COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 9, Problem 25QAP
To determine
The ratio
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The leg bone (femur) breaks under a compressive force of about 9.00 × 104 N for a
human and (1.02x10^1) × 104 N for a horse. The human femur has a compressive
strength of 160 MPa, whereas the horse femur has a compressive strength of 140
MPа.
What is the effective cross-sectional area of the femur in a human in units of m^2?
Give your answer with three significant figures.
Note: Your answer is assumed to be reduced to the highest power possible.
Your Answer:
х10
Answer
Human bones have a Young's modulus of 1.5 x 1010 Pa. The bone breaks if
stress exceeds 1.5 x 10° Pa. If, for example, a femur of length 25.31 cm
experiences this stress compressively, what will be the new length of the
bone?
Answer must be in cm and in two decimal places.
A tow truck is pulling a car out of a ditch by means of a steel cable that is 9.2 m long and has a radius of 0.50 cm. When the car just begins to move, the tension in the cable is 279.6 N. How much has the cable stretched from its initial length? Assume Ysteel is 2x1011 N/m2
Chapter 9 Solutions
COLLEGE PHYSICS
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- A uniform wire (Y = 2.0 1011 N/m2) is subjected to a longitudinal tensile stress of 4.0 107 N/m2. What is the fractional change in the length of the wire?arrow_forwardConsider a nanotube with a Youngs modulus of 2.130 1012 N/m2 that experiences a tensile stress of 5.3 1010 N/m2. Steel has a Youngs modulus of about 2.000 1011 Pa. How much stress would cause a piece of steel to experience the same strain as the nanotube?arrow_forwardA copper rod with length 1.4 m and cross-sectional area 2.0 cm2 is fastened to a steel rod of length L and cross-sectional area 1.0 cm2. The compound structure is pulled on each side by two forces of equal magnitude 6.00 104 N (Fig. P14.57). Find the length L of the steel rod if the elongations (L) of the two rods are equal. Use the values Ysteel = 2.0 1011 Pa and YCu = 1.1 1011 Pa. FIGURE P14.57arrow_forward
- The lintel of prestressed reinforced concrete in Figure P12.27 is 1.50 m long. The concrete encloses one steel reinforcing rod with cross-sectional area 1.50 cm2. The rod joins two strong end plates. The cross-sectional area of the concrete perpendicular to the rod is 50.0 cm2. Youngs modulus for the concrete is 30.0 109 N/m2. After the concrete cures and the original tension T1 in the rod is released, the concrete is to be under compressive stress 8.00 106 N/m2. (a) By what distance will the rod compress the concrete when the original tension in the rod is released? (b) What is the new tension T2 in the rod? (c) The rod will then be how much longer than its unstressed length? (d) When the concrete was poured, the rod should have been stretched by what extension distance from its unstressed length? (e) Find the required original tension T1 in the rod. Figure P12.27arrow_forwardA brass wire and a steel wire, both of the same length, are extended by 1.0 mm under the same force. Is the cross-sectional radius of the brass wire more, less, or equal to the cross-sectional radius of the steel wire? Explain. Youngs moduli for brass and steel are 1.0 1010 N/m2 and 2.0 1011 N/m2, respectively.arrow_forwardA horizontal, rigid bar of negligible weight is fixed against a vertical wall at one end and supported by a vertical string at the other end. The bar has a length of 50.0 cm and is used to support a hanging block of weight 400.0 N from a point 30.0 cm from the wall as shown in Figure P14.81. The string is made from a material with a tensile strength of 1.2 108 N/m2. Determine the largest diameter of the string for which it would still break. FIGURE P14.81arrow_forward
- Why is the following situation impossible? A worker in a factory pulls a cabinet across the floor using a rope as shown in Figure P12.36a. The rope make an angle = 37.0 with the floor and is tied h1 = 10.0 cm from the bottom of the cabinet. The uniform rectangular cabinet has height = 100 cm and width w = 60.0 cm, and it weighs 400 N. The cabinet slides with constant speed when a force F = 300 N is applied through the rope. The worker tires of walking backward. He fastens the rope to a point on the cabinet h2 = 65.0 cm off the floor and lays the rope over his shoulder so that he can walk forward and pull as shown in Figure P12.36b. In this way, the rope again makes an angle of = 37.0 with the horizontal and again has a tension of 300 N. Using this technique, the worker is able to slide the cabinet over a long distance on the floor without tiring. Figure P12.36 Problems 36 and 44.arrow_forwardAssume Youngs modulus for bone is 1.50 1010 N/m2. The bone breaks if stress greater than 1.50 108 N/m2 is imposed on it. (a) What is the maximum force that can be exerted on the femur bone in the leg if it has a minimum effective diameter of 2.50 cm? (b) If this much force is applied compressively, by how much does the 25.0-cm-long bone shorten?arrow_forwardIn Example 14.3, we found that one of the steel cables supporting an airplane at the Udvar-Hazy Center was under a tension of 9.30 103 N. Assume the cable has a diameter of 2.30 era and an initial length of 8.00 m before the plane is suspended on the cable. How much longer is the cable when the plane is suspended on it?arrow_forward
- A nanotube with a Youngs modulus of 1.000 1012 Pa is subjected to a stress of 3.14 1011 Pa by being pulled at its ends. Assuming the tube had an initial length of 8.12 106 m, what is the new length of the nanotube?arrow_forwardA tow truck is pulling a car out of a ditch by means of a steel cable (Y = 2.0 x 1011 N/m2) that is 9.70 m long and has a radius of 0.466 cm. When the car just begins to move, the tension in the cable is 840 N. How much has the cable stretched?arrow_forwardA high-carbon steel wire, circular in cross-section, has a diameter of 14 mm. What is the force (in newtons) needed to break it? The ultimate tensile stress of high-carbon steel is 1.0 x 109 Pa.arrow_forward
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