Physics Fundamentals
2nd Edition
ISBN: 9780971313453
Author: Vincent P. Coletta
Publisher: PHYSICS CURRICULUM+INSTRUCT.INC.
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Chapter 6, Problem 35P
To determine
To Find:The apparent value of gravitational acceleration at the given latitude.
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If the radius of Earth is given by R_ERE, then when you are a distance of 2R_E2RE from the center of the Earth your acceleration due to gravity will be?
I thinks its 2g but I'm not sure or truly understand how to find it.
Earth’s gravitational field strength at the surface is 9.80 N/kg. Determine the distance, as a multiple of Earth’sradius, rE, above Earth’s surface at which the magnitude of the acceleration due to gravity is 3.20 N/kg.
A rock is dropped from high above the surface of the Earth.
The initial speed is 0, and the initial height above the
surface is NxRg where Rg is the radius of the Earth. Calculate
the speed of the rock when it hits the upper atmosphere, say
at height 20 km above the surface.
DATA for the Earth:
radius Rg = 6.38 x 108 m; mass M = 5.98 x 1024 kg.
N = 9;
(in m/s)
OA: 7.258x103 OB: 1.052×104 OC: 1.526x104 OD: 2.213x104 OE: 3.208x104 OF: 4.652x104 OG: 6.746x104 OH: 9.781x104
Chapter 6 Solutions
Physics Fundamentals
Ch. 6 - Prob. 1QCh. 6 - Prob. 2QCh. 6 - Prob. 3QCh. 6 - Prob. 4QCh. 6 - Prob. 5QCh. 6 - Prob. 6QCh. 6 - Prob. 7QCh. 6 - Prob. 8QCh. 6 - Prob. 9QCh. 6 - Prob. 10Q
Ch. 6 - Prob. 11QCh. 6 - Prob. 12QCh. 6 - Prob. 13QCh. 6 - Prob. 14QCh. 6 - Prob. 15QCh. 6 - Prob. 1PCh. 6 - Prob. 2PCh. 6 - Prob. 3PCh. 6 - Prob. 4PCh. 6 - Prob. 5PCh. 6 - Prob. 6PCh. 6 - Prob. 7PCh. 6 - Prob. 8PCh. 6 - Prob. 9PCh. 6 - Prob. 10PCh. 6 - Prob. 11PCh. 6 - Prob. 12PCh. 6 - Prob. 13PCh. 6 - Prob. 14PCh. 6 - Prob. 15PCh. 6 - Prob. 16PCh. 6 - Prob. 17PCh. 6 - Prob. 18PCh. 6 - Prob. 19PCh. 6 - Prob. 20PCh. 6 - Prob. 21PCh. 6 - Prob. 22PCh. 6 - Prob. 23PCh. 6 - Prob. 24PCh. 6 - Prob. 25PCh. 6 - Prob. 26PCh. 6 - Prob. 27PCh. 6 - Prob. 28PCh. 6 - Prob. 29PCh. 6 - Prob. 30PCh. 6 - Prob. 31PCh. 6 - Prob. 32PCh. 6 - Prob. 33PCh. 6 - Prob. 34PCh. 6 - Prob. 35PCh. 6 - Prob. 36PCh. 6 - Prob. 37PCh. 6 - Prob. 38PCh. 6 - Prob. 39PCh. 6 - Prob. 40PCh. 6 - Prob. 41PCh. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45P
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- Explain why centripetal acceleration changes the direction of velocity in circular motion but not its magnitude.arrow_forwardThe “mean” orbital radius listed for astronomical objects orbiting the Sun is typically not an integrated average but is calculated such that it gives the correct period when applied to the equation for circular orbits. Given that, what is the mean orbital radius in terms of aphelion and perihelion?arrow_forwardA space station, in the form of a wheel 120 m in diameter, rotates to provide an artificial gravity of 3.00 m/s2 for persons who walk around on the inner wall of the outer rim. Find the rate of the wheels rotation in revolutions per minute that will produce this effect.arrow_forward
- In Example 2.6, we considered a simple model for a rocket launched from the surface of the Earth. A better expression for the rockets position measured from the center of the Earth is given by y(t)=(R3/2+3g2Rt)2/3j where R is the radius of the Earth (6.38 106 m) and g is the constant acceleration of an object in free fall near the Earths surface (9.81 m/s2). a. Derive expressions for vy(t) and ay(t). b. Plot y(t), vy(t), and ay(t). (A spreadsheet program would be helpful.) c. When will the rocket be at y=4R? d. What are vy and ay when y=4R?arrow_forwardWhat is the orbital radius of an Earth satellite having a period of 1.00 h? (b) What is unreasonable about this result?arrow_forwardCalculate the effective gravitational field vector g at Earths surface at the poles and the equator. Take account of the difference in the equatorial (6378 km) and polar (6357 km) radius as well as the centrifugal force. How well does the result agree with the difference calculated with the result g = 9.780356[1 + 0.0052885 sin 2 0.0000059 sin2(2)]m/s2 where is the latitude?arrow_forward
- What is the gravitational acceleration close to the surface of a planet with a mass of 2ME and radius of 2RE where ME, and RE are the mass and radius of Earth, respectively? Answer as a multiple of g, the magnitude of the gravitational acceleration near Earths surface. (See Section 7.5.)arrow_forwardEstimate the gravitational force between two sumo wrestlers, with masses 220 kg and 240 kg, when they are embraced and their centers are 1.2 m apart.arrow_forward2/113 A space shuttle which moves in a circular orbit around the earth at a height h 150 mi above its surface must have a speed of 17,369 mi/hr. Calculate the gravitational accelerationg for this altitude. The mean radius of the earth is 3959 mi. (Check your an- swer by computing g from the gravitational law g = R go where go = 32.22 ft/sec2 from Table D/2 R+h in Appendix D.)arrow_forward
- A 20 kg satellite has a circular orbit with a period of 2.4 hand a radius of 8.0 * 10^6 m around a planet of unknown mass. Ifthe magnitude of the gravitational acceleration on the surface ofthe planet is 8.0 m/s2, what is the radius of the planet?arrow_forwardThe equatorial radius of the Earth is 6378 km and gravity at the equator is 9.780 m s-2. Compute the ratio m of the centrifugal acceleration at the equator to the gravitational acceleration at the equator. If the ratio m is written as 1/k, what is the value of k?arrow_forwardA woman whose mass is 70 kg on Earth's surface is in a spacecraft at a height of twice Earth's radius (that is, 3 Earth radii) above Earth's surface. What is her mass (not weight) there? BIU S S.arrow_forward
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