(a)
To determine: The mechanism for the racemisation of
Interpretation: The mechanism for the racemisation of
Concept introduction: The stereoisomers that possess the mirror images of each other which are not superimposable or not identical to each other are termed as enantiomers.
The process of producing the equal mixture of possible enantiomers if any compound undergoes a transformation is termed as racemization. And the resultant mixture is known as racemic mixture.
The characteristic of rotating the plane polarized light by any compound is termed as optical activity of that compound.
(b)
To determine: The reason corresponding to the fact that the reaction of optically active
Interpretation: The reason corresponding to the fact that the reaction of optically active
Concept introduction: The stereoisomers that possess the mirror images of each other which are not superimposable or not identical to each other are termed as enantiomers.
The process of producing the equal mixture of possible enantiomers if any compound undergoes a transformation is termed as racemization. And the resultant mixture is known as racemic mixture.
The characteristic of rotating the plane polarized light by any compound is termed as optical activity of that compound.
(c)
To determine: The mechanism for the racemization of optically active
Interpretation: The mechanism for the racemization of optically active
Concept introduction: The stereoisomers that possess the mirror images of each other which are not superimposable or not identical to each other are termed as enantiomers.
The process of producing the equal mixture of possible enantiomers if any compound undergoes a transformation is termed as racemization. And the resultant mixture is known as racemic mixture.
The characteristic of rotating the plane polarized light by any compound is termed as optical activity of that compound.
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Organic Chemistry (9th Edition)
- Alkyl diazonium salts are unstable even at low temperature. They decompose to form carbocations, which go on to form products of substitution, elimination, and (sometimes) rearrangement. Keeping this in mind, draw a stepwise mechanism that forms all of the following products. NANO2 он + HCI, H2O NH2 онarrow_forwardWhen (ft)-6-bromo-2,6-dimethylnonane is dissolved in CH3OH, nucleophilic substitution yields an optically inactive solution. When the isomeric halide (fl)-2-bromo-2,5- dimethylnonane is dissolved in CH3OH under the same conditions, nucleophilic substitution forms an optically active solution. Draw the products formed in each reaction, and explain why the difference in optical activity is observed.arrow_forwardPropose a mechanism for the reaction of benzyl acetate with methylamine. Label theattacking nucleophile and the leaving group, and draw the transition state in which theleaving group leaves.arrow_forward
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- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning