Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 7, Problem 26P
To determine
To Plot: The graph of
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Problem
A moving electron has a Kinetic Energy K1. After a net amount of work is done on it, the electron is moving one-quarter as fast in the
opposite direction. What is the work done W in terms of K?
Solution
To solve for the work done, first we must determine what is the final kinetic energy of the electron.
By concept, we know that
K1=(1/2)mv2,
K2=(1/2)mv2
But it was mentioned that:
V2=(
so, K2 in terms of v1 is
K2=(
)mv21
Substituting the expression for K1 results to
K2=(
K1
Since work done is
W=AK=K
-K
Evaluating results to
w=( |
K1
An object moves in the xy plane in above figure and experiences a friction force with constant magnitude 3.00N, always acting in the direction opposite the objects velocity. Calculate the work that you must do to slide the object at constant speed against the friction force as the object moves along (a) the purple path O to A followed by a return purple path to O, (b) the purple path O to C followed by a return blue path to O, and (c) the blue path O to C followed by a return blue path to O. (d) Each of your three answers should be nonzero. What is the significance of this observation?
A certain force has components F
in Newtons and distance in meters.
=
4x² + 1, F₂ = 2y, F₂ = 0, where the force is measured
What is the work done by the force if the particle moves on a straight line from x = 0, y = 0, z = 0 to
x = 2.0 m, y = 2.0 m, z = 0?
Specify your answer as as integer i.e. no decimal places. Do not include units.
Chapter 7 Solutions
Physics for Scientists and Engineers
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- “ E=K+Uconstant is a special case of the work energy theorem.” Discuss this statement.arrow_forwardShown below is a box of mass m1 that sits on a frictionless incline at an angle above the horizontal =30. This box is connected by a relatively massless string, over a frictionless pulley, and finally connected to a box at rest over the ledge, labeled m2 . If m 1 and m2 are a height h above the ground and m2m1: (a) What is the initial gravitational potential energy of the system? (b) What is the final kinetic energy of the system?arrow_forwardA block of mass 200 g is attached at the end of a massless spring of spring constant 50 N/m. The other end of the spring is attached to the ceiling and the mass is released at a height considered to be where the gravitational potential energy is zero. (a) What is the net potential energy of the block at the instant the block is at the lowest point? (b) What is the net potential energy of the block at the midpoint of its descent? (c) What is the speed of the block at the midpoint of its descent?arrow_forward
- (a) Can the kinetic energy of a system be negative? (b) Can the gravitational potential energy of a system be negative? Explain.arrow_forwardConsider a particle on which a force acts that depends on the position of the particle. This force is given by . Find the work done by this force when the particle moves from the origin to a point 5 meters to the right on the x-axis.arrow_forwardA particle of mass 0.50 kg moves along the x -axis with a potential energy whose dependence on x is shown below. (a) What is the force on the particle at x = 2.0, 5.0, 8.0, and 12 m? (b) If the total mechanical energy E of the particle is —6.0 J, what are the minimum and maximum positions of the particle? (c) What are these positions if E = 2.0 J? (d) If E = 16 J, what are the speeds of the particle at the positions listed in part (a)?arrow_forward
- Consider a particle moving in the region x > 0 under the influence of the potential where U0 = 1 J and α = 2 m. Plot the potential, find the equilibrium points, and determine whether they are maxima or minima.arrow_forwardFind the work done by the same force in Example 7.4, between the same points, A=(0,0) and B=(2m,2m) , over a circular arc of radius 2 m, centered at (0,2m) . Evaluate the path integral using Cartesian coordinates. (Hint: You will probably need to consult a table of integrals.)arrow_forwardRepeat the preceding problem, but this time, suppose that the work done by air resistance cannot be ignored. Let the work done by the air resistance when the skier goes from A to B along the given hilly path be —2000 J. The work done by air resistance is negative since the air resistance acts in the opposite direction to the displacement. Supposing the mass of the skier is 50 kg, what is the speed of the skier at point B ?arrow_forward
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Mechanical work done (GCSE Physics); Author: Dr de Bruin's Classroom;https://www.youtube.com/watch?v=OapgRhYDMvw;License: Standard YouTube License, CC-BY