Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 5.7, Problem 45SEP
To determine
Is the non-steady diffusion process more sensitive to temperature or time. Explain using appropriate equations.
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Give three examples of materials processes that rely on diffusion in solids and explain how diffusion plays a critical role for one of those processes.
Chapter 5 Solutions
Foundations of Materials Science and Engineering
Ch. 5.7 - Prob. 1KCPCh. 5.7 - Write an equation for the number of vacancies...Ch. 5.7 - Prob. 3KCPCh. 5.7 - Prob. 4KCPCh. 5.7 - Describe the substitutional and interstitial...Ch. 5.7 - Prob. 6KCPCh. 5.7 - What factors affect the diffusion rate in solid...Ch. 5.7 - Write the equation for Ficks second law of...Ch. 5.7 - Prob. 9KCPCh. 5.7 - Prob. 10KCP
Ch. 5.7 - (a) Calculate the equilibrium concentration of...Ch. 5.7 - Prob. 12AAPCh. 5.7 - Determine the diffusion flux of zinc atoms in a...Ch. 5.7 - The diffusion flux of copper solute atoms in...Ch. 5.7 - Prob. 15AAPCh. 5.7 - Prob. 16AAPCh. 5.7 - Prob. 17AAPCh. 5.7 - A gear made of 1020 steel (0.20 wt% C) is to be...Ch. 5.7 - Prob. 19AAPCh. 5.7 - The surface of a steel gear made of 1020 steel...Ch. 5.7 - Prob. 21AAPCh. 5.7 - If boron is diffused into a thick slice of silicon...Ch. 5.7 - Prob. 23AAPCh. 5.7 - Prob. 24AAPCh. 5.7 - Prob. 25AAPCh. 5.7 - Prob. 26AAPCh. 5.7 - Prob. 27AAPCh. 5.7 - Prob. 28AAPCh. 5.7 - Prob. 29AAPCh. 5.7 - Prob. 30AAPCh. 5.7 - The diffusivity of copper atoms in the aluminum...Ch. 5.7 - Prob. 32AAPCh. 5.7 - Prob. 33SEPCh. 5.7 - Prob. 34SEPCh. 5.7 - Prob. 37SEPCh. 5.7 - Prob. 38SEPCh. 5.7 - The activation energy of nickel atoms in FCC iron...Ch. 5.7 - Prob. 40SEPCh. 5.7 - The self-diffusion of iron atoms in BCC iron is...Ch. 5.7 - Would you expect the diffusion rate of copper...Ch. 5.7 - Would you expect the diffusion rate of copper...Ch. 5.7 - Prob. 44SEPCh. 5.7 - Prob. 45SEPCh. 5.7 - Prob. 46SEPCh. 5.7 - Prob. 47SEPCh. 5.7 - Prob. 48SEPCh. 5.7 - Prob. 49SEPCh. 5.7 - Prob. 50SEP
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- Answer in a brief and concise essay. 1. Why does diffusion in solids important?arrow_forwardPlease kindly help. I will give a like. Thank you! a. Describe the S-curve model of diffusion on how does ‘rate of adoption’ change over time? At which-point is the rate of diffusion the fastest? b. S-curve model of diffusion: (true/false) and reasoning - k = 0, the rate of diffusion is instantaneous? - fixed k ≥ 0, the carrying capacity is determined only by the ratio of a and b? - fixed k ≥ 0, the rate of diffusion is determined only by the ratio of a and b? c. The diffusion of hybrid corn in the 1940s, who or which region seems to have adopted the hybrids more quickly and why?arrow_forwardRank the magnitudes of the diffusion coefficients from greatest to least for the following systems: N in Fe at 700°C Cr in Fe at 700°C N in Fe at 900°C Cr in Fe at 900°C Now justify this ranking. (Note: Both Fe and Cr have the BCC crystal structure, and the atomic radii for Fe, Cr, and N are 0.124, 0.125, and 0.065 nm, respectively. You may also want to refer to Section 5.4.)arrow_forward
- DISCUSSION THEORY OF DISFFUSION AND THROUGLY EXPLAIN FIVE DIFFUSION QUANTITIES.ALSO EXPLAIN THE DIFFUSION AND HEAT TRANSFER. PLEASE GIVE 2-3 PAGE DETAILED ESSAY.arrow_forwardThe diffusion coefficient for carbon in BCC iron at 400C and 900C is given as 3.80x10-13 and 1.70x-10m2/s respectively. Determine the temperature (in degrees C) at which a specimen of BCC iron has to be carburized for 150 minutes to produce the same diffusion result as at 900C for one hour.arrow_forwardThe preexponential and activation energy for the diffusion of chromium in nickel are 1.1 x 10-4 m²/s and 272,000 J/mol, respectively. At what temperature (in "C) will the diffusion coefficient have a value of 1.1 x 10-14 m²/s? i °Carrow_forward
- The diffusion coefficient of nickel in an austenitic stainless steel is 10-22 m2/s at 500°C and 10^-15 m^2/s at 1000°C. Calculate the activation energy for the diffusion of nickel in this alloy over this temperature range.arrow_forwardProblem 1 A sheet of BCC iron 1 mm thick was exposed to a carburizing gas atmosphere on one side and a decarburizing atmosphere on the other side at 725°C. After having reached steady state, the iron was quickly cooled to room temperature. The carbon concentrations at the two surfaces of the sheet were determined to be 0.012 and 0.0075 wt%. Compute the diffusion coefficient if the diffusion flux is 1.4 x 108 kg/m2-s. Hint: Use Equation 4.9(Text Book) to convert the concentrations from weight percent to kilograms of carbon per cubic meter of iron.arrow_forwardThe diffusion coefficients for iron in nickel are given at two temperatures: T(K) D(m2/s) 1273 9.4 x 10-16 1473 2.4 x 10-14 (a) Determine the values of D0 and the activation energy Qd. (b) What is the magnitude of D at 1100ºC (1373 K)?arrow_forward
- Consider a diffusion couple setup between pure tungsten and a tungsten alloy containing 1 at% thorium. After several minutes of exposure at 2000 C, a transition zone of 0.01 cm thickness is established. What is the flux of thorium atoms at this time if diffusion is due to (a) volume diffusion, (b) grain boundary diffusion, and (c) surface diffusion? TABLE 5-2 I The effect of the type of diffusion for thorium in tungsten and for self-diffusion in silver* Diffusion Coefficient (D) Diffusion Type Thorium in Tungsten Silver in Silver Do cm?/s Q cal/mole Do cm2/s Q cal/mole 66,400 90,000 120,000 0.47 0.068 8,900 22,750 45,700 Surface Grain boundary 0.74 0.24 Volume 1.00 0.99arrow_forward(c) Consider an alloy that is undergoing carburizing process, initially has a uniform carbon concentration of 0.27 wt% and is to be treated at 950oC (1750oF). If the concentration of carbon at the surface is suddenly brought to and maintained at 1.32 wt%, how long will it take to achieve a carbon content of 0.85% at a position 0.7 mm below the surface? The diffusion coefficient for carbon in iron at this temperature is 1.6 x 10-11 m2/s; assume that the steel piece is semi-finite.arrow_forwardWhat are the differences between Equimolar counter diffusion (EMD) and Uni molecular diffusionarrow_forward
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Ficks First and Second Law for diffusion (mass transport); Author: Taylor Sparks;https://www.youtube.com/watch?v=c3KMpkmZWyo;License: Standard Youtube License