University Physics with Modern Physics (14th Edition)
14th Edition
ISBN: 9780321973610
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Chapter 42, Problem 42.25E
To determine
The probability that a state having energy of
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The Fermi energy of sodium is 3.23 eV.
(a) Find the average energy Eav of the electrons at absolute zero.
(b) What is the speed of an electron that has energy Eav ?
(c) At what Kelvin temperature T is kT equal to EF ? (This is called the Fermi temperature for the metal. It is approximately the temperature at which molecules in a classical ideal gas would have the same kinetic energy as the fastest-moving electron in the metal.)
For the free electrons in a solid, what is the value of the E/EF ratio knowing that the occupancy factor of the energy level E is equal to 0.05 at a temperature such that kT=EF/4? (NOTE: EF is the Fermi energy).
The Fermi energy of copper at 300 K is 7.05 eV. (a) What is the average energy of a conduction electron in copper at 300 K? (b) At what temperature would the average translational energy of a molecule in an ideal gas be equal to the energy calculated in part (a)?
Chapter 42 Solutions
University Physics with Modern Physics (14th Edition)
Ch. 42.1 - If electrons obeyed the exclusion principle but...Ch. 42.2 - Prob. 42.2TYUCh. 42.3 - Prob. 42.3TYUCh. 42.4 - One type of thermometer works by measuring the...Ch. 42.5 - Prob. 42.5TYUCh. 42.6 - Prob. 42.6TYUCh. 42.7 - Suppose a negative charge is placed on the gate of...Ch. 42 - Van der Waals bonds occur in many molecules, but...Ch. 42 - Prob. 42.2DQCh. 42 - The H2+ molecule consists of two hydrogen nuclei...
Ch. 42 - The moment of inertia for an axis through the...Ch. 42 - Prob. 42.5DQCh. 42 - Prob. 42.6DQCh. 42 - Prob. 42.7DQCh. 42 - The air you are breathing contains primarily...Ch. 42 - Prob. 42.9DQCh. 42 - Prob. 42.10DQCh. 42 - What factors determine whether a material is a...Ch. 42 - Prob. 42.12DQCh. 42 - Prob. 42.13DQCh. 42 - Prob. 42.14DQCh. 42 - Prob. 42.15DQCh. 42 - Prob. 42.16DQCh. 42 - Prob. 42.17DQCh. 42 - Prob. 42.18DQCh. 42 - Prob. 42.19DQCh. 42 - Prob. 42.20DQCh. 42 - Prob. 42.21DQCh. 42 - Prob. 42.22DQCh. 42 - Prob. 42.23DQCh. 42 - Prob. 42.24DQCh. 42 - If the energy of the H2 covalent bond is 4.48 eV,...Ch. 42 - An Ionic Bond, (a) Calculate the electric...Ch. 42 - Prob. 42.3ECh. 42 - Prob. 42.4ECh. 42 - Prob. 42.5ECh. 42 - Prob. 42.6ECh. 42 - Prob. 42.7ECh. 42 - Two atoms of cesium (Cs) can form a Cs2 molecule....Ch. 42 - Prob. 42.9ECh. 42 - Prob. 42.10ECh. 42 - A lithium atom has mass 1.17 1026 kg, and a...Ch. 42 - Prob. 42.12ECh. 42 - When a hypothetical diatomic molecule having atoms...Ch. 42 - The vibrational and rotational energies of the CO...Ch. 42 - Prob. 42.15ECh. 42 - Prob. 42.16ECh. 42 - Prob. 42.17ECh. 42 - Prob. 42.18ECh. 42 - Prob. 42.19ECh. 42 - Prob. 42.20ECh. 42 - Prob. 42.21ECh. 42 - Prob. 42.22ECh. 42 - Prob. 42.23ECh. 42 - Prob. 42.24ECh. 42 - Prob. 42.25ECh. 42 - Prob. 42.26ECh. 42 - Prob. 42.27ECh. 42 - Prob. 42.28ECh. 42 - Prob. 42.29ECh. 42 - Prob. 42.30ECh. 42 - Prob. 42.31ECh. 42 - Prob. 42.32ECh. 42 - Prob. 42.33PCh. 42 - Prob. 42.34PCh. 42 - Prob. 42.35PCh. 42 - The binding energy of a potassium chloride...Ch. 42 - (a) For the sodium chloride molecule (NaCl)...Ch. 42 - Prob. 42.38PCh. 42 - Prob. 42.39PCh. 42 - Prob. 42.40PCh. 42 - Prob. 42.41PCh. 42 - Prob. 42.42PCh. 42 - Prob. 42.43PCh. 42 - Prob. 42.44PCh. 42 - Prob. 42.45PCh. 42 - Prob. 42.46PCh. 42 - Prob. 42.47PCh. 42 - Prob. 42.48PCh. 42 - Prob. 42.49PCh. 42 - Prob. 42.50PCh. 42 - Prob. 42.51PCh. 42 - Prob. 42.52PCh. 42 - Prob. 42.53CPCh. 42 - Prob. 42.54CPCh. 42 - Prob. 42.55CPCh. 42 - Prob. 42.56PPCh. 42 - Prob. 42.57PPCh. 42 - Prob. 42.58PP
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Similar questions
- The probability of an electron occupying a state 3kT above the Fermi energy in a particular semiconducting sample is 4.74 x 10-2. What is the probability of a hole occupying a state 3kT below the Fermi energy in the same sample?arrow_forwardIf the Fermi energy of a metal is E, = 4.6 eV, and the mean free time of an electron is 3*10^-14what is the average free path in the metal?arrow_forwardSince the Fermi energy level of zinc is EF = 9.47 eV, what is the number of electrons per unit energy per unit volume at this energy level? Since the resistivity of zinc is 5.90 x 10^-8 ohm.m, calculate the average time interval between collisions of electrons.arrow_forward
- Physics Consider a solid piece of Lithium, Li, which is a metal and has electron density n = 4.70 × 1022 cm−3 . Assuming a free-electron quantum model, i.e., the Sommerfeld model, determine the, Fermi energy, density of states, and number of available states up to an energy of 4 eV for a cubic piece of Li of side 1 mm.arrow_forwardThe Fermi energy of aluminum is 11.6 eV; its density and molar mass are 2.70 g/cm3 and 27.0 g/mol, respectively. From these data, determine the number of conduction electrons per atom.arrow_forwardAn atom’s nucleus is a collection of fermions— protons and neutrons. (a) In calculating the Fermi energy in a nucleus, the protons and neutrons must be considered separately. Why? (b) Find the Fermi energy of (i) the protons and (ii) the neutrons in a uranium nucleus, which has a radius of 7.4 x 10-15 m and contains 92 protons and 146 neutrons.arrow_forward
- Silver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the density of states (in states>J and states>eV) at the Fermi energy for a block of silver of volume 1.0 cm3?arrow_forwardSilver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the Fermi energy (in J and eV) of silver?arrow_forwardAt low temperatures, copper has a free-electron concentration n = 8.45 *1028 m-3. Using the free-electron model, find the Fermi energy for solid copper, and find the speed of an electron with a kinetic energy equal to the Fermi energy.arrow_forward
- Calculate the value of the Fermi energy for a specific metal when it contains 2.54x1028 free electrons per cubic meter (m, = 9.11x10-31 kg and h= 6.63x10-3ª J.s). (A) 1.15 eV (В) 3.1 еV (С) 13.6 eV (D) 0.50 eVarrow_forwardThe general expression for the Fermi energy of a metal at OK is 3.65X10-19x n2/3ev more 3.65X1019Xn?eV O 3.65X1019Xn2/3eV 3.65X1019Xn1/3eVarrow_forwardUsing the Fermi function, estimate the temperature at which there is a 1% probability that an electron in a solid will have an energy of 0.5 eV above the Fermi energy.arrow_forward
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