Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 4.8PFS
To determine
The lightest section of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Prob 01: An 18” depth beam is bolted to a 24” depth girder is connected similar to that in figure shown below. Thediameter of the rivet is 20mm and the angles are each 100mm x 100mm x 12mm thick. For each bolt, assume thatthe allowable bearing stress is 220 MPa. Determine the allowable load P in KN on the connection. *show all theload P in kN for bearing stressBeam web thickness = 5mmGirder web thickness =
04.
For the truss shown below, design member HI using W shape of A992 steel. The loads acting on the truss
are the design panel loads. Assume that each flange will be connected to a 20-mm thick gusset plate
with two lines of three-20-mm diameter bolts as shown in the detail. For this connection, assume that
U = 0.85. The size of the member should be controlled so you must limit your selections to W8, W10,
and W12 sections.
80 KN
B
80 kN
80 KN
80⁰ kN
80 kN
=I=I1=IS
DETAIL OF CONNECTION
D
H
80 kN
5 @ 5m= 25 m
a.com
80 kN
E
F
40 kN
GIVEN:
STEEL GRADE: A992 Steel
t = 20mm
Length = 5m
h = 5m
40 kN
REQUIRED:
Design of Member HI using W shape
+ Test Adequacy
5 m
1. For the Pratt bridge truss and the loading shown below, determine the average normal stress
in member BE, knowing that the cross-sectional area of that member is 60 in².
NN
K
12-12--12--12--|
50 lips 50 kips 50. ips
Figure 1
G
xfone
Chapter 4 Solutions
Structural Steel Design (6th Edition)
Ch. 4 - Prob. 4.1PFSCh. 4 - Prob. 4.2PFSCh. 4 - Prob. 4.3PFSCh. 4 - Prob. 4.4PFSCh. 4 - Prob. 4.5PFSCh. 4 - Prob. 4.6PFSCh. 4 - Prob. 4.7PFSCh. 4 - Prob. 4.8PFSCh. 4 - Prob. 4.9PFSCh. 4 - Prob. 4.10PFS
Ch. 4 - Prob. 4.11PFSCh. 4 - Prob. 4.12PFSCh. 4 - Prob. 4.13PFSCh. 4 - Prob. 4.14PFSCh. 4 - Prob. 4.15PFSCh. 4 - Prob. 4.16PFSCh. 4 - Prob. 4.17PFSCh. 4 - Prob. 4.18PFSCh. 4 - Prob. 4.19PFSCh. 4 - Prob. 4.20PFSCh. 4 - Prob. 4.21PFSCh. 4 - Prob. 4.22PFSCh. 4 - Prob. 4.23PFSCh. 4 - Prob. 4.24PFSCh. 4 - Prob. 4.25PFSCh. 4 - Prob. 4.26PFS
Knowledge Booster
Similar questions
- Use LRFD and design the tension members of the roof truss shown in Figure below. Use double-angle shapes throughout and assume 10-mm-thick gusset plates and welded connections. Assume a shear lag factor of U = 0.80. The trusses are spaced at 9 meters. Use A36 steel and design for te following loads. Metal deck : 190 Pa of roof surface Built-up roof : 575 Pa of roof surface Purlins : 145 Pa of roof surface (estimated) Roof Live Load : 960 Pa of horizontal projection Truss weight : 240 Pa of horizontal projection (estimated)arrow_forwardFor Problem 1: Use LRFD and design the tension members of the roof truss shown in Figure below. Use double-angle shapes throughout and assume 20-mm-thick gusset plates and welded connections. Assume a shear lag factor of U=0.8 . The trusses are spaced at 9 meters. Use A36 steel and design for the following loads. Metal deck : 380 Pa of roof surface Built-up roof : 1150 Pa of roof surface Purlins : 290 Pa of roof surface (estimated) Roof Live Load : 1920 Pa of horizontal projection Truss weight : 480 Pa of horizontal projection (estimated) For Problem 2: Use A36 steel and design sag rods for the truss of problem 1. Assume that, once attached, the metal deck will provide lateral support for the purlins; therefore, the sag rods need to be designed for the purlin weight only. a. Use LRFD. b. Use ASD.arrow_forwardA WT205 × 30 structural steel section (see Appendix B for cross-sectional properties) is used for a 6.4 m column. Assume pinned connections at each end of the column. Determine:(a) the slenderness ratio.(b) the Euler buckling load. Use E = 200 GPa for the steel.(c) the axial stress in the column when the Euler load is applied. Use Appendix B to look up the cross-sectional area, the area moment of inertia, and the radius of gyration for a WT205 x 30 structural steel section.Answer:A = mm2Ix = x 106 mm4rx = mmIy = x 106 mm4ry = mmarrow_forward
- A WT205 x 30 structural steel section (see Appendix B for cross-sectional properties) is used for a 8.8 m column. Assume pinned connections at each end of the column. Determine: (a) the slenderness ratio. (b) the Euler buckling load. Use E = 200 GPa for the steel. (c) the axial stress in the column when the Euler load is applied. Part 1 Use Appendix B to look up the cross-sectional area, the area moment of inertia, and the radius of gyration for a WT205 x 30 structural steel section. Answer: A = i mm2 Ix = i x 106 mm4 mm x 106 mm4 ry i mmarrow_forward4. The steel truss that is shown in the Figure below is loaded with three concentrated service live loads applied at B, D, and F. Assume lateral support is provided only at joints. Assume that the effective area is 85% of the computed net area. Use 20 mm ø bolts, Fy = 250 MPa, and Fu = 400 MPa. a. Investigate the adequacy of L51X51X7.9 at member IJ. b. Investigate the adequacy of L64X64X7.9 at member DI. P- KN 125 125 P= KN H 6@2m =12m %3Darrow_forwardQ2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m Darrow_forward
- Instructions:-Write down each step clearly in calculation suggestion what you are doing.( you need to tell why you selected particular value ofø (phi) and U). What and why you are calculating certain step Consider R= 433.5 PROBLEM A welded tension member is consisting of two channels placed 400mm back to back with flanges turned out. Select a channel for factored tensile of 4RKN using A36 steel and AISC specifications.The member is to be 15m long. PLASE USE THE EXAMPLE AS GUIDE OF ALL STEPS AND FORMULAS TO BE USEarrow_forwardA PL40 mm X 250 mm (smaller member) is connected to a gusset plate (bigger member) as shown. The diameter of the holes are 25 mm. The pitch and gage of the holes are 50 mm and 75 mm, respectively. The yield strength of the steel is 260 MPa while the ultimate tensile strength of the steel is 400 MPa. Determine the design (LRFD) tensile strength of the tension member in kN. Neglect block shear. H FO E. • D A Вarrow_forwardThe built-up section shown below is fastened together by passing two 10 mm diameter rivets through the top and bottom plates into the flanges of the beam. Each rivet will withstand 11.8 kN in shear. Determine the required spacing of the rivets along the length of the beam if it carries a shearing force of 199 kN. 12 mm x 180 mm plates (2) I IPE I 400x180x642.2 steel 10 mm rivetsarrow_forward
- ure B 2m2 m C -2 m D 4 m 500 N 700 N 2 of 2 Part B Identify the zero-force members in the truss shown in (Figure 2). Check all that apply. 000 CD DE CG CF FG BC BG DF AG EF AB Submit Provide Feedback Request Answerarrow_forwardProblem 4: Use A992 steel and select a W shape. The service dead load is 142 kips, and the service live load is 356 kips. ↑ a 10' wwww Do wwwwww y-axis 16' x-axisarrow_forwardDetermine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning