COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 12QAP
To determine
Converging lenses are used to correct hyperopia and diverging lenses are used to correct myopia, explain why?
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Students have asked these similar questions
• It has become common to replace the cataract-clouded lens of the
eye with an internal lens. This intraocular lens can be chosen so that
the person has perfect distant vision. Will the person be able to read
without glasses? If the person was nearsighted, is the power of the
intraocular lens greater or less than the removed lens?
Supposed your physics instructor wears a pair of glasses with diverging lenses with focal length
-60 cm. While looking at a distant tree, the image of the tree is only 58 cm from the glasses.
. Find the actual location of the tree.
•
•
Sketch a diagram showing the eye, the glasses, the image of the tree, and the tree itself.
Identify whether the image of the tree is real or virtual.
3. Bifocal lenses are prescribed for a patient, the components having focal length of
40cm & -300cm.
• What are the new and far points of the patients eye?
4. 45 year old man can see with his left eye between 25 → 300 cm and in his right
eye between 15cmo, a man has astigmatism at his left eye which requires a
lens of focal length + 0.5m at axis 120°. The patient requires magnification
glasses of focal length 0.25m. write the required prescription for this patient
Chapter 24 Solutions
COLLEGE PHYSICS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- • Part A Consider a typical convex passenger-side mirror with a focal length of -80 cm. A 1.7-m-tall cyclist on a bicycle is 25 m from the mirror. You are 1.4 m from the mirror, and suppose, for simplicity, that the mirror, you, and the cyclist all lie along a line. How far are you from the image of the cyclist? Express your answer with the appropriate units. µA 团? L = Value Units Submit Request Answer Part B What is the image height? Express your answer with the appropriate units. h' = Value Units Submit Request Answerarrow_forward• An object is a distance 2ƒ from a convex lens. (a) Use a ray diagram to find the approximate location of the image. (b) Is theimage upright or inverted? (c) Is the image real or virtual? Explain.arrow_forward• Analyze the different types of mirrors and solve problems involving mirror equation. Differentiate the two types of lenses and solve problems involving the lens equation. OBJECTIVE Identify the parts of a concave and convex lenses and mirrors. Determine the location, orientation, size and type of image produced by a concave and convex lenses and mirrors. Solve problems involving mirrors and lenses. WHAT'S IN Light is one of the necessities of life on Earth. • Light is essential in the process of photosynthesis by plants. Light is also how reception and transmission of information about the things around us become possible. WHAT'S NEW Activity 1. Pinpoint Me? Directions: Identify the words described by the statements below and write your answer on the space before each number. 1. The law which states that the angle of incidence is equal to the angle of reflection. 2. The term used to describe the scattered reflection of light. 3. The center of the sphere to which the mirror is a part.…arrow_forward
- • A concave mirror produces a virtual image that is three times as tallas the object. (a) If the object is 16 cm in front of the mirror, what is theimage distance? (b) What is the focal length of this mirror?arrow_forward•• A certain telescope uses a concave spherical mirror that has a radius equal to 8.0 m. Find the location and diameter of the image of the moon formed by this mirror. The moon has a diameter of 3.5 X 10°m and is 3.8 x 10* m from Earth. 31arrow_forwardBifocal lenses are prescribed for a patient, the components having focal length of 40cm & -300cm. • What far points of the patients eye?arrow_forward
- An object is located 28.0 cm from a certain lens. The lens forms a real image that is twice as high as the object. • Part A What is the focal length of this lens? > View Available Hint(s) O 84.0 cm O 9.33 cm O 10.7 cm O 5.36 cm O 18.7 cm Submit Previous Answers v Correct Part B Now replace the lens used in Part A with another lens. The new lens is a diverging lens whose focal points are at the same distance from the lens as the focal points of the first lens. If the object is 5.00 cm high, what is the height of the image formed by the new lens? The object is still located 28.0 cm from the lens. > View Available Hint(s) О 12.5 ст O 2.0 cm O 10.0 cm O 11.2 cm O 7.5 cm О 33 стarrow_forward•• An object is 15.0 cm in front of a converging lens that has a focal length equal to 15.0 cm. A diverging lens that has a focal length whose magnitude is equal to 15.0 cm is located 20.0 cm in back of the first. (a) Find the location of the final image and describe its properties (for example, real and inverted) and (b) draw a ray diagram to corroborate your answers to Part (a). SSM 55arrow_forward•• You view a nearby tree in a concave mirror. The inverted imageof the tree is 4.8 cm high and is located 7.0 cm in front of the mirror.If the tree is 28 m from the mirror, what is its height?arrow_forward
- • A convex mirror has a radius of curvature that has a magnitude equal to 24 cm. Use ray diagrams to locate the image, if it exists, for an object near the axis at distances of (a) 55 cm, (b) 24 cm, (c) 12 cm, (d) 8.0 cm, and (e) 1.0 cm from the mirror. For each case, state whether the image is real or virtual; upright or inverted; and enlarged, reduced, or the same size as the object. 26arrow_forward• A convex mirror on the passenger side of a car produces animage of a vehicle that is 18.3 m from the mirror. If the image islocated 55.4 cm behind the mirror, what is the radius of curvatureof the mirror?arrow_forwardMath is not required, however you can use it to help with yoursolution. • You are only required to draw the position of the FINAL IMAGE given the system of lenses bellow. Use the following information: Focal length of biconvex lens=25 cm and focal length of the biconcave length =-10 cm Object 1.00 m 35 cm Hint: Find or estimatehow far the image from the lens is from the biconcave lens. Use thatto graph the optical rays between both lenses to get the FINAL IMAGE.arrow_forward
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Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY