Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Question
Chapter 3, Problem 3.12PFS
To determine
The net area of given members.
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A) The 3/4 in x 15 in plate has 4 rows (or horizontal lines) of bolts. Each row has 3 bolts.
The bolt diameter is 7/8 in. Determine the gross area (Ag) and the net area (An)
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Calculate the capacity of the shear connection below. A36 Plate: Fyp= 248MPa, Fup= 400MPa. A992 Beam; Fyb= 345MPa, Fub= 450MPa. Fexx= 480MPa. twb= 10.92mm
tp= 12, X= 45, nr= 3(no. of bolts)
What is the shear yielding capacity of shear plate in kN?
What is the shear rupture capacity of the shear plate in kN?
What is the block shear rupture capacity of shear plate in kN?
What is the weld capacity in kN?
The 3/4 in x 15 in plate has staggered holes as shown. The holes are for 7/8 in F bolts. Determine the smallest net area (An)
Chapter 3 Solutions
Structural Steel Design (6th Edition)
Ch. 3 - Prob. 3.1PFSCh. 3 - Prob. 3.2PFSCh. 3 - Prob. 3.3PFSCh. 3 - Prob. 3.4PFSCh. 3 - Prob. 3.5PFSCh. 3 - Prob. 3.6PFSCh. 3 - Prob. 3.7PFSCh. 3 - Prob. 3.8PFSCh. 3 - Prob. 3.9PFSCh. 3 - Prob. 3.10PFS
Ch. 3 - Prob. 3.11PFSCh. 3 - Prob. 3.12PFSCh. 3 - Prob. 3.13PFSCh. 3 - Prob. 3.14PFSCh. 3 - Prob. 3.15PFSCh. 3 - Prob. 3.16PFSCh. 3 - Prob. 3.17PFSCh. 3 - Prob. 3.18PFSCh. 3 - Prob. 3.19PFSCh. 3 - Prob. 3.20PFSCh. 3 - Prob. 3.21PFSCh. 3 - Prob. 3.22PFSCh. 3 - Prob. 3.23PFSCh. 3 - Prob. 3.24PFSCh. 3 - Prob. 3.25PFSCh. 3 - Prob. 3.26PFSCh. 3 - Prob. 3.27PFSCh. 3 - Prob. 3.28PFSCh. 3 - Prob. 3.29PFSCh. 3 - Prob. 3.30PFSCh. 3 - Prob. 3.31PFSCh. 3 - Prob. 3.32PFSCh. 3 - Prob. 3.33PFSCh. 3 - Prob. 3.34PFSCh. 3 - Determine the LRFD design strength and the ASD...Ch. 3 - Prob. 3.36PFSCh. 3 - Prob. 3.37PFS
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Similar questions
- Compute the net area of each given members. 1. PLx 8 in Ø bolts 2. in O bolts W12 x 40- -PL를 x 14 3. WT15 x 45arrow_forwardCalculate the capacity of the shear connection below. A36 Plate: Fyp= 248MPa, Fup= 400MPa. A992 Beam; Fyb= 345MPa, Fub= 450MPa. Fexx= 480MPa. twb= 10.92mm tp= 12, X= 45, nr= 3(no. of bolts) What is the bolt shear capacity in kN? What is the bearing capacity of the shear plate in kN? What us the bearing capacity of the beam in kN? What is the shear yielding capacity of shear plate in kN? What is the shear rupture capacity of the shear plate in kN? What is the block shear rupture capacity of shear plate in kN? What is the weld capacity in kN?arrow_forwardThe L6 x 4 x 1/2single angle shown has one line of 5/8 in bolts in each leg as shown. The bolts are spaced at 4 in in each line as shown (staggered at 2 in with respect to each other). Determine the net area (An)arrow_forward
- 8. Determine the effective net area of the W 16 x 40 shown. Assume the holes are for ¾ in diameter bolts. W16 X 40 in Ø bolts PA % 12 121 All 3 inarrow_forward7. Compute the tensile capacity for the A36 steel plate shown. Bolts are 7/8 in diameter. Neglect block shear. 4 3" A B e C D 3″ E @ F H Plate 15" xarrow_forwardCompute the net area. The 6 x 4 x 1/2 angle shown has one line of 1-in Ø bolts in each leg.The bolts are 4-in on center in each line and are staggered 2 in with respect to each other.arrow_forward
- Problem 3.. for 7/8 in bolts. . Compute the net area for the 7/8 x 12 plate shown below. The holes are 2 in O 3 in 3 in 4 in 3 in 2 in PL 7/8 x 12 12 in-arrow_forwardA double angle shape (L5 x 3 x 5/16) is shown below. The steel is A36 and the holes are for 1/2 in diameter bolts. Assume Ae = 0.75 An. Ag of one angle = 2.41 in². Fy = 36 ksi and Fu = 58 ksi. Determine the allowable strength. Section 0 2 25 x 3 x 5/6arrow_forwardDetermine the LRFD design strength and the ASD allowable strength of sections given. Neglect block shear. A36 steel and 3/4-in Ø bolts 1.4 in 2 in A BQ 3 in 0.650 in 0.400 in 0.400 in- + 9 in C15 х 33.9 3 in QE 3 in 1.4 in 2 in 0.650 in (a) (b) (c)arrow_forward
- The 200 mm x 150 mm x 12/5 mm angle has one line of 20 mm diameter bolts in each leg. The bolts are 75 mm on center in each line and are staggered 37.5mm with respect to each other. Fy 248 MPa, Fu-400 MPa. Standard nominal hole diameter of 20 mm bolt is 21mm. Area of the angular section= 4355 mm2. Reduction coefficient U-0.75 CIVIL ENGINEERING STEEL DESIGN Compute The following: a) The effective net area b.)The design strength for LRFD. c) The allowable strength for ASD. 200 75 (1125 67.5 150 1125 1125arrow_forwardProblem 1 Given the double splice connection shown made up of 6mm x 150mm steel plates with double row of 19mm diameter bolts. O = 552.93 MPa , t= 207MPA and op = 552.93 MPa a. Compute the tensile force of the steel plates ANS b. Compute the number of 19mm diameter bolts from shear ANS c. Compute the number of 19mm diameter bolts from bearing ANS d. Compute the number of 19mm diameter bolts for the connection ANS 150mm 6mmarrow_forward) Determine the smallest net area of the tension member shown. The holes are for 19 mm Ø bolts at the usual gage locations. The stagger is 37.5 mm. 50 9.5 50 50 43.75 P 2L125 x 87.5 x 6.25arrow_forward
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