Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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Chapter 25.6, Problem 19P
Interpretation Introduction
Interpretation:
D-Allose and D-glucose are stereoisomers. In the open chain form, hexose sugars have four chiral centres. Glucose and allose differ in the stereochemistry only at carbon three and are hence called C3 epimers.
Concept introduction:
When D-glucose is treated with nitric acid, oxidation of D-glucose takes place. The
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Draw the product of the mutarotation of the monosaccharide
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ОН
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ОН
ОН
H3O+
ОН
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Raffinose is a trisaccharide (C18H32O16) isolated from cottonseed meal. Raffinose doesnot reduce Tollens reagent, and it does not mutarotate. Complete hydrolysis of raffinosegives d-glucose, d-fructose, and d-galactose. When raffinose is treated with invertase,the products are d-fructose and a reducing disaccharide called melibiose. Raffinose isunaffected by treatment with a b@galactosidase, but an a@galactosidase hydrolyzes itto d-galactose and sucrose. When raffinose is treated with dimethyl sulfate and basefollowed by hydrolysis, the products are 2,3,4-tri-O-methylglucose, 1,3,4,6-tetraO-methylfructose, and 2,3,4,6-tetra-O-methylgalactose. Determine the completestructures of raffinose and melibiose, and give a systematic name for melibiose.
A D-aldopentose A is reduced to an optically active alditol. Upon Kiliani–Fischer synthesis, A is converted to two D-aldohexoses, B and C. B is oxidized to an optically inactive aldaric acid. C is oxidized to an optically active aldaric acid. What are the structures of A–C?
Chapter 25 Solutions
Organic Chemistry
Ch. 25.1 - Prob. 1PCh. 25.2 - Prob. 2PCh. 25.2 - Prob. 3PCh. 25.2 - Prob. 4PCh. 25.2 - Prob. 5PCh. 25.3 - Prob. 6PCh. 25.3 - Prob. 7PCh. 25.4 - Prob. 8PCh. 25.4 - Prob. 9PCh. 25.4 - Prob. 10P
Ch. 25.5 - Prob. 11PCh. 25.5 - Prob. 12PCh. 25.5 - Prob. 13PCh. 25.5 - Prob. 14PCh. 25.5 - Prob. 15PCh. 25.6 - Prob. 16PCh. 25.6 - Prob. 17PCh. 25.6 - Prob. 18PCh. 25.6 - Prob. 19PCh. 25.6 - Prob. 20PCh. 25.6 - Prob. 21PCh. 25.6 - Prob. 22PCh. 25.6 - Prob. 23PCh. 25.7 - Prob. 24PCh. 25.8 - Show the product you would obtain from the...Ch. 25.SE - Prob. 26VCCh. 25.SE - Prob. 27VCCh. 25.SE - Prob. 28VCCh. 25.SE - Prob. 29VCCh. 25.SE - Prob. 30MPCh. 25.SE - Prob. 31MPCh. 25.SE - Glucosamine, one of the eight essential...Ch. 25.SE - D-Glicose reacts with acetone in the presence of...Ch. 25.SE - Prob. 34MPCh. 25.SE - Prob. 35MPCh. 25.SE - Prob. 36APCh. 25.SE - Prob. 37APCh. 25.SE - Prob. 38APCh. 25.SE - Prob. 39APCh. 25.SE - Prob. 40APCh. 25.SE - Assign R or S configuration to each chirality...Ch. 25.SE - Prob. 42APCh. 25.SE - Prob. 43APCh. 25.SE - Prob. 44APCh. 25.SE - Prob. 45APCh. 25.SE - Prob. 46APCh. 25.SE - Prob. 47APCh. 25.SE - Prob. 48APCh. 25.SE - Prob. 49APCh. 25.SE - Prob. 50APCh. 25.SE - Prob. 51APCh. 25.SE - Prob. 52APCh. 25.SE - Prob. 53APCh. 25.SE - Prob. 54APCh. 25.SE - Prob. 55APCh. 25.SE - Prob. 56APCh. 25.SE - Prob. 57APCh. 25.SE - Prob. 58APCh. 25.SE - Prob. 59APCh. 25.SE - Prob. 60APCh. 25.SE - Prob. 61APCh. 25.SE - Prob. 62APCh. 25.SE - Prob. 63APCh. 25.SE - D-Mannose reacts with acetone to give a...Ch. 25.SE - Prob. 65APCh. 25.SE - Prob. 66APCh. 25.SE - Prob. 67APCh. 25.SE - Prob. 68APCh. 25.SE - Prob. 69APCh. 25.SE - Prob. 70APCh. 25.SE - Prob. 71AP
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- A D-aldohexose A is formed from an aldopentose B by the Kiliani-Fischer synthesis. Reduction of A with NABH4 forms an optically inactive alditol. Oxidation of B forms an optically active aldaric acid. What are the structures of A and B?arrow_forward(d) Draw the structure of the expected product when monosaccharide B undergo mutarotation upon dissolving in water in the presence of Tollens reagent (AGNO3, NHẠOH). он OH O. OH OH OH monosaccharide Barrow_forwardMonosaccharide A is a diastereomer of d-lyxose. Treatment of A with nitric acid forms an optically inactive aldaric acid. A undergoes a Kiliani-Fischer synthesis to form B and C. B is oxidized by nitric acid to an optically active aldaric acid, and C is oxidized to an optically inactive aldaric acid. Wohl degradation of A forms D, which is oxidized by nitric acid to an optically inactive aldaric acid. Wohl degradation of D forms a d-aldotriose. Identify A, B, C, and D.arrow_forward
- 1. Draw Haworth projections of B-D-arabinofuranose and a-L-mannopyranose. 2. Consider the structure of the disaccharide drawn at right: НО `CH2 В ОН (a) Give the names and D/L designation for the two monosaccharides linked together. H,C-O OHO „OH OH А: НО НО A В: ОН (b) In the structure, circle the anomeric carbon of each saccharide. (c) Is each saccharide present in its a or ß anomer? Specify both A and B (d) Would this disaccharide undergo mutarotation? Why or why not? (e) Would this disaccharide react with Tollens and/or Benedicts reagent? Why or why not? (f) There are two reasons this is very unlikely to be a naturally occurring disaccharide. What about its structure suggests this is true? Give both reasons.arrow_forwardDraw the structure of: (a) a polysaccharide formed by joining D-mannose units in 1->4-ß-glycosidic linkages; (b) a polysaccharide formed by joining D-glucose units in 1->6-a-glycosidic linkages. The polysaccharide in (b) is dextran, a component of dental plaque.arrow_forwardm) Which pyranose ring (A, B, C, or D) in the tetrasaccharide below is derived from D-altrose? The Fischer projections for the four aldohexoses that make up this tetrasaccharide are shown below. B C D HOH CHO CHO CHO CHO HO+H HTOH Fонно н HOH HOH H-OH H-OH H-+-OH H-TOHHOH HOH H+OH HOHнтон нон CHOH CHOH CHOH CHOH De D-glue Dalose Datrone i NH Į HOH STEP 1 OH, HO- answer 1. Just add arrows and charges for steps 1, 2, and 3 in formation of this enamine з no arrows needed here OH н Н ЮН -OH STEP 3 :ÖH н H STEP 2 на это про за почarrow_forward
- Cellulose is not digestible by humans because it contains glucose units linked by -glycosidic bonds. O a-1,6 O a-1,4 O a-1,2 O B-1,4 O B-1,2arrow_forwardTreatment of D-glucose with NaBH4 gives an alditol A. What L-aldohexose also yields A when treated with NaBH4?arrow_forwardD-Aldopentose A is oxidized to an optically inactive aldaric acid. On Wohl degradation, A forms an aldotetrose B that is oxidized to an optically active aldaric acid. What are the structures of A and B?arrow_forward
- 6 CH2OH 4 OH 2 ОН 3 OH (d) Draw the hemiacetal that results from above acetal. (e) Draw the open chain equivalent of the sugar in part (d). (f) Classify the monosaccharide below as a D-sugar or an L-sugar. H ОН O. ОН CH2OH ОН ОНarrow_forwardDraw the structure of: (a) a polysaccharide formed by joining D-mannose units in 1→4-β- glycosidic linkages; (b) a polysaccharide formed by joining D-glucose units in 1→6-α- glycosidic linkages. The polysaccharide in (b) is dextran, a component of dental plaque.arrow_forwardВ. 1. Draw the Fischer, Haworth & chair (where applicable) representations of the given monosaccharides. Sugar Fischer Haworth Chair a CHO но H- H но OH ČH2OH D-idose (а-anomer) CH2OH FOH H- ČH2OH a ketopentose (B-anomer) b.arrow_forward
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