8000°V 3 j2 w mo 8:1 * I, 31₂ mn V Figure 9: For Q18,19: Consider the ideal transformer circuit shown in Figure 9. 18. The current I, on the primary side of the transformer is given by (a) 1.700242.5° A (b) 437.12-28.3° mA (c) 13.41239.6° A (d) 212.8242.9° mA (e) 231.92-33.7° mA 40.2 -40 19. The voltage Vacross the 352 resistor on the secondary side of the transformer is given by (a) 5.1072-137.1° V (b) 638.4242.9° mV (e) 798.02-127.2⁰ mV (d) 5.3262146.3° V (e) 40.86242.9° V

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.3P: Consider an ideal transformer with N1=3000andN2=1000 turns. Let winding 1 be connected to a source...
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IDEAL TRANSFORMER GIVEN( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).

8000°V
3 j22
wwmo
I,
(d) 212.8242.9° mA
(e) 231.92-33.7° mA
8:1
eeeee
seeeee
3.2
mn
V₂
I
Figure 9:
For Q18,19: Consider the ideal transformer circuit shown in Figure 9.
18. The current I, on the primary side of the transformer is given by
(a) 1.700242.5° A
(b) 437.12-28.3° mA
(c) 13.41239.6° A
4002
-j40
19. The voltage V across the 352 resistor on the secondary side of the transformer is given by
(a) 5.1072-137.1° V
(b) 638.4242.9° mV
(e) 798.02-127.2 mV
(d) 5.3262146.3° V
(e) 40.86242.9° V
Transcribed Image Text:8000°V 3 j22 wwmo I, (d) 212.8242.9° mA (e) 231.92-33.7° mA 8:1 eeeee seeeee 3.2 mn V₂ I Figure 9: For Q18,19: Consider the ideal transformer circuit shown in Figure 9. 18. The current I, on the primary side of the transformer is given by (a) 1.700242.5° A (b) 437.12-28.3° mA (c) 13.41239.6° A 4002 -j40 19. The voltage V across the 352 resistor on the secondary side of the transformer is given by (a) 5.1072-137.1° V (b) 638.4242.9° mV (e) 798.02-127.2 mV (d) 5.3262146.3° V (e) 40.86242.9° V
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