Explanation Let x be the width of the corral and accordingly the measurement of the half circle, and let y be the stature of the rectangular area. At that point the edge of the corral can be communicated by the condition 2 y + x + π 2 x = 2 y + ( 1 + π 2 ) x = 600 m Since x and y must both be nonnegative, it takes after that x must be limited to the interim. The territory of the corral is the aggregate of the region of the rectangle and half circle. A ( x ) = 1 2 x ( 600 − ( 1 + π 2 ) x ) + π 8 x 2 = 300 x − 1 2 ( 1 + π 2 ) x 2 + π 8 x 2 A ( 300 1 + π 4 ) ≈ 25204

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.6, Problem 15E

To determine

To Find the dimensional that maximize the area of the corral.

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Chapter 4.6, Problem 14E

Chapter 4.6, Problem 16E

Chapter 4 Solutions

CALCULUS (CLOTH)

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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To Find the dimensional that maximize the area of the corral.

Solution Summary: The author explains that x is the width of the corral and accordingly the measurement of a half circle.

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To Find the dimensional that maximize the area of the corral.

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Chapter 4 Solutions