Structural Steel Design (6th Edition)
Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
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Chapter 3, Problem 3.35PFS

Determine the LRFD design strength and the ASD allowable strength of the sections given, including block shear.

3-35. A WT 6 × 22.5 , A992 steel, attached through the flange with six 7 8 -in 0 bolts as shown in Fig. P3.35.

Chapter 3, Problem 3.35PFS, Determine the LRFD design strength and the ASD allowable strength of the sections given, including

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6) Calculate the shear lag reduction factor, u, for the spliced W-shape tension member shown. Hint: you can treat the wide flange section like two WT6x25s. | W12x50 H THE 3" 3" Typical Splice Plate TH HHHH -Splice Plate W12x50
3. Segui Text Problem 3.5-1 (Modified) Compute the nominal block shear strength of the tension member shown in Figure P3.5-1. ASTM A572 Grade 50 steel is used. The bolts are 1" inch 3.5-1 in diameter. L4 X 4 X 1/2" 2'4" -- 1½2" 3" 1/2" FIGURE P3.5-1
3.5-1 Block Shear The tension member is a PL38 x 5¹2 of A242 steel. It is connected to a 38-in. thick gusset plate, also of A242 steel, with 3/4-inch diameter bolts as shown in Figure P3.5-1. Determine the nominal block shear strength of the tension member. 1½" 2½" 1/2" 01 02 1½" 3" FIGURE P3.5-1 3" 1½" 115 3.5-1 the shear areas are Agv = (3/8) (7.5) 2-5.625 in.² and, since there are 2.5 hole diameters in each line of bolts, Av = (3/8)[7.5-2.5(3/4+1/8)]2= 3.984 in.² The tension area is Am = (3/8) [2.5-17/8)] = 0.6094 in.² Fy= 50 ksi, F, = 70 ksi R₁ = 0.6F₂Anv + Ubs FuAnt = 0.6(70) (3.984) + 1.0(70) (0.6094) = 210 kips Check upper limit: 0.6F Agv + Ubs FuAnt = 0.6(50) (5.625) + 1.0(70) (0.6094) = 211 kips > 210 kips

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