COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Question
Chapter 24, Problem 82QAP
To determine
(a)
The image distance and lateral magnification
To determine
(b)
To draw the ray diagram.
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Students have asked these similar questions
• An object is a distance 2ƒ from a convex lens. (a) Use a ray diagram to find the approximate location of the image. (b) Is theimage upright or inverted? (c) Is the image real or virtual? Explain.
• Analyze the different types of mirrors and solve problems involving
mirror equation.
Differentiate the two types of lenses and solve problems involving
the lens equation.
OBJECTIVE
Identify the parts of a concave and convex lenses and mirrors.
Determine the location, orientation, size and type of image
produced by a concave and convex lenses and mirrors.
Solve problems involving mirrors and lenses.
WHAT'S IN
Light is one of the necessities of life on Earth.
• Light is essential in the process of photosynthesis by plants.
Light is also how reception and transmission of information about the
things around us become possible.
WHAT'S NEW
Activity 1. Pinpoint Me?
Directions: Identify the words described by the statements below and write your
answer on the space before each number.
1. The law which states that the angle of incidence is equal to the angle of reflection.
2. The term used to describe the scattered reflection of light.
3. The center of the sphere to which the mirror is a part.…
• Part A
Consider a typical convex passenger-side mirror
with a focal length of -80 cm. A 1.7-m-tall cyclist on
a bicycle is 25 m from the mirror. You are 1.4 m
from the mirror, and suppose, for simplicity, that the
mirror, you, and the cyclist all lie along a line.
How far are you from the image of the cyclist?
Express your answer with the appropriate units.
µA
团?
L =
Value
Units
Submit
Request Answer
Part B
What is the image height?
Express your answer with the appropriate units.
h' =
Value
Units
Submit
Request Answer
Chapter 24 Solutions
COLLEGE PHYSICS
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- •• A concave mirror has a radius of curvature equal to 24 cm. Use ray diagrams to locate the image, if it exists, for an ob- ject near the axis at distances of (a) 55 cm, (b) 24 cm, (c) 12 cm, and (d) 8.0 cm from the mirror. For each case, state whether the image is real or virtual; upright or inverted; and enlarged, reduced, or the same size as the object. 24arrow_forward•• A certain telescope uses a concave spherical mirror that has a radius equal to 8.0 m. Find the location and diameter of the image of the moon formed by this mirror. The moon has a diameter of 3.5 X 10°m and is 3.8 x 10* m from Earth. 31arrow_forward•8 An object is placed against the center of a spherical mirror and then moved 70 cm from it along the central axis as the image distance i is measured. Figure 34-36 gives i versus object distance p out to P. = 40 cm. What is i for p = 70 cm? 400 -400arrow_forward
- 3. Bifocal lenses are prescribed for a patient, the components having focal length of 40cm & -300cm. • What are the new and far points of the patients eye? 4. 45 year old man can see with his left eye between 25 → 300 cm and in his right eye between 15cmo, a man has astigmatism at his left eye which requires a lens of focal length + 0.5m at axis 120°. The patient requires magnification glasses of focal length 0.25m. write the required prescription for this patientarrow_forwardSupposed your physics instructor wears a pair of glasses with diverging lenses with focal length -60 cm. While looking at a distant tree, the image of the tree is only 58 cm from the glasses. . Find the actual location of the tree. • • Sketch a diagram showing the eye, the glasses, the image of the tree, and the tree itself. Identify whether the image of the tree is real or virtual.arrow_forwardA 4.0-cm-tall object is 15 cm in front of a convex mirror that has a -25 cm focal length.arrow_forward
- • A mirrored-glass gazing globe in a garden is 31.9 cm in diameter.What is the focal length of the globe?arrow_forward•• An object is 15.0 cm in front of a converging lens that has a focal length equal to 15.0 cm. A diverging lens that has a focal length whose magnitude is equal to 15.0 cm is located 20.0 cm in back of the first. (a) Find the location of the final image and describe its properties (for example, real and inverted) and (b) draw a ray diagram to corroborate your answers to Part (a). SSM 55arrow_forwardA 1.5-cm-tall object is 18 cm in front of a convex mirror that has a -59 cm focal length. Part A Calculate the position of the image. Express your answer to two significant figures and include the appropriate units. > View Available Hint(s) ? s' = 14 cm Submit Previous Answers X Incorrect; Try Again; 3 attempts remaining Part B Calculate the height of the image. Express your answer to two significant figures and include the appropriate units. • View Available Hint(s) HA ? h' = Value Units Submitarrow_forward
- A diverging lens with /= -32.5 em is placed 14.0 en behind a converging lens with -20.5 cm. • Part A Where will an object at infinity be focused? Determine the image distance from the second lens. Folow the sign conventions Express your answer to two significant figures and include the appropriate units. Taymplates Symbol Ledo redo rest keyboard shortouts nelp Value Units Submit Request Answerarrow_forward• A convex mirror on the passenger side of a car produces animage of a vehicle that is 18.3 m from the mirror. If the image islocated 55.4 cm behind the mirror, what is the radius of curvatureof the mirror?arrow_forwardMath is not required, however you can use it to help with yoursolution. • You are only required to draw the position of the FINAL IMAGE given the system of lenses bellow. Use the following information: Focal length of biconvex lens=25 cm and focal length of the biconcave length =-10 cm Object 1.00 m 35 cm Hint: Find or estimatehow far the image from the lens is from the biconcave lens. Use thatto graph the optical rays between both lenses to get the FINAL IMAGE.arrow_forward
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