COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 16, Problem 70QAP
To determine
(a)
The expression for electric field due to the plane.
To determine
(b)
The electric field created by two equal but opposite charge parallel planes.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Positive charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positive x-axis at x=a+r, a distance r to the right of the end of Q.
Calculate the x-component of the electric field produced by the charge distribution Q at points on the positive x-axis where x>a.
Express your answer in terms of the variables Q, a, r, and and appropriate constants.
Calculate the magnitude of the force that the charge distribution Q exerts on q.
Express your answer in terms of the variables Q, q, a, r, and appropriate constants.
Calculate the direction of the force that the charge distribution Q exerts on q.
Positive charge Q is distributed uniformly along the x-axis from x=0 to x=a. A positive point charge q is located on the positive x-axis at x=a+r, a distance r to the right of the end of Q.
Calculate the x-component of the electric field produced by the charge distribution Q at points on the positive x-axis where x>a.
Express your answer in terms of the variables Q, a, r, and and appropriate constants.
Calculate the y-component of the electric field produced by the charge distribution Q at points on the positive x-axis where x>a.
Express your answer in terms of the variables Q, a, x, and appropriate constants.
Calculate the magnitude of the force that the charge distribution Q exerts on q.
Express your answer in terms of the variables Q, q, a, r, and appropriate constants.
Calculate the direction of the force that the charge distribution Q exerts on q.
A total charge of Q is uniformly distributed along a line, which extends along the x- axis from x=0 to x=L. What is the electric field due to this line of charge at a point P, which is on the x axis at x=a. Your answer should be a symbolic expression that only depends on the variables k, Q, a, and L. What does your expression reduce to when a≫L (far-field limit)?
Chapter 16 Solutions
COLLEGE PHYSICS
Ch. 16 - Prob. 1QAPCh. 16 - Prob. 2QAPCh. 16 - Prob. 3QAPCh. 16 - Prob. 4QAPCh. 16 - Prob. 5QAPCh. 16 - Prob. 6QAPCh. 16 - Prob. 7QAPCh. 16 - Prob. 8QAPCh. 16 - Prob. 9QAPCh. 16 - Prob. 10QAP
Ch. 16 - Prob. 11QAPCh. 16 - Prob. 12QAPCh. 16 - Prob. 13QAPCh. 16 - Prob. 14QAPCh. 16 - Prob. 15QAPCh. 16 - Prob. 16QAPCh. 16 - Prob. 17QAPCh. 16 - Prob. 18QAPCh. 16 - Prob. 19QAPCh. 16 - Prob. 20QAPCh. 16 - Prob. 21QAPCh. 16 - Prob. 22QAPCh. 16 - Prob. 23QAPCh. 16 - Prob. 24QAPCh. 16 - Prob. 25QAPCh. 16 - Prob. 26QAPCh. 16 - Prob. 27QAPCh. 16 - Prob. 28QAPCh. 16 - Prob. 29QAPCh. 16 - Prob. 30QAPCh. 16 - Prob. 31QAPCh. 16 - Prob. 32QAPCh. 16 - Prob. 33QAPCh. 16 - Prob. 34QAPCh. 16 - Prob. 35QAPCh. 16 - Prob. 36QAPCh. 16 - Prob. 37QAPCh. 16 - Prob. 38QAPCh. 16 - Prob. 39QAPCh. 16 - Prob. 40QAPCh. 16 - Prob. 41QAPCh. 16 - Prob. 42QAPCh. 16 - Prob. 43QAPCh. 16 - Prob. 44QAPCh. 16 - Prob. 45QAPCh. 16 - Prob. 46QAPCh. 16 - Prob. 47QAPCh. 16 - Prob. 48QAPCh. 16 - Prob. 49QAPCh. 16 - Prob. 50QAPCh. 16 - Prob. 51QAPCh. 16 - Prob. 52QAPCh. 16 - Prob. 53QAPCh. 16 - Prob. 54QAPCh. 16 - Prob. 55QAPCh. 16 - Prob. 56QAPCh. 16 - Prob. 57QAPCh. 16 - Prob. 58QAPCh. 16 - Prob. 59QAPCh. 16 - Prob. 60QAPCh. 16 - Prob. 61QAPCh. 16 - Prob. 62QAPCh. 16 - Prob. 63QAPCh. 16 - Prob. 64QAPCh. 16 - Prob. 65QAPCh. 16 - Prob. 66QAPCh. 16 - Prob. 67QAPCh. 16 - Prob. 68QAPCh. 16 - Prob. 69QAPCh. 16 - Prob. 70QAPCh. 16 - Prob. 71QAPCh. 16 - Prob. 72QAPCh. 16 - Prob. 73QAPCh. 16 - Prob. 74QAPCh. 16 - Prob. 75QAPCh. 16 - Prob. 76QAPCh. 16 - Prob. 77QAPCh. 16 - Prob. 78QAPCh. 16 - Prob. 79QAPCh. 16 - Prob. 80QAPCh. 16 - Prob. 81QAPCh. 16 - Prob. 82QAPCh. 16 - Prob. 83QAPCh. 16 - Prob. 84QAPCh. 16 - Prob. 85QAPCh. 16 - Prob. 86QAPCh. 16 - Prob. 87QAPCh. 16 - Prob. 88QAPCh. 16 - Prob. 89QAPCh. 16 - Prob. 90QAPCh. 16 - Prob. 91QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Consider two thin disks, of negligible thickness, of radius R oriented perpendicular to the x axis such that the x axis runs through the center of each disk. The disk centered at x=0 has positive charge density η, and the disk centered at x=a has negative charge density −η, where the charge density is charge per unit area. What is the magnitude E of the electric field at the point on the x axis with x coordinate a/2? Express your answer in terms of η, R, a, and the permittivity of free space ϵ0.arrow_forwardConsider a charge configuration comprising two point sources, one carrying a positive charge and the other a negative charge. The magnitude of the negative charge is three times as large as the positive charge. Construct a careful sketch of the electric field around the configuration.arrow_forwardA uniform charge distribution of total charge Q (Q>0) has endpoints located at (0.0m,12.0m) and (5.0m,0.0m). Assume the x-direction is horizontal and the y-direction is vertical. Our goal is to calculate the electric field at point P which is located at the origin.Draw a picture of the system and derive the equation of the line that represents the charge distribution. You are not allowed to rotate your coordinate system for this problem.(a) Determine the expression for dq. In this case the element of length of the charge distribution is written as ds=(dx^2+dy^2)1/2.You will need to write an equation for y in terms of x. (b) Determine the expression for r2, the magnitude of the vector that is directed from the element of charge dq to the location in which the field is to be determined. Eliminate the variable y by writing y in terms of x. (c) Determine the expression for r̂ the unit vector that is directed from the element of charge dq to the location in which the field is to be…arrow_forward
- Two homogeneous rods with a length of 5 cm each are positioned as in Fig. a. Determine the magnitude and direction of the electric field vector at point P on the coordinates (5.0) cm, if the unit charge density is λ = 2.10-9 C / m! b. If an electron is placed at point P, what is the electric force that is experienced by the electron?arrow_forwardNow suppose the cube and the charged ball setup is brought near an infinite charged plane. The lower face of the cube is parallel to the plane. If the charge density of the plane is σ=43μC/m2, what are the magnitudes of the electric fields at P and Q now? the magnitude of the electric field at points P ?arrow_forwardPositive electric charge Q is distributed uniformly throughout the volume of an insulating sphere with radius R. Find the magnitude of the electric field at a point P a distance r from the center of the sphere.arrow_forward
- Find the electric field at the origin of the x,y-plane for charge distributions (a) and (b), see the figures shown below. The field is produced (a) by a thin half-circle with a radius of 15 cm and the linear charge density K-10 pc/cm and (b) by a thin quarter-circle with the same radius and the linear charge density K = -10 pc/cm. K>0 (a) For the charge distribution (a): The x-component of Ea. Ea,x= The y-component of Ea, Ea,y= For the charge distribution (b): The x-component of Eb, Eb,x- The y-component of Eb, Eb,y = Units N/C Units N/C Units N/C Units N/C K<0 (b)arrow_forwardWhy is a spherical Gaussian surface appropriate when calculating the electric field of a point charge? The normal vector at any point on the sphere is parallel to the electric field of the point charge. The surface area of a sphere is directly proportional to the square of its radius. The field lines of the point charge are concentric with the spherical Gaussian surface. A point charge can be easily enclosed by a spherical surface.arrow_forwardCharge of a uniform density (11 pC/m?) is distributed over the entire xy plane. A charge of uniform density (6 pC/m2) is distributed over the parallel plane defined by z = 2.0 m. Determine the magnitude of the electric field for any point with z = 3.0 m.arrow_forward
- Given example derives the exact expression for the electric field at a point on the axis of a uniformly charged disk. Consider a disk of radius R = 3.00 cm having a uniformly distributed charge of +5.20 μC. (a) Using the result of the given example, compute the electric field at a point on the axis and 3.00 mm from the center. (b) What If? Explain how the answer to part (a) compares with the field computed from the near-field approximation E = σ/2ε0. (We derived this expression in Example 23.3.) (c) Using the result of Example 23.3, compute the electric field at a point on the axis and 30.0 cm from the center of the disk. (d) What If? Explain how the answer to part (c) compares with the electric field obtained by treating the disk as a +5.20-μC charged particle at a distance of 30.0 cm.arrow_forwardThe figure shows two parallel nonconducting rings with their central axes along a common line. Ring 1 has uniform charge q1 and radius R; ring 2 has uniform charge q, and the same radius R. The rings are separated by a distance 3.00R. The ratio of the electric field magnitudes of Ring 1 and Ring 2 at point P on the common line is 2.33. What is the ratio of charge magnitudes q1/92? Ring 1 Ring 2, 41 42 R ER- d Number i Unitsarrow_forwardAn infinite wire which is uniformly charged with charge density A=C/m is perpendicular to an infinite plane of uniform charge with charge density o = Consider a point which is a distance r =0.3 m away from the wire and a distance d away from the plane as shown in the figure. What is the magnitude of the electric field times the electric 0.3 C/m² constant, eo E, in units of C/m² at that point? O 4.7 O 94 O 2.4 O 7.1 O 12arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY