(Python matplotlib or seaborn) CPU Usage We have the hourly average CPU usage for a worker's computer over the course of a week. Each row of data represents a day of the week starting with Monday. Each column of data is an hour in the day starting with 0 being midnight. Create a chart that shows the CPU usage over the week. You should be able to answer the following questions using the chart: When does the worker typically take lunch? Did the worker do work on the weekend? On which weekday did the worker start working on their computer at the latest hour?   cpu_usage = [ [2, 2, 4, 2, 4, 1, 1, 4, 4, 12, 22, 23, 45, 9, 33, 56, 23, 40, 21, 6, 6, 2, 2, 3], # Monday [1, 2, 3, 2, 3, 2, 3, 2, 7, 22, 45, 44, 33, 9, 23, 19, 33, 56, 12, 2, 3, 1, 2, 2], # Tuesday [2, 3, 1, 2, 4, 4, 2, 2, 1, 2, 5, 31, 54, 7, 6, 34, 68, 34, 49, 6, 6, 2, 2, 3], # Wednesday [1, 2, 3, 2, 4, 1, 2, 4, 1, 17, 24, 18, 41, 3, 44, 42, 12, 36, 41, 2, 2, 4, 2, 4], # Thursday [4, 1, 2, 2, 3, 2, 5, 1, 2, 12, 33, 27, 43, 8,…

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Question:  A common year in the modern Gregorian Calendar consists of 365 days. In reality, Earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines the number of days in February for that year. My Code: def days_in_feb(user_year):    is_leap_year = 29    not_leap_year = 28    if user_year % 4 ==0:        return is_leap_year    elif user_year % 4 ==0 and user_year % 100 == 0 and user_year % 400 == 0:        return is_leap_year    else:          return(not_leap_year)    if __name__ == '__main__':    # Type your code here. Your code must call the function.    user_year =…