Concept explainers
(a)
The expression for electric field at point X.
Answer to Problem 80QAP
The expression for electric field at point X is,
Explanation of Solution
Given:
Charge,
Charge,
Charge,
Distance,
Formula used:
The electric field is given by,
Where,
Calculation:
The electric field at point X is given by,
(b)
The expression for electric field at point Y.
Answer to Problem 80QAP
The expression for electric field at point Y is,
Explanation of Solution
Given:
Charge,
Charge,
Charge,
Distance,
Formula used:
The electric field is given by,
Where,
The electric field at point Y is given by,
(c)
The expression for electric field at point Z.
Answer to Problem 80QAP
The expression for electric field at point Z is,
Explanation of Solution
Given:
Charge,
Charge,
Charge,
Distance,
Formula used:
The electric field is given by,
Where,
The electric field at point Z is given by,
(d)
The electric field at point X, Y and Z.
Answer to Problem 80QAP
The electric field at point X, Y and Z are,
Explanation of Solution
Given:
Charge,
Charge,
Charge,
Distance,
Formula used:
The electric field is given by,
Where,
Calculation:
The electric field at point X is given by,
The electric field at point Y is given by,
The electric field at point Z is given by,
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Chapter 16 Solutions
COLLEGE PHYSICS
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- A uniformly charged insulating rod of length 14.0 cm is bent into the shape of a semicircle as shown in Figure P 19.21. The rod has a total charge of 7.50 C. Find (a) the magnitude and (b) the direction of the electric field at O, the center of the semicircle.arrow_forwardConsider a thin, spherical shell of radius 14.0 cm with a total charge of 32.0 C distributed uniformly on its surface. Find the electric field (a) 10.0 cm and (b) 20.0 cm from the center of the charge distribution.arrow_forwardIs it possible for a conducting sphere of radius 0.10 m to hold a charge of 4.0 C in air? The minimum field required to break down air and turn it into a conductor is 3.0 106 N/C.arrow_forward
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- Consider the charge distribution shown in Active Figure 19.31. (i) What are the charges contributing to the total electric flux through surface S? (a) q1 only (b) q4 only (c) q2 and q3 (d) all four charges (e) none of the charges (ii) What are the charges contributing to the total electric field at a chosen point on the surface S? (a) q1 only (b) q4 only (c) q2 and q3 (d) all four charges (e) none of the charges Active Figure 19.31 The net electric flux through any closed surface depends only on the charge inside that surface. The net flux through surface S is ql/0, the net flux through surface S is (q2 + q3)/0, and the net flux through surface S is zero.arrow_forwardThree charged particles are located at the corners of an equilateral triangle as shown in Figure P19.9. Calculate the total electric force on the 7.00-C charge.arrow_forwardShow that the maximum magnitude Emax of the electric field along the axis of a uniformly charged ring occurs at x=a/2 (see Fig. 23.3) and has the value Q/(630a2). Figure 23.3 (Example 23.2) A uniformly charged ring of radius c. (a) The field at P on the x axis due to an element of charge dq. (b) The perpendicular component of the field at P due to segment 1 is canceled by the perpendicular component due to segment 2.arrow_forward
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