EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 2, Problem 2.60P
To determine
The modulus of resilience of cold worked steel and cold worked copper.
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A part made from hot-rolled AISI 1212 steel undergoes a certain amount
of cold-work operation. If the ultimate strength of the material after cold work
operation was 80 kpsi.
(a) Determine the percentage of cold work
(b) Obtain the yield strength after the cold work
(c) Determine the hardness of the material before and after the cold work
operation
As the tempering temperature of a heat treated steel increases the associated values of Brinnell hardness also increase, while the values of tensile strength and yield strength decrease. True or false
98
Z 161423820785837...
->
Choose the correct answer for the following:
1- Cast iron the refined form of ?
a- Pig iron
b- carbon
C- molybdenum
2- Proof stress is used when the material ?
a- Don't have clear yield point in stress-strain diagram.
b- Have clear yield point.
C- Have no elasticity
3- Ductile material ?
a- Have elongation before failure.
b- Doesn't have elongation before failure.
c- When failure the section of failure flat.
4- Compression test is the opposite of tensile test ?
a- According to direction of applied load.
b- Is the same direction of applied load with tensile test.
c- Compression test used with metallic materials to
determincition Its properties.
5- Impact test ?
a- Used to measuring the stress.
b- Used to measuring the energy absorbed in bending or
breaking the specimen.
c- Used to measuring the plasticity.
6- Vacancy diffusion this tape occurs in all metals or alloys
a- With Fcc only types of crystal structures
b- With Fcc Bcc and Hcp types of crystal…
Chapter 2 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
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- : Brinell Hardness and Ultimate Tensile Stress A steel member has a Brinell of H = 275. Estimate the ultimate strength of the steel in MPa. A gray cast iron part has a Brinell hardness number of H₂= 200. Estimate the ultimate strength of the part in kpsi. Make a reasonable assessment of the likely grade of cast iron by comparing both hardness and strength to material options in Table A-24. A part made from 1040 hot-rolled steel is to be heat treated to increase its strength to approx- imately 100 kpsi. What Brinell hardness number should be expected from the heat-treated part?arrow_forward(ii) The turbine blade root is found to contain a surface fatigue crack of 3.3 mm during a routine maintenance inspection. The major stop-start load cycle is experienced twice per day with a minimum stress of 34 MPa and a maximum stress of 195 MPa. The turbine blade has a KIC of 75 MPa√m. Fatigue crack growth rate data for this alloy is given by: the Paris law constant, A = 4.5 x 10-11 and the Paris law exponent, m = 3.8. How many more stop-starts would you recommend be used? Explain your reasoning. You can assume the shape factor Q = 1.2, K is in MPaNm and a (crack length) is in marrow_forwardProblem 2: A catastrophic failure occurred to a 7079-T6 aluminum alloy shaft. The maximum tensile stress was specified as 30% of the yield stress (0₂ = 300 MPa) and the stress ratio R was zero. Post-failure examination found that fatigue crack growth striation started at a depth of 2.0 cm from the surface, and the striation spacing was 1.3 x 10-4 cm. The fatigue-crack growth behavior of the aluminum alloy is given in the right figure. The manufacturer claimed that the part was overloaded by the user, but the user denied the allegation and sued the manufacturer. As a mechanical engineer, what is your verdict based on your calculation? da/dN (μm)/cycle 4 6 8 10 2.5TTTTT 1.0 0.25 Titanium Aluminum 0.05- 10 20 30 ksi Vin 40 60 80 100 • 200 Som 200 T -Steel 80 AK (MN/m2) 400 600 1000 • A533 alloy steel Ni-Mo-V alloy steel A HP 9-4-25 alloy steel 7079-T6 aluminum alloy 5456-H321 aluminum alloy Ti-6 Al-4V titanium alloy L 180 T 600 100 480 460 40 uin./cyclearrow_forward
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- Using various tables, determine the specific strength (yield strength-to-density ratio) in unit of kN⋅m/kg for AISI 1015 hot-rolled steel, 7075-T6 aluminum alloy, Ti-0.2 Pd titanium alloy, and ASTM No. 60 gray cast iron.arrow_forwardDetermine the indentation diameter and the surface area of indentation of a copper material subjected to a Brinell hardness test with a test force of 7.1 kN using a hardened steel ball indentor of 9 mm. Take the Brinell Hardness Number as 955. Solution: i) Indentation Diameter (in mm) = 3.0314043041657 ii) Surface Area of Indentation (in mm?) = 7.434554973822 glish (United States) earch %23arrow_forwardA hot rolled AISI 1212 steel is given a cold work of 20 percent. Determine the new values of the yield strength and the ultimate resistance.arrow_forward
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