Explanation Given: y = f ( x ) = 5 x 2 + 6 x − 4 We know that the critical points are the points at which the derivatives of the function become zero or undefined. Here, the given function is y = f ( x ) = 5 x 2 + 6 x − 4 Differentiating the above function with respect to x, we get f ' ( x ) = d d x ( 5 x 2 + 6 x − 4 ) = ( 10 x + 6 ) To find out the critical points, we equate the above equation to zero. i.e. f ' ( x ) = 0 10 x + 6 = 0 x = − 3 5<

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Chapter 4.3, Problem 28E

To determine

To find all the critical points of the function y=5x2+6x−4 and the intervals on which the function is increasing or decreasing. Also determine the critical point is a local minimum or maximum.

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Chapter 4.3, Problem 27E

Chapter 4.3, Problem 29E

Chapter 4 Solutions

CALCULUS (CLOTH)

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To find all the critical points of the function y = 5 x 2 + 6 x − 4 and the intervals on which the function is increasing or decreasing. Also determine the critical point is a local minimum or maximum.

Solution Summary: The author explains that the critical points are the points at which the derivatives of the function become zero or undefined.

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To find all the critical points of the function y=5x2+6x−4 and the intervals on which the function is increasing or decreasing. Also determine the critical point is a local minimum or maximum.

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