To find: The solution set of the given inequality.
Answer to Problem 67E
Solution set:
Explanation of Solution
Given information:
Aninequality is given as -
Concept used:
Key numbers of a polynomial are its zeros. Real zeros of a polynomial divides real line into intervals in which the polynomial does not change its sign. A test value is taken from each interval and corresponding value of inequality is calculated (whether positive or negative). The inequality maintains same sign for whole interval.
Calculation:
Given inequality is -
Key numbers are
Test interval | Test | Polynomial value
| Conclusion |
Positive | |||
Negative | |||
Positive |
From above table, it can be concluded that inequality is satisfied in the interval
Hence, solution set for the given inequality will be
Chapter 2 Solutions
EBK PRECALCULUS W/LIMITS
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- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning