Structural Steel Design (6th Edition)
6th Edition
ISBN: 9780134589657
Author: Jack C. McCormac, Stephen F. Csernak
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 3, Problem 3.31PFS
To determine
The LRFD design strength and the ASD allowable strength of the given section,
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Calculate the capacity of the shear connection below. A36 Plate: Fyp= 248MPa, Fup= 400MPa. A992 Beam; Fyb= 345MPa, Fub= 450MPa. Fexx= 480MPa. twb= 10.92mm
tp= 12, X= 45, nr= 3(no. of bolts)
What is the shear yielding capacity of shear plate in kN?
What is the shear rupture capacity of the shear plate in kN?
What is the block shear rupture capacity of shear plate in kN?
What is the weld capacity in kN?
3. Segui Text Problem 3.5-1 (Modified)
Compute the nominal block shear strength of the tension member shown in
Figure P3.5-1. ASTM A572 Grade 50 steel is used. The bolts are 1" inch
3.5-1
in diameter.
L4 X 4 X 1/2"
2'4"
--
1½2"
3"
1/2"
FIGURE P3.5-1
Calculate the capacity of the shear connection below. A36 Plate: Fyp= 248MPa, Fup= 400MPa. A992 Beam; Fyb= 345MPa, Fub= 450MPa. Fexx= 480MPa. twb= 10.92mm
tp= 12, X= 45, nr= 3(no. of bolts)
What is the bolt shear capacity in kN?
What is the bearing capacity of the shear plate in kN?
What us the bearing capacity of the beam in kN?
What is the shear yielding capacity of shear plate in kN?
What is the shear rupture capacity of the shear plate in kN?
What is the block shear rupture capacity of shear plate in kN?
What is the weld capacity in kN?
Chapter 3 Solutions
Structural Steel Design (6th Edition)
Ch. 3 - Prob. 3.1PFSCh. 3 - Prob. 3.2PFSCh. 3 - Prob. 3.3PFSCh. 3 - Prob. 3.4PFSCh. 3 - Prob. 3.5PFSCh. 3 - Prob. 3.6PFSCh. 3 - Prob. 3.7PFSCh. 3 - Prob. 3.8PFSCh. 3 - Prob. 3.9PFSCh. 3 - Prob. 3.10PFS
Ch. 3 - Prob. 3.11PFSCh. 3 - Prob. 3.12PFSCh. 3 - Prob. 3.13PFSCh. 3 - Prob. 3.14PFSCh. 3 - Prob. 3.15PFSCh. 3 - Prob. 3.16PFSCh. 3 - Prob. 3.17PFSCh. 3 - Prob. 3.18PFSCh. 3 - Prob. 3.19PFSCh. 3 - Prob. 3.20PFSCh. 3 - Prob. 3.21PFSCh. 3 - Prob. 3.22PFSCh. 3 - Prob. 3.23PFSCh. 3 - Prob. 3.24PFSCh. 3 - Prob. 3.25PFSCh. 3 - Prob. 3.26PFSCh. 3 - Prob. 3.27PFSCh. 3 - Prob. 3.28PFSCh. 3 - Prob. 3.29PFSCh. 3 - Prob. 3.30PFSCh. 3 - Prob. 3.31PFSCh. 3 - Prob. 3.32PFSCh. 3 - Prob. 3.33PFSCh. 3 - Prob. 3.34PFSCh. 3 - Determine the LRFD design strength and the ASD...Ch. 3 - Prob. 3.36PFSCh. 3 - Prob. 3.37PFS
Knowledge Booster
Similar questions
- Determine the LRFD design tensile strength of the bolted connection shown. The angles are connected through the longer legs to a % x 11 in plate. Holes are made for % in bolts. Use steel F,-50 ksi F-65 ksi. L5x3x% (4, = 4.92in, x%30.947in, y=1.69in). Consider block shear in your calculations. %3D 3/4" plate 2L5 x 3 % x 5/8 3" Pr 3" 3 @ 3" 12" - 3" P,arrow_forwardProblem 1 Given the double splice connection shown made up of 6mm x 150mm steel plates with double row of 19mm diameter bolts. O = 552.93 MPa , t= 207MPA and op = 552.93 MPa a. Compute the tensile force of the steel plates ANS b. Compute the number of 19mm diameter bolts from shear ANS c. Compute the number of 19mm diameter bolts from bearing ANS d. Compute the number of 19mm diameter bolts for the connection ANS 150mm 6mmarrow_forward2. A double-channel shape, 2C10 x 20 steel, Fy = 50 ksi and Fu = 70 ksi, is used for a built-up tension member as shown in the figure. The holes are for 1/2-inch-diameter bolts. a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. 2½" 2½" Shape C12x30 X25 x20.7 PNA Web Thickness, t tw 2 in.² in. in. in. C15x50 14.7 15.0 15 0.716 11/16 3/8 x40 11.8 15.0 15 0.520 2 x33.9 10.0 15.0 15 0.400 C10x30 by d Area, Depth, A d 8.81 12.0 7.34 12.0 6.08 12.0 8.81 10.0 x25 7.35 10.0 x20 5.87 10.0 x15.3 4.48 10.0 12 0.510 2 12 0.387 12 0.282 5/16 10 0.673 11/16 10 0.526%2 10 0.379 38 10 0.240 4 4" Table 1-5 C-Shapes Dimensions Width, b; in. Flange 3.72 3% 1/4 3.52 32 3/16 3.40 3% 1/4 3.17 38 3/16 3.05 3 3/16 2.94 3 4" 3/8 3.03 3 1/4 2.89 278 3/16 2.74 234 V8 2.60 258 4" 4" Average Thickness, tr in. Distance Work- k Table 0.650 %8 0.650 8 1/16 0.650 % 17/16 0.501 21% 0.501 2 1½ 0.501 2 1½ 0.436 7/16 1/16 0.436 7/16 1/16 0.436 7/16 1/16 0.436 7/16 1/16 Gage in. in.…arrow_forward
- A) The 3/4 in x 15 in plate has 4 rows (or horizontal lines) of bolts. Each row has 3 bolts. The bolt diameter is 7/8 in. Determine the gross area (Ag) and the net area (An) 3/4 15 O O O O O O Q O O 3" 3 27 3 784 Bolts Pet *arrow_forwardProblem # 8.0 The tension member shown is a C12 x 20.7 of A572 Grade 50 steel. Will it safely support a service dead load of 60 kips and a service live load of 125 kips? Use Equation 3.1 for U. by O O 2½" 22" | 2½" 7/8-in.-diameter bolts. оооо оооо m 000 U=0.90 Single and double angles m W10x 19 = 0.394 (for parent shape) 0000 by Single and double angles … W8 x 24 -=0.820 > U=0.90 O O O 00 U=0.80 W shape U=0.70arrow_forward3.5-1 Block Shear The tension member is a PL¾8 X 5¹2 of A242 steel. It is connected to a 38-in. thick gusset plate, also of A242 steel, with ¾-inch diameter bolts as shown in Figure P3.5-1. Determine the nominal block shear strength of the tension member. 1½" ro 2¹2" O 1 1½" I 1½" 3" O O O o FIGURE P3.5-1 O- 14 3" 1½" 3.5-1 the shear areas are Agv = (3/8) (7.5) 2 5. 625 in. ² and, since there are 2.5 hole diameters in each line of bolts, Any (3/8) [7.5-2.5(3/4+1/8)] x 2 = 3.984 in.² The tension area is Ant = (3/8) [2.5-1(7/8)] = 0.6094 in. ²2 Fy= 50 ksi, Fu = 70 ksi Rn 0.6FuAny + Ubs FuAnt = = 0.6(70) (3.984) + 1.0(70) (0.6094) = 210 kips Check upper limit: 0.6FyAgv + UbsFuAnt = 0.6(50)(5.625) + 1.0(70)(0.6094) = 211 kips > 210 kipsarrow_forward
- Determine the LRFD design strength and the ASD allowable strength of sections given. Neglect block shear. A36 steel and 3/4-in Ø bolts 1.4 in 2 in A BQ 3 in 0.650 in 0.400 in 0.400 in- + 9 in C15 х 33.9 3 in QE 3 in 1.4 in 2 in 0.650 in (a) (b) (c)arrow_forward7. Compute the tensile capacity for the A36 steel plate shown. Bolts are 7/8 in diameter. Neglect block shear. 4 3" A B e C D 3″ E @ F H Plate 15" xarrow_forwardA W16 x 45 of A992 steel is connected to a plate at each flange as shown. Determine the nominal strength based on the net section using alternative value of shear lag factor. * -2¼" 8-in.-diameter bolts W16 x 45arrow_forward
- The 200 mm x 150 mm x 12/5 mm angle has one line of 20 mm diameter bolts in each leg. The bolts are 75 mm on center in each line and are staggered 37.5mm with respect to each other. Fy 248 MPa, Fu-400 MPa. Standard nominal hole diameter of 20 mm bolt is 21mm. Area of the angular section= 4355 mm2. Reduction coefficient U-0.75 CIVIL ENGINEERING STEEL DESIGN Compute The following: a) The effective net area b.)The design strength for LRFD. c) The allowable strength for ASD. 200 75 (1125 67.5 150 1125 1125arrow_forward(See Attached picture of truss) 2. Since the reaction force at point A is 8975 #, The reaction force at point H is 7625#, the stress force in member AB is 14262 # (C), and the stress force in member BC is 11083# (T); calculate the minimum steel bolt size for attachment at points A and H. Use a factor of safety of 1.5 and a fitting factor of 1.15arrow_forward3-25. A36 steel and 3/4-in Ø bolts (Ans. LRFD 170.42 k, ASD 113.39 k) - L7 x 4 x} 1 in 3 in 2 in 3 in + 2 in FIGURE P3-25arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Structural Analysis (10th Edition)Civil EngineeringISBN:9780134610672Author:Russell C. HibbelerPublisher:PEARSONPrinciples of Foundation Engineering (MindTap Cou...Civil EngineeringISBN:9781337705028Author:Braja M. Das, Nagaratnam SivakuganPublisher:Cengage Learning
- Fundamentals of Structural AnalysisCivil EngineeringISBN:9780073398006Author:Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel LanningPublisher:McGraw-Hill EducationTraffic and Highway EngineeringCivil EngineeringISBN:9781305156241Author:Garber, Nicholas J.Publisher:Cengage Learning
Structural Analysis (10th Edition)
Civil Engineering
ISBN:9780134610672
Author:Russell C. Hibbeler
Publisher:PEARSON
Principles of Foundation Engineering (MindTap Cou...
Civil Engineering
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Cengage Learning
Fundamentals of Structural Analysis
Civil Engineering
ISBN:9780073398006
Author:Kenneth M. Leet Emeritus, Chia-Ming Uang, Joel Lanning
Publisher:McGraw-Hill Education
Traffic and Highway Engineering
Civil Engineering
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Cengage Learning