A bacterial cell divides in the presence 32p, which is a radioactive isotope of phosphorous. This atom becomes part of the phosphate which is in DNA. After the first division, the bacteria is switched into a growth medium in which the phosphorous is not radioactive and is kept in this media for the rest of the experiment. The bacterial cell divides until there are 8 cells. How many of these cells would be radioactive if DNA replication is conservative, not semi-conservative? a) O b) 1 c) 2 d) 4 e) 8

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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A bacterial cell divides in the presence 32P, which is a radioactive isotope of
phosphorous. This atom becomes part of the phosphate which is in DNA. After the
first division, the bacteria is switched into a growth medium in which the
phosphorous is not radioactive and is kept in this media for the rest of the
experiment. The bacterial cell divides until there are 8 cells. How many of these cells
would be radioactive if DNA replication is conservative, not semi-conservative?
a) O
b) 1
○ c) 2
d) 4
e) 8
Transcribed Image Text:Question 8 Listen A bacterial cell divides in the presence 32P, which is a radioactive isotope of phosphorous. This atom becomes part of the phosphate which is in DNA. After the first division, the bacteria is switched into a growth medium in which the phosphorous is not radioactive and is kept in this media for the rest of the experiment. The bacterial cell divides until there are 8 cells. How many of these cells would be radioactive if DNA replication is conservative, not semi-conservative? a) O b) 1 ○ c) 2 d) 4 e) 8
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