C++ How to Program (10th Edition)
C++ How to Program (10th Edition)
10th Edition
ISBN: 9780134448237
Author: Paul J. Deitel, Harvey Deitel
Publisher: PEARSON
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Chapter 21, Problem 21.19E

(Erasing Characters from a string) Write a program that erases the sequences "by “and “By" from a string.

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(1) Prompt the user for a string that contains two strings separated by a comma. (1 pt) Examples of strings that can be accepted: Jill, Allen Jill , Allen Jill,Allen Ex: Enter input string:Jill, Allen (2) Print an error message if the input string does not contain a comma. Continue to prompt until a valid string is entered. Note: If the input contains a comma, then assume that the input also contains two strings. (2 pts)Ex: Enter input string:Jill AllenError: No comma in string. Enter input string:Jill, Allen (3) Extract the two words from the input string and remove any spaces. Store the strings in two separate variables and output the strings. (2 pts)Ex: Enter input string:Jill, AllenFirst word: JillSecond word: Allen (4) Using a loop, extend the program to handle multiple lines of input. Continue until the user enters q to quit. (2 pts)Ex: Enter input string: Jill, Allen First word: Jill Second word: Allen Enter input string: Golden , Monkey First word: Golden Second word:…
(Financial: credit card number validation) Credit card numbers follow certain pat- terns. A credit card number must have between 13 and 16 digits. It must start with: 4 for Visa cards 5 for Master cards 37 for American Express cards 6 for Discover cards In 1954, Hans Luhn of IBM proposed an algorithm for validating credit card numbers. The algorithm is useful to determine whether a card number is entered correctly or whether a credit card is scanned correctly by a scanner. Credit card numbers are generated following this validity check, commonly known as the Luhn check or the Mod 10 check, which can be described as follows (for illustra- tion, consider the card number 4388576018402626): 1. Double every second digit from right to left. If doubling of a digit results in a two-digit number, add up the two digits to get a single-digit number. 4388576018402626 → 2 * 2 = 4 → 2 * 2 = 4 → 4 * 2 = 8 → 1 * 2 = 2 6 * 2 = 12 (1+ 2 = 3) → 5 * 2 = 10 (1+ 0 = 1) → 8 * 2 = 16 (1 + 6 = 7) → 4 * 2 = 8
[SHORT ANSWER] Use Python. Using loop, if, and string methods validate the string variable password by making sure the length of the password is at least 8 characters and has at least one alphabet and one digit. Display appropriate messages as shown in the following examples (use any additional variables):
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