Concept explainers
(a)
The electric field at point (0, 3) cm
Answer to Problem 58QAP
Net electric field is
Explanation of Solution
Given:
Two charges are placed on the x -axis:
Formula used:
Electric field at distance r from the charge Q.
Calculation:
Point P is at x =0, y = 0.03 m
The x -component of electric field is:
The y -component of electric field is:
Net electric field,
At the angle,
Conclusion:
Net electric field is
(b)
Force acting on the electron at point (0, 3) cm
Answer to Problem 58QAP
Net force acting on the electron is
Direction of force on the electron is toward the positive charges.
Explanation of Solution
Given:
Electric field,
Charge on electron,
Formula used:
Calculation:
Conclusion:
Net force acting on electron is
Want to see more full solutions like this?
Chapter 16 Solutions
COLLEGE PHYSICS
- (a) Find the electric field at the center of the triangular configuration of charges in Figure 18-54., given that qa=+ 2.50 nC, qb=-8.00 nC, and qc=+ 1.50 nC. (b) Is there any combination of charges, other than qa= qb=qc,that will produce a zero strength electric field at the center of the triangular configuration?arrow_forwardTwo solid spheres, both of radius 5 cm. carry identical total charges of 2 C. Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume, (i) How do the magnitudes of the electric fields they separately create at a radial distance of 6 cm compare? (a) EA EB= 0 (b) EA EB 0 (c) EA = EB 0 (d) 0EAEB (e) 0 = Ea EB (ii) How do the magnitudes of the electric fields they separately create at radius 4 cm compare? choose from the same possibilities as in part (i).arrow_forwardShow that the maximum magnitude Emax of the electric field along the axis of a uniformly charged ring occurs at x=a/2 (see Fig. 23.3) and has the value Q/(630a2). Figure 23.3 (Example 23.2) A uniformly charged ring of radius c. (a) The field at P on the x axis due to an element of charge dq. (b) The perpendicular component of the field at P due to segment 1 is canceled by the perpendicular component due to segment 2.arrow_forward
- (a) Using the symmetry of the arrangement, show that the electric field at the center of the square in figure 18.46 is zero if the charges on the four comers are exactly equal. (b) Show that this is also true for any combination of charges in which qa= qd and qa = qcarrow_forwardA thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108 C is placed on the plate. Find (a) the charge density on each face of the plate, (b) the electric field just above the plate, and (c) the electric field just below the plate. You may assume the charge density is uniform.arrow_forwardAn electron and a proton, each starting from rest, are accelerated by the same uniform electric field of 200 N/C. Determine the distance and time for each particle to acquire a kinetic energy of 3.21016 J.arrow_forward
- (a) Find the electric field at x = 5.00 cm in Figure 18.52 (a), given that q = 1.00 C. (b) at what position between 3.00 and 8.00 cm is the total electric field the same as that for ? 2q alone? (c) Can the electric field be zero anywhere between 0.00 and 8.00 cm? (d) At very large positive or negative values of x, the electric field approaches zero in both (a) and (b). In which does it most rapidly approach zero and why? (e) At what position to the light of 11.0 cm is the total electric field zero, other than at infinity? (Hint: A graphing calculator can yield considerable insight in this problem.)arrow_forwardConsider n equal positively charged particles each of magnitude Q/n placed symmetrically around a circle of radius a. (a) Calculate the magnitude of the electric field at a point a distance x from the center of the circle and on the line passing through the center and perpendicular to the plane of the circle. (b) Explain why this result is identical to the result of the calculation done in Example 23.8.arrow_forwardThree charges are situated at corners of a rectangle as in Figure P16.13. How much work must an external agent do to move the 8.00-C charge to infinity? Figure P16.13 Problems 13 and 14.arrow_forward
- ne electric field at 2 cm from the center of long copper rod of radius 1 cm has a magnitude 3 N/C and directed outward from the axis of the rod. (a) How much charge per unit length exists on the rod? (b) What would be the electric flux through a cube of side 5 cm situated such that the rod passes through opposite sides of the cube perpendicularly?arrow_forwardA charge of q = 2.00 109 G is spread evenly on a thin metal disk of radius 0.200 m. (a) Calculate the charge density on the disk. (b) Find the magnitude of the electric field just above the center of the disk, neglecting edge effects and assuming a uniform distribution of charge.arrow_forwardTwo solid spheres, both of radius 5 cm, carry identical total charges of 2 C. Sphere A is a good conductor. Sphere B is an insulator, and its charge is distributed uniformly throughout its volume. (i) How do the magnitudes of the electric fields they separately create at a radial distance of 6 cm compare? (a) EA EB = 0 (b) EA EB 0 (c) EA = EB 0 (d) 0 EA EB (e) 0 = EA EB (ii) How do the magnitudes of the electric fields they separately create at radius 4 cm compare? Choose from the same possibilities as in part (i).arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning