Organic Chemistry: Principles and Mechanisms (Second Edition)
Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 5, Problem 5.76P
Interpretation Introduction

(a)

Interpretation:

It is to be identified which two hydrogen atoms in 2, 3-dibromoprop-1-ene (C3H4Br2) can be replaced by Cl atoms to yield constitution isomers having molecular formula C3H3Br2Cl.

Concept introduction:

Constitutional isomers are the isomers having the same molecular formula but different connectivity. For the given structure, replacing the hydrogen atoms by halogen atoms attached to different carbon atoms would generate constitutional isomers.

Interpretation Introduction

(b)

Interpretation:

It is to be identified which two hydrogen atoms in 2, 3-dibromoprop-1-ene (C3H4Br2) can be replaced by Cl atoms to yield enantiomers having molecular formula C3H3Br2Cl.

Concept introduction:

Configurational isomers are the stereoisomers which have the same connectivity of atoms and which can’t be interconverted by rotations around single bonds. Enantiomers are the type of constitutional isomers, which are non-superimposable mirror images of each other. For the given structure, replacing hydrogen atoms on wedge and dash bond by halogen atoms attached to the same carbon atoms would generate enantiomers.

Interpretation Introduction

(c)

Interpretation:

It is to be identified which two hydrogen atoms in 2, 3-dibromoprop-1-ene (C3H4Br2) can be replaced by Cl atoms to yield diastereomers of C3H3Br2Cl.

Concept introduction:

Configurational isomers are the stereoisomers which have the same connectivity of atoms and which can’t be interconverted by rotations around single bonds. Diastereomers are the type of constitutional isomers which are not mirror images of each other. Cis-trans isomers are diastereomers of each other. Cis isomers are the ones in which two top-priority substituents are linked to the same side of the double bond. Trans isomers are the ones in which two top-priority substituents are attached to the opposite sides of the double bond. For any given structure, replacing hydrogen atoms attached to any one doubly bonded carbon atom would generate diastereomers.

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Students have asked these similar questions
Write structural formulas for compounds that meet the following descriptions:(a) An alkene, C6H12, that cannot have cis–trans isomersand whose longest chain is 5 carbons long(b) An alkene with a chemical formula of C10H12 that hascis–trans isomers and contains a benzene ring.
(5) For the formula of C5H12O, (a) show your calculation and determine the degrees of unsaturation present, and (b) draw four of the structural/constitutional isomers possible for the formula.
Cyclopropane (C3H6, a three-membered ring) is more reactive than most other cycloalkanes.(a) Draw a Lewis structure for cyclopropane.(b) Compare the bond angles of the carbon atoms in cyclopropane with those in an acyclic (noncyclic) alkane.(c) Suggest why cyclopropane is so reactive.

Chapter 5 Solutions

Organic Chemistry: Principles and Mechanisms (Second Edition)

Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27PCh. 5 - Prob. 5.28PCh. 5 - Prob. 5.29PCh. 5 - Prob. 5.30PCh. 5 - Prob. 5.31PCh. 5 - Prob. 5.32PCh. 5 - Prob. 5.33PCh. 5 - Prob. 5.34PCh. 5 - Prob. 5.35PCh. 5 - Prob. 5.36PCh. 5 - Prob. 5.37PCh. 5 - Prob. 5.38PCh. 5 - Prob. 5.39PCh. 5 - Prob. 5.40PCh. 5 - Prob. 5.41PCh. 5 - Prob. 5.42PCh. 5 - Prob. 5.43PCh. 5 - Prob. 5.44PCh. 5 - Prob. 5.45PCh. 5 - Prob. 5.46PCh. 5 - Prob. 5.47PCh. 5 - Prob. 5.48PCh. 5 - Prob. 5.49PCh. 5 - Prob. 5.50PCh. 5 - Prob. 5.51PCh. 5 - Prob. 5.52PCh. 5 - Prob. 5.53PCh. 5 - Prob. 5.54PCh. 5 - Prob. 5.55PCh. 5 - Prob. 5.56PCh. 5 - Prob. 5.57PCh. 5 - Prob. 5.58PCh. 5 - Prob. 5.59PCh. 5 - Prob. 5.60PCh. 5 - Prob. 5.61PCh. 5 - Prob. 5.62PCh. 5 - Prob. 5.63PCh. 5 - Prob. 5.64PCh. 5 - Prob. 5.65PCh. 5 - Prob. 5.66PCh. 5 - Prob. 5.67PCh. 5 - Prob. 5.68PCh. 5 - Prob. 5.69PCh. 5 - Prob. 5.70PCh. 5 - Prob. 5.71PCh. 5 - Prob. 5.72PCh. 5 - Prob. 5.73PCh. 5 - Prob. 5.74PCh. 5 - Prob. 5.75PCh. 5 - Prob. 5.76PCh. 5 - Prob. 5.77PCh. 5 - Prob. 5.78PCh. 5 - Prob. 5.79PCh. 5 - Prob. 5.1YTCh. 5 - Prob. 5.2YTCh. 5 - Prob. 5.3YTCh. 5 - Prob. 5.4YTCh. 5 - Prob. 5.5YTCh. 5 - Prob. 5.6YTCh. 5 - Prob. 5.7YTCh. 5 - Prob. 5.8YTCh. 5 - Prob. 5.9YTCh. 5 - Prob. 5.10YTCh. 5 - Prob. 5.11YTCh. 5 - Prob. 5.12YTCh. 5 - Prob. 5.13YTCh. 5 - Prob. 5.14YTCh. 5 - Prob. 5.15YTCh. 5 - Prob. 5.16YTCh. 5 - Prob. 5.17YT
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