Physics Fundamentals
2nd Edition
ISBN: 9780971313453
Author: Vincent P. Coletta
Publisher: PHYSICS CURRICULUM+INSTRUCT.INC.
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Chapter 5, Problem 10Q
To determine
The ratio of maximum deceleration to the maximum acceleration of a car.
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A car starts rolling down a 1-in-4 hill (1-in-4 means that for each 4 m traveled along the sloping road, the elevation change is 1 m). How fast is it going when it reaches the bottom after traveling 55 m? (a) Ignore friction. (b) Assume an effective coefficient of friction equal to 0.10.
A man was originally walking at 1.5 m/s and then reaches a speed of 8.1 m/s in 2.4 s. He estimated that his coefficient of friction was 0.30. Was it above or below this value?
A driver in a car traveling at 23 m/s slams on the brakes and skids to a stop. If the coefficient of friction between the tires and the horizontal road is 0.70, how long will the skid marks be?
Chapter 5 Solutions
Physics Fundamentals
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- (a) If the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you can stop a car by locking the brakes when the car is traveling at 28.7 m/s (about 65 mi/h)? (b) On wet pavement the coefficient of kinetic friction may be only 0.25. How fast should you drive on wet pavement to be able to stop in the same distance as in part (a)? (Note: Locking the brakes is not the safest way to stop.)arrow_forwardA car of mass m = 1100 kg is traveling down a θ = 14 degree incline. When the car's speed is v0 = 13 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is μk = 0.45. Calculate the distance the car travels down the hill L in meters until it comes to a stop at the endarrow_forwardAt an accident scene on a level road, investigators measure a car's skid mark to be 78 m long. It was a rainy day and the coefficient of friction was estimated to be 0.30. use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)arrow_forward
- A frictionless plane is 10.0 m long and inclined at 30.0°. A sled starts at the bottom with an initial speed of 5.50 m/s up the incline. When the sled reaches the point at which it momentarily stops, a second sled is released from the top of the incline with an initial speed v. Both sleds reach the bottom of the incline at the same moment. (b) Determine, in m/s, the initial speed of the second sled.arrow_forwardMY NOTES ASK YOUR TEACHER A frictionless plane is 10.0 m long and inclined at 30.0°. A sled starts at the bottom with an Initial speed of 5.10 m/s up the incline. When the sled reaches the point at which it momentarily stops, a second sled is released from the top of the incline with an initial speed v,. Both sleds reach the bottom of the incline at the same moment. (a) Determine the distance that the first sled traveled up the Incline. (b) Determine the initlal speed of the second sled. m/sarrow_forwardIf the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you can stop a car by locking the brakes when the car is traveling at 28.7 m>s (about 65 mi>h)?arrow_forward
- A crate is pushed up a frictionless inclined plane with initial speed of 4 m/s. The angle of incline is 30 degrees. (a) What is its speed when it gets back to the bottom? (b) How far up the plane does the block go? (c) How long does it take to get there?arrow_forwardA body weighing 40 lb starts from rest and slides down a plane at an angle of 30° with the horizontal for which the coefficient of friction µ = 0.30. (1) How far will it move during the third second? (2) How long will it require for it to move 60ft?arrow_forwardA box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.18 and the push imparts an initial speed of 3.9 m/sm/s ? Express your answer to two significant figures and include the appropriate units.arrow_forward
- A Stevedore wants to push a 50 kg crate up a 40 degree ramp. He can push with a maximum 300 N. What is the largest cofficient of friction that he could successfully push against if he slides the crate up at a constant speed? (This question has been already answered, don't answer) What minimum coefficient of friction would be necessary to hold the crate in the other question on the same ramp without it sliding down at all, with no help from the Stevedore? (Answer this question)arrow_forwardA city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be so that even low-powered cars can get up the hills without slowing down. A particular small car, with a mass of 920 kg, can accelerate on a level road from rest to 21m/s(75Km/h) in 12.5 s. Using these data, calculate the maximum steepness of a hill.arrow_forwardA box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is 0.25 and the push imparts an initial speed of 3.4 m/sm/s ?arrow_forward
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