Modern Physics
3rd Edition
ISBN: 9781111794378
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Chapter 5, Problem 29P
To determine
The ratio of the probability of an electron arriving at an maximum interference and to the minimum interference.
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a) In a double-slit experiment, a stream of electrons with speed v = 10 m/s is aimed at two parallel
slits. On the screen one meter behind the slits an interference pattern is observed in the number of
electrons arriving at different points on the screen. The distance between the first and the second
intensity maxima is 1 cm. Find the distance between the slits.
b) What is the distance between the first and the second maxima in the interference pattern, if we
perform the double-slit experiment with footballs (mass 0,4 kg) moving at speed 10 m/s? Let's
assume the slits are 1 m apart, and the screen is 10 m behind the slits. Is it possible to observe
interference of footballs?
a) In a double-slit experiment, a stream of electrons with speed v = 10 m/s is aimed at two parallel
slits. On the screen one meter behind the slits an interference pattern is observed in the number of
electrons arriving at different points on the screen. The distance between the first and the second
intensity maxima is 1 cm. Find the distance between the slits.
A linear particle accelerator using beta particles collides electrons with
their anti-matter counterparts, positrons. The accelerated electron hits the
stationary positron with a velocity of 77 x 10° m/s, causing the two
particles to annihilate.
If two gamma photons are created as a result, calculate the energy of
each of these two photons, giving your answer in MeV (mega electron
volts), accurate to 1 decimal place. Take the mass of the electron to be
5.486 x 104 u, or 9.109 x 1031 kg.
Note: Assume that the kinetic energy is also converted into the gamma
rays, and is included in the two photons.
Chapter 5 Solutions
Modern Physics
Ch. 5.1 - A 0.20-kg ball is thrown upward. How much work is...Ch. 5.5 - Prob. 5ECh. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Prob. 4QCh. 5 - Prob. 5QCh. 5 - Prob. 7QCh. 5 - Prob. 8QCh. 5 - Prob. 9Q
Ch. 5 - Prob. 10QCh. 5 - Prob. 11QCh. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10PCh. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Show that the group velocity for a nonrelativistic...Ch. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37P
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- When low-energy electrons pass through an ionized gas, electrons of certain energies pass through the gas as if the gas atoms weren’t there and thus have transmission coefficients (tunneling probabilities) T equal to unity. The gas ions can be modeled approximately as a rectangular barrier. The value of T = 1 occurs when an integral or half-integral number of de Broglie wavelengths of the electron as it passes over the barrier equal the width L of the barrier. You are planning an experiment to measure this effect. To assist you in designing the necessary apparatus, you estimate the electron energies E that will result in T = 1. You assume a barrier height of 10 eV and a width of 1.8 x 10-10 m. Calculate the three lowest values of E for which T = 1arrow_forwardA horizontal beam of laser light of wavelength 585 nm passes through a narrow slit that has width 0.0620 mm. The intensity of the light is measured on a vertical screen that is 2.00 m from the slit. (a) What is the minimum uncertainty in the vertical component of the momentum of each photon in the beam after the photon has passed through the slit? (b) Use the result of part (a) to estimate the width of the central diffraction maximum that is observed on the screen.arrow_forwardThe width of the central bright fringe in a diffraction pattern on a screen is identical when either electrons or optical light pass through a single slit. The distance between the screen and the slit is the same in each case and is large compared to the slit width. If the wavelength of the optical light is 552 nm, how fast are the electrons moving?Give your answer in units of m/s, accurate to 2 decimal placesarrow_forward
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