s i 2 ) . Under Statistics , click the box of Mean . Click OK . The output using MINITAB software is given as, Thus, s i 2 ≈ 1.67 Degrees of freedom: The degrees of freedom for chi-square test statistic for sample size n is given as d f = n − 1

Probability and Statistics for Engineering and the Sciences

9th Edition

ISBN: 9781305251809

Author: Jay L. Devore

Publisher: Cengage Learning

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Chapter 16.3, Problem 20E

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Obtain the given chart for the data of exercise 11.

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Chapter 16 Solutions

Probability and Statistics for Engineering and the Sciences

Ch. 16.1 - A control chart for thickness of rolled-steel...Ch. 16.1 - Refer to Exercise 1 and suppose the ten most...Ch. 16.1 - Suppose a control chart is constructed so that the...Ch. 16.1 - A cork intended for use in a wine bottle is...Ch. 16.1 - If a process variable is normally distributed, in...Ch. 16.2 - In the case of known and , what control limits...Ch. 16.2 - Consider a 3-sigma control chart with a center...Ch. 16.2 - The table below gives data on moisture content for...Ch. 16.2 - Refer to the data given in Exercise 8, and...Ch. 16.2 - When installing a bath faucet, it is important to...

Ch. 16.2 - The accompanying table gives sample means and...Ch. 16.2 - The accompanying table gives sample means and...Ch. 16.2 - Prob. 13E Ch. 16.2 - Prob. 14E Ch. 16.2 - Prob. 15E Ch. 16.3 - A manufacturer of dustless chalk instituted a...Ch. 16.3 - Subgroups of power supply units are selected once...Ch. 16.3 - Prob. 18E Ch. 16.3 - The accompanying table gives sample means and...Ch. 16.3 - Prob. 20E Ch. 16.4 - On each of the previous 25 days, 100 electronic...Ch. 16.4 - A sample of 200 ROM computer chips was selected on...Ch. 16.4 - Prob. 23E Ch. 16.4 - Prob. 24E Ch. 16.4 - Prob. 25E Ch. 16.4 - Prob. 26E Ch. 16.4 - Prob. 27E Ch. 16.4 - Prob. 28E Ch. 16.5 - Prob. 29E Ch. 16.5 - Prob. 30E Ch. 16.5 - The standard deviation of a certain dimension on...Ch. 16.5 - Prob. 32E Ch. 16.6 - Consider the single-sample plan with c = 2 and n =...Ch. 16.6 - A sample of 50 items is to be selected from a...Ch. 16.6 - Prob. 35E Ch. 16.6 - Develop a single-sample plan for which AQL = .02...Ch. 16.6 - Consider the double-sampling plan for which both...Ch. 16.6 - Prob. 38E Ch. 16.6 - Refer to Example 16.11, in which a single-sample...Ch. 16.6 - Consider the single-sample plan that utilizes n =...Ch. 16 - Observations on shear strength for 26 subgroups of...Ch. 16 - The number of scratches on the surface of each of...Ch. 16 - The following numbers are observations on tensile...Ch. 16 - Prob. 44SE Ch. 16 - Prob. 46SE

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Obtain the given chart for the data of exercise 11.

Solution Summary: The author explains how to make a variable using MINITAB software.

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Obtain the given chart for the data of exercise 11.

Chapter 16 Solutions