(a)
Interpretation:
The molecular structure is to be drawn for the given name.
Concept introduction:
E/Z designations indicate the absolute stereochemistry of double bonds. An E designation indicates the higher priority groups on the double bond are on opposite sides of the bond. A Z designation indicates that they are on the same side of the double bond.
In cyclic compounds with less than eight atoms, a ring double bond can have only one configuration, with the ring continuing on the same side of the double bond.
The groups at each end of the double bond are assigned priorities on the basis of Cahn-Ingold-Prelog rules.
(b)
Interpretation:
The molecular structure is to be drawn for the given name.
Concept introduction:
E/Z designations indicate the absolute stereochemistry of double bonds. An E designation indicates the higher priority groups on the double bond are on opposite sides of the bond. A Z designation indicates that they are on the same side of the double bond.
The groups at each end of the double bond are assigned priorities on the basis of Cahn-Ingold-Prelog rules.
(c)
Interpretation:
The molecular structure is to be drawn for the given name.
Concept introduction:
E/Z designations indicate the absolute stereochemistry of double bonds. An E designation indicates the higher priority groups on the double bond are on opposite sides of the bond. A Z designation indicates that they are on the same side of the double bond.
The groups at each end of the double bond are assigned priorities on the basis of Cahn-Ingold-Prelog rules.
(d)
Interpretation:
The molecular structure is to be drawn for the given name.
Concept introduction:
E/Z designations indicate the absolute stereochemistry of double bonds. An E designation indicates the higher priority groups on the double bond are on opposite sides of the bond. A Z designation indicates that they are on the same side of the double bond.
The groups at each end of the double bond are assigned priorities on the basis of Cahn-Ingold-Prelog rules.
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Chapter C Solutions
Organic Chemistry: Principles and Mechanisms (Second Edition)
- Q1: Draw the structure of each of the following molecules: (a) (R)-1-chloro-1-fluorobutane (c) (2R,3S)-3-Bromo-2-chloro-1-pentanol (b) (S)-2-chloropentane; (d) (R)-2,2,3-trichlorobutane.arrow_forwardGiven each of the following names, draw the corresponding structure. (a) (Z)-2-methoxypent-2-ene; (b) (E)-3-methylpent-2-ene; (c) (Z)-1-chloro-2-methylpent-1-ene; (d) (E)-2-chloro-3-methoxybut-2-ene; (e) (Z)-1-bromo-1-chloropent-1-ene; (f) (Z)-3-methylpent-2-enearrow_forward1. Draw the structures of the following substituents and place them in descending order of priority. (a) Methyl, bromomethyl, trichloromethyl, ethyl; (b) 2-methyl-propyl (isobutyl), 1-methyl-ethyl (isopropyl),cyclohexyl; (c) butyl, 1-methyl-propyl (sec-butyl), 2-methyl-propyl (isobutyl), 1,1-dimethyl-ethyl (tert-butyl); (d) ethyl, 1-chloro-ethyl, 1-bromo-ethyl, 2-bromo-ethyl. 2. Check the absolute configuration of the items below: a) b) d) H "CH₂CH3 CH3 Br CH3 f F |||| H₂N- CH₂CH3 CH3 fr -COH H f) HC H- H Br HC. "ICH3 FCH₂ CH3 CH3 Br Harrow_forward
- Show how hex-1-yne might be converted to(a) 1,2-dichlorohex-1-ene. (b) 1-bromohex-1-ene.(c) 2-bromohex-1-ene. (d) 1,1,2,2-tetrabromohexane.(e) 2-bromohexane. (f) 2,2-dibromohexane.arrow_forwardWhat reagents are needed to convert 1-ethylcyclohexene into (a) 1-bromo-2ethylcyclohexane; (b) 1-bromo-1-ethylcyclohexane; (c) 1,2-dibromo-1-ethylcyclohexane?arrow_forward(b) Consider the reaction of 1-bromobutane with a large excess of ammonia (NH3). Draw the reactants, the transition state, andthe products. Note that the initial product is the salt of an amine (RNH3+ Br - ), which is deprotonated by the excess ammonia to give the amine.arrow_forward
- When piperidine undergoes the series of reactions shown here, 1,4-pentadiene is obtained as the product. When the four different methyl- substituted piperidines undergo the same series of reactions, each forms a different diene: 1,5-hexadiene; 1,4-pentadiene; 2-methyl-1,4-pentadiene; and 3-methyl-1,4-pentadiene. Which methyl-substituted piperidine forms which diene?arrow_forwardB) Rank the following species in order of increasing nucleophilicity. (A) CH3CH2S-, (B) CH3CH2O-, (C) (CH3)3CO-, (D) (CH3)3COH.arrow_forwardShow all steps and reagents needed to convert cyclohexane into each compound: (a) the two enantiomers of trans-1,2- dibromocyclohexane; and (b) 1,2-epoxycyclohexane.arrow_forward
- 2) Draw the molecule that corresponds to (3R,5R,6R)-5-cyclopropyl-6-ethyl-3-iodo-1-methylcyclohex-1-ene.arrow_forward(a) (1R,2R)-1,2-dibromocyclohexane, draw any diastereomers.arrow_forwardDraw the structures of the following molecules: (a) (S)-sec-butylcyclopentane b) p-benzyltoluene c) (Z)-5-phenyl-3-methyl-3-octene （Veey important！！Please also draw out Dash and Wedge line in order to indicate RR,SS,RS , Cis, Trans, Z, E）arrow_forward
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