COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 24QAP
To determine
The correct statement about the compound microscope
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Students have asked these similar questions
• Analyze the different types of mirrors and solve problems involving
mirror equation.
Differentiate the two types of lenses and solve problems involving
the lens equation.
OBJECTIVE
Identify the parts of a concave and convex lenses and mirrors.
Determine the location, orientation, size and type of image
produced by a concave and convex lenses and mirrors.
Solve problems involving mirrors and lenses.
WHAT'S IN
Light is one of the necessities of life on Earth.
• Light is essential in the process of photosynthesis by plants.
Light is also how reception and transmission of information about the
things around us become possible.
WHAT'S NEW
Activity 1. Pinpoint Me?
Directions: Identify the words described by the statements below and write your
answer on the space before each number.
1. The law which states that the angle of incidence is equal to the angle of reflection.
2. The term used to describe the scattered reflection of light.
3. The center of the sphere to which the mirror is a part.…
Chapter 24 Solutions
COLLEGE PHYSICS
Ch. 24 - Prob. 1QAPCh. 24 - Prob. 2QAPCh. 24 - Prob. 3QAPCh. 24 - Prob. 4QAPCh. 24 - Prob. 5QAPCh. 24 - Prob. 6QAPCh. 24 - Prob. 7QAPCh. 24 - Prob. 8QAPCh. 24 - Prob. 9QAPCh. 24 - Prob. 10QAP
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- A jewelers lens of focal length 5.0 cm is used as a magnifier. With the lens held near the eye, determine (a) the angular magnification when the object is at the focal point of the lens and (b) the angular magnification when the image formed by the lens is at the near point of the eye (25 cm). (c) What is the object distance giving the maximum magnification?arrow_forwardA person with a nearsighted eye has near and far points of 16 cm and 25 cm, respectively. (a) Assuming a lens is placed 2.0 cm from the eye, what power must the lens have to correct this condition? (b) Suppose contact lenses placed directly on the cornea are used to correct the person's eyesight. What is the power of the lens required in this case, and what is the new near point? Hint: The contact lens and the eyeglass lens require slightly different powers because they are at different distances from the eye.arrow_forwardAndy decides to use an old pair of eyeglasses to make some optical instruments. He knows that the near point in his left eye is 50.0 cm and the near point in his right eve is 100 cm. (a) What is the maximum angular magnification he can produce in a telescope? (b) If he places the lenses 10.0 cm apart, what is the maximum overall magnification he can produce in a microscope? Hint: Go back to basics and use the thin lens equation to solve part (b).arrow_forward
- A person with a nearsighted eye has near and far points of 16 cm and 25 cm, respectively. (a) Assuming a lens is placed 2.0 cm from the eye, what power must the lens have to correct this condition? (b) Suppose contact lenses placed directly on the cornea are used to correct the person's eyesight. What is the power of the lens required in this case, and what is the new near point? Hint: The contact lens and the eyeglass lens require slightly different powers because they are at different distances from the eye.arrow_forwardA cataract-impaired lens in an eye may be surgically removed and replaced by a manufactured lens. The focal length required for the new lens is determined by the lens-lo-retina distance, which is measured by a sonar-like device, and by the requirement that the implant provide for correct distance vision. (a) If the distance from lens to retina is 22.4 mm, calculate the power of the implanted lens in diopters. (b) Since there is no accommodation and the implant allows for correct distance vision, a corrective lens for close work or reading must be used. Assume a reading distance of 33.0 cm, and calculate the power of the lens in the reading glasses.arrow_forwardConstruct Your Own Problem Consider a telescope of the type used by Galileo, having a convex objective and a concave eyepiece as illustrated in part (a) of Figure 2.40. Construct a problem in which you calculate the location and size of the image produced. Among the things to be considered are the focal lengths of the lenses and their relative placements as well as the size and location of the object. Verify that the angular magnification is greater than one. That is, the angle subtended at the eye by the image is greater than the angle subtended by the object.arrow_forward
- In many applications, it is necessary to expand or decrease the diameter of a beam of parallel rays of light, which can be accomplished by using a converging lens and a diverging lens in combination. Suppose you have a converging lens of focal length 21.0 cm and a diverging lens of focal length 12.0 cm. (a) How can you arrange these lenses to increase the diameter of a beam of parallel rays? (b) By what factor will the diameter increase?arrow_forwardIf the lens of a person’s eye is removed because of cataracts (as has been done since ancient times), why would you expect a spectacle lens of about 16 D to be prescribed?arrow_forwardSuppose an object has thickness dp so that it extends from object distance p to p + dp. (a) Prove that the thickness dq of its image is given by (q2/p2)dp. (b) The longitudinal magnification of the object is Mlong = dq/dp. How is the longitudinal magnification related to the lateral magnification M?arrow_forward
- Unreasonable Results Your friends show you an image 1hrough a microscope. They tell you that the microscope has an objective with a 0.500 cm focal length and an eyepiece with a 5.00 cm focal laugh. The resulting overall magnification is 250,000. Are 1hese viable values for a microscope?arrow_forward(a) What is the maximum angular magnification of an eyeglass lens having a focal length of 18.0 cm when used as a simple magnifier? (b) What is the magnification of this lens when the eye is relaxed?arrow_forward
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Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY