,magnetism of [Ni(NH 3 ) 4 ] 2+ and ’should be identified Concept introduction: The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH 3 ) 4 ] 2+ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN) 4 ] 2- has no unpaired electron thus it is diamagnetic.

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Answer 1

Question

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

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Answer 2

Question

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

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Answer 3

Question

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

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Answer 4

Question

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

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Answer 5

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

Answer 6

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

Answer 7

Chapter 23, Problem 72E

Interpretation Introduction

Interpretation:

,magnetism of [Ni(NH₃)₄]²⁺ and ’should be identified

Concept introduction:

The magnetism of any co-ordination compound is determined by the number of unpaired electron present in the molecule in their crystal field splitting diagram. In [Ni(NH₃)₄]²⁺ there are two unpaired electrons as shown in the figure. Whereas [Ni(CN)₄]^2- has no unpaired electron thus it is diamagnetic.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 23 - What is the electron configuration of the Cu+ ion?...Ch. 23 - Prob. 2SAQ Ch. 23 - Prob. 3SAQ Ch. 23 - Prob. 4SAQ Ch. 23 - Prob. 5SAQ Ch. 23 - Prob. 6SAQ Ch. 23 - Prob. 7SAQ Ch. 23 - Estimate the crystal field splitting energy (in...Ch. 23 - Use crystal field theory to determine the number...Ch. 23 - Prob. 10SAQ

Solution Summary: The author explains that the magnetism of any co-ordination compound is determined by the number of unpaired electrons present in the molecule in their crystal field splitting diagram.

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Chapter 23 Solutions