Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 19, Problem 19.2P
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1. A jack having square threads of 50 mm nominal diameter and 10 mm pitch is supporting a load of 89 kN. A double thread is used and the coefficient of friction maybe as low as 0.10 or as high as 0.15.a. Will this screw always self-locking?b. What is the highest torque necessary to raise the load?c. What maximum torque is necessary to lower the load?d. What is the maximum torsional shear stress induced on the screw?
3) To provide a clamping force of 48,000 lb between two components of a machine (Tensile load, ignore bending), A set of six screws is used. The load is equally shared among three screws. Specify suitable standard screw, including grade of the material (Use Table 10.1 and 10.4 from the book to select the standard size screw. SAE Grade 7 type fasteners with UNC thread need to be used.). Clearly write down all the assumptions, and the details of the screw selected. Calculate the torque prescribed.
1. For a bolted assembly with six bolts, the stiffness of each bolt is k, = 3 Mlbf/in and the stiffness of the
members is km = 12 Mlbf/in per bolt. An external load of 80 kips is applied to the entire joint. Assume
the load is equally distributed to all the bolts. It has been determined to use 1/2 in-13 UNC grade 8 bolts
with rolled threads. Assume a torque co-efficient of K = 0.2.
a. Determine the maximum bolt preload that can be applied without exceeding the proof strength of the
bolts.
b. Determine the minimum bolt preload that can be applied while avoiding joint separation.
c. Determine the value of torque in units of Ibf-ft that should be specified for preloading the bolts if it is
desired to preload to 75% of the proof load.
d. Determine the yielding factor of safety for part c). (based on proof strength)
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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- 34 in 3. The following data apply to the C-clamp: a. The screw is ACME with ¾" Diameter b. Coefficient of thread friction = 0.12 c. Coefficient of collar friction = 0.23 d. Mean collar radius = 0.55 in. e. Max. clamping force = 1000 lb Determine: The tightening torque The operator force at the end of the handle (Note: Use table 8-3 to determine the screw pitch (p))arrow_forwardRequired information For a bolted assembly with six bolts, the stiffness of each bolt is kb 2 Mibf/in and the stiffness of the members is km = 13 Mlbf/in per bolt. An external load of 80 kips is applied to the entire joint. Assume the load is equally distributed to all the bolts. It has been determined to use 1/2 in-13 UNC grade 8 bolts with rolled threads. It is desired to find the range of torque that a mechanic could apply to initially preload the bolts without expecting failure once the joint is loaded. Assume a torque coefficient of K = 0.2. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Determine the maximum bolt preload that can be applied without exceeding the proof strength of the bolts once the load is applied. The maximum bolt preload that can be applied is Ibf.arrow_forward4) An electric motor purchased by your employer surprisingly arrived without a keyway in the shaft. The motor has power rating of 7.5kW & 1,800rpm & has a shaft of 17mm. It will be used to drive a centrifugal pump using cast iron sheave. Design the square key to be used in the assembly based on maximum bearing & shearing stresses of 580MPa & 370MPa, respectively, and factor of safety of 5.arrow_forward
- Problem 7: Analyse to determine the maximum service tensile live load force that can be supported by a pair of angles 2Ls 152x102x19, shown in the accompanying figure, if 4709M, Grade 345 steel and the AISC LRFD specifications are used. The live load is to be 3/2 times the dead load. The holes are drilled for 18mm rivets at standard gage distances.arrow_forwardThe width of the belt used if its thickness is 6 mm. Ans. 261 mm 8. A nylon-core flat belt has an elastomer envelop; is 200 mm wide, and transmits 60 KW at a belt speed of 25 m/s. The belt has a mass of 2 kg/m of the belt length. The belt is used in a crossed configuration to connect a 300 mm diameter driving pulley to a 900 mm diameter driven pulley at a shaft spacing of 6 m. A. Calculate the belt length and the angles of wrap. Ans. 13.95 m, 3.34 rad or 191.4° B. Compute the belt tensions based on a coefficient of friction of 0.33. Ans. 1.76 KN, 1.96 KNarrow_forwardIn the Bolted Connection shown, find the following by ASD.Specifications:M20 Bolts in standard holes. Nominal hole diameter = 22mmEffective Hole diameter = nominal hole diameter + 2 mmA325 steel boltAssume thread in shear planeFv = 372 MPaProperties of Angle Bar< 125 x 125 x 13 mmA = 3065 mm²x = 36.3 mmy = 36.3 mmFy = 248 MPa , Fu = 410 MPa 1. For angle bars used as bolted tension element connected to another element only on one leg, the effective area Ae = UAn. Where: An = Net area, U = Shear lag factor = 1 – x/L, L= center to center longitudinal distance of extremely located fasteners, X= distance from centroid of angle bar to surface of contact of joined elements. What is the shear lag factor of our angular bar? a. 0.454 b. 0.9 c. 0.838 d. 0.869 2. Considering RUPTURE of angle bar, what is the allowable force P that the connection can handle if allowable RUPTURE stress in net area of angle bar is Fu/2 a. 463.83 kN…arrow_forward
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