The structure of compound X consistent with the given information is to be proposed and the formation of X is to be stated. Concept introduction: In the proton NMR spectrum of ketones and aldehydes , we primarily see proton is attached to the carbonyl group (aldehyde or ketone protons) and the proton is attached to the adjacent carbon atom. The chemical shift value between δ 9 and δ 10 indicates the presence of aldehyde proton in proton NMR spectrum of an aldehydes. The chemical shift value between δ 2.1 and δ 2.4 indicates the presence of protons on the α carbon atom of a ketone or aldehyde, if there are no other electron withdrawing groups nearby in the proton NMR spectrum of ketones and aldehydes.

Question

Want to see the full answer?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.75SP

Interpretation Introduction

Interpretation:

The structure of compound X consistent with the given information is to be proposed and the formation of X is to be stated.

Concept introduction:

In the proton NMR spectrum of ketones and aldehydes, we primarily see proton is attached to the carbonyl group (aldehyde or ketone protons) and the proton is attached to the adjacent carbon atom. The chemical shift value between δ 9 and δ 10 indicates the presence of aldehyde proton in proton NMR spectrum of an aldehydes.

The chemical shift value between δ 2.1 and δ 2.4 indicates the presence of protons on the α carbon atom of a ketone or aldehyde, if there are no other electron withdrawing groups nearby in the proton NMR spectrum of ketones and aldehydes.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Given here are 1H-NMR and 13C-NMR spectral data for nine compounds. Each compound shows strong absorption between 1720 and 1700 cm-1 and strong, broad absorption over the region 2500–3300 cm-1. Propose a structural formula for each compound.

The ¹H NMR spectrum of a compound with the molecular formula C7H₁5Cl exhibits signals with relative integration 9:3:2:1. Propose a structure for this compound. 4-chloroheptane 3-chloro-2,2-dimethylpentane 3-chloro-2,4-dimethylpentane O2-chloro-2,3,3-trimethylbutane

The 1H- and 13C-NMR data of an ester of molecular formula C6H10O2 are given below. Also shown are the COSY and HETCOR NMR spectra of the ester. Draw the structure of the ester, explaining how you reach your conclusion. 1H-NMR: 7.20-6.90 (1H), 5.85 (1H), 4.16 (2H), 1.88 (3H), 1.31 (3H) ppm 13C-NMR: 166.7, 144.5, 123.0 , 60.2, 18.0, 14.3 ppm

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.75SP

Interpretation Introduction

Interpretation:

The structure of compound X consistent with the given information is to be proposed and the formation of X is to be stated.

Concept introduction:

In the proton NMR spectrum of ketones and aldehydes, we primarily see proton is attached to the carbonyl group (aldehyde or ketone protons) and the proton is attached to the adjacent carbon atom. The chemical shift value between δ 9 and δ 10 indicates the presence of aldehyde proton in proton NMR spectrum of an aldehydes.

The chemical shift value between δ 2.1 and δ 2.4 indicates the presence of protons on the α carbon atom of a ketone or aldehyde, if there are no other electron withdrawing groups nearby in the proton NMR spectrum of ketones and aldehydes.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.75SP

Interpretation Introduction

Interpretation:

The structure of compound X consistent with the given information is to be proposed and the formation of X is to be stated.

Concept introduction:

In the proton NMR spectrum of ketones and aldehydes, we primarily see proton is attached to the carbonyl group (aldehyde or ketone protons) and the proton is attached to the adjacent carbon atom. The chemical shift value between δ 9 and δ 10 indicates the presence of aldehyde proton in proton NMR spectrum of an aldehydes.

The chemical shift value between δ 2.1 and δ 2.4 indicates the presence of protons on the α carbon atom of a ketone or aldehyde, if there are no other electron withdrawing groups nearby in the proton NMR spectrum of ketones and aldehydes.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 18, Problem 18.75SP

Interpretation Introduction