Chemistry
Chemistry
13th Edition
ISBN: 9781259911156
Author: Raymond Chang Dr., Jason Overby Professor
Publisher: McGraw-Hill Education
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Chapter 21, Problem 21.22QP
Interpretation Introduction

Interpretation:

Silicon would form n-type semiconductors or p-type semiconductors with the given elements have to be explained.

Concept introduction:

n-type semiconductors in silicon: Solid semiconducting material having donor impurities are said to be n-type semiconductors, where “n” indicates negative which means the charge of the extra electron.

p-type semiconductors in silicon: Semiconducting material having acceptor impurities are said to be p-type semiconductors, where, ”p” indicates positive.

  • Silicon atom has totally 14 electrons among them 4 electors are considered as valence electrons and these 4 valence electrons plays main role when an impurity added to it.
  • The formation of n-type or p-type semiconductors is depending upon using impurities either pentavalent or trivalent.

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Students have asked these similar questions
a) Explain the band structure of an electrical conductor (metal), a semiconductor, and an insulator at 0 K by showing the valence and conduction bands and fermi energy levels. Explain how the electrical conduction takes place in these three types of materials. Give an example for each type of material. b)Explain what n and p-type semiconductors are using their band structures. Why?
Explain the process of making an n -type and p -type semiconductor materials
what are p type and n type semiconductors?

Chapter 21 Solutions

Chemistry

Ch. 21 - Prob. 21.9QPCh. 21 - Prob. 21.10QPCh. 21 - In the Mond process for the purification of...Ch. 21 - Copper is purified by electrolysis (see Figure...Ch. 21 - Prob. 21.13QPCh. 21 - Prob. 21.14QPCh. 21 - Prob. 21.15QPCh. 21 - Prob. 21.16QPCh. 21 - Which of the following compounds would require...Ch. 21 - Although iron is only about two-thirds as abundant...Ch. 21 - Prob. 21.19QPCh. 21 - Prob. 21.20QPCh. 21 - Prob. 21.21QPCh. 21 - Prob. 21.22QPCh. 21 - Prob. 21.23QPCh. 21 - Why is potassium usually not prepared...Ch. 21 - Prob. 21.25QPCh. 21 - Prob. 21.26QPCh. 21 - Prob. 21.27QPCh. 21 - Prob. 21.28QPCh. 21 - Prob. 21.29QPCh. 21 - Prob. 21.30QPCh. 21 - Prob. 21.31QPCh. 21 - Prob. 21.32QPCh. 21 - Prob. 21.33QPCh. 21 - Prob. 21.34QPCh. 21 - Prob. 21.35QPCh. 21 - Prob. 21.36QPCh. 21 - Prob. 21.37QPCh. 21 - Prob. 21.38QPCh. 21 - Prob. 21.39QPCh. 21 - Prob. 21.40QPCh. 21 - Prob. 21.41QPCh. 21 - Prob. 21.42QPCh. 21 - Prob. 21.43QPCh. 21 - With the Hall process, how many hours will it take...Ch. 21 - Aluminum forms the complex ions AlCl4 and AlF63....Ch. 21 - The overall reaction for the electrolytic...Ch. 21 - Prob. 21.47QPCh. 21 - Write a balanced equation for the thermal...Ch. 21 - Prob. 21.49QPCh. 21 - The pressure of gaseous Al2Cl6 increases more...Ch. 21 - Starting with aluminum, describe with balanced...Ch. 21 - Prob. 21.52QPCh. 21 - Prob. 21.53QPCh. 21 - Prob. 21.54QPCh. 21 - Prob. 21.55QPCh. 21 - Referring to Figure 21.6, would you expect H2O and...Ch. 21 - A 0.450-g sample of steel contains manganese as an...Ch. 21 - Given that Gf (Fe2O3) = 741.0 kJ/mol and that Gf...Ch. 21 - Prob. 21.59QPCh. 21 - Prob. 21.60QPCh. 21 - Prob. 21.61QPCh. 21 - Explain each of the following statements: (a) An...Ch. 21 - Prob. 21.63QPCh. 21 - Write a balanced equation for the reaction between...Ch. 21 - Prob. 21.65QPCh. 21 - Explain why most metals have a flickering...Ch. 21 - Prob. 21.67QPCh. 21 - Prob. 21.68QPCh. 21 - The following are two reaction schemes involving...Ch. 21 - Prob. 21.70QPCh. 21 - Prob. 21.71QPCh. 21 - Prob. 21.72QPCh. 21 - After heating, a metal surface (such as that of a...Ch. 21 - Prob. 21.74QPCh. 21 - Prob. 21.75QPCh. 21 - As stated in the chapter, potassium superoxide...Ch. 21 - A sample of 10.00 g of sodium reacts with oxygen...
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