Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 7, Problem 73P
To determine
The rest energy of person in mega electron-volts and joules;
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anwer according to the blanks:
A new type of force was discovered by physicists with the following expression:
where alpha & beta are constants, and x is the position. The expression above was obtained from the interaction of a massless Higgs Boson (a type of particle) and a black hole.
Quantum physicists then decides to design and build a machine that is able to move the Higgs Boson from x2 to x1. How much work should the machine do to achieve this feat? (For simplicity, consider that no energy is lost in the process)
Solution
To determine the work done we apply the following
W = Blank 1dx
Evaluating the above, we get
W = Blank 2| Blank 3 | + Blank 4eBlank 5 + Blank 6xBlank 7 for the limits from xi to xf
substituting x1 and x2 as the limits, the work done is expressed as
W = Blank 8| Blank 9/Blank 10 | + ( Blank 11x1 - Blank 12 ) + Blank 13( x15 - x25 )
I need the complete detailed steps for C and D
Our Sun shines bright with a luminosity of 3.828 x 1026 Watt. Her energy is responsible for manyprocesses and the habitable temperatures on the Earth that make our life possible.(a) Calculate the amount of energy arriving on the Earth in a single day.
=6 x 10^22(b) To how many liters of heating oil (energy density: 37.3 x 106J/liter) is this equivalent? =1.6 x 10^15(c) The Earth reflects 30% of this energy: Determine the temperature on Earth’s surface.(d) What other factors should be considered to get an even more precise temperature estimate?Note: The Earth’s radius is 6370 km; the Sun’s radius is 696 x 103 km; 1 AU is 1.495 x 108 km
QUESTION 2:
Apply the energy interaction model to the two-masses-over-a-pulley situation. Model this system as if the pulley is massless and frictionless, so you won't have to worry about energy systems associated with the pulley system.
Take the initial state to be you just release the masses (what is vi? what is delta-v?)
Take the final state to be when the masses have a distance d and have speed but before they hit anything or out of string. (since d denotes a distance, it is a positive number: delta-y = +/- d, as appropriate)
2. when you substitute algebraic expressions for changes in individual energy systems in the algebraic representations of your particular Energy-Interaction Models, you will find the symbols m, M, g, v, and d useful. Watch your "minus signs"!
Chapter 7 Solutions
Physics for Scientists and Engineers
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