COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 24, Problem 63QAP
To determine
Prove that all the mirror images of convex lenses are virtual using mirror equation
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•8 An object is placed against the
center of a spherical mirror and
then moved 70 cm from it along the
central axis as the image distance i is
measured. Figure 34-36 gives i
versus object distance p out to P. =
40 cm. What is i for p = 70 cm?
400
-400
• A mirrored-glass gazing globe in a garden is 31.9 cm in diameter.What is the focal length of the globe?
•• A slab of glass that has an index of refraction of 1.50 is
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if the angle of incidence is (a) 60°, (b) 45°, and (c) 30°. SSM
31
Chapter 24 Solutions
COLLEGE PHYSICS
Ch. 24 - Prob. 1QAPCh. 24 - Prob. 2QAPCh. 24 - Prob. 3QAPCh. 24 - Prob. 4QAPCh. 24 - Prob. 5QAPCh. 24 - Prob. 6QAPCh. 24 - Prob. 7QAPCh. 24 - Prob. 8QAPCh. 24 - Prob. 9QAPCh. 24 - Prob. 10QAP
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- •• A certain telescope uses a concave spherical mirror that has a radius equal to 8.0 m. Find the location and diameter of the image of the moon formed by this mirror. The moon has a diameter of 3.5 X 10°m and is 3.8 x 10* m from Earth. 31arrow_forward•39 In Fig. 34-38, a beam of parallel light rays from a laser is in- cident on a solid transparent sphere of index of refraction n. (a) If a point image is produced at the back of the sphere, what is the index of refraction of the sphere? (b) What index of refraction, if any, will produce a point image at the center of the sphere?arrow_forward•42 Figure 34-40 gives the lateral magnification m of an object versus the object distance p from a lens as the object is moved along the cen- tral axis of the lens through a range of values for p out to p, = 20.0 cm. What is the magnification of the ob- ject when the object is 35 cm from the lens? E 0.5 p (cm) Figure 34-40 Problem 42.arrow_forward
- •Explain what happens to the light ray at ech boundary: a plastic rectblock a mirrorarrow_forward•• A concave mirror has a radius of curvature equal to 24 cm. Use ray diagrams to locate the image, if it exists, for an ob- ject near the axis at distances of (a) 55 cm, (b) 24 cm, (c) 12 cm, and (d) 8.0 cm from the mirror. For each case, state whether the image is real or virtual; upright or inverted; and enlarged, reduced, or the same size as the object. 24arrow_forward• A concave mirror produces a virtual image that is three times as tallas the object. (a) If the object is 16 cm in front of the mirror, what is theimage distance? (b) What is the focal length of this mirror?arrow_forward
- •48 An object is moved along the central axis of a thin lens while the lateral magnification m is measured. Figure 34-43 gives m ver- sus object distance p out to p, = 8.0 cm. What is the magnification of the object when the object is 14.0 cm from the lens? p (cm)arrow_forward• An object is a distance 2ƒ from a convex lens. (a) Use a ray diagram to find the approximate location of the image. (b) Is theimage upright or inverted? (c) Is the image real or virtual? Explain.arrow_forward•• An object is 15.0 cm in front of a converging lens that has a focal length equal to 15.0 cm. A diverging lens that has a focal length whose magnitude is equal to 15.0 cm is located 20.0 cm in back of the first. (a) Find the location of the final image and describe its properties (for example, real and inverted) and (b) draw a ray diagram to corroborate your answers to Part (a). SSM 55arrow_forward
- 400 •44 An object is placed against the center of a thin lens and then moved away from it along the central axis as the image distance i is measured. Figure 34-41 gives i versus object distance p out to p, = 60 cm. What is the image distance when p= 100 -400 p (cm) Figure 34-41 Problem 44. cm? (un)!arrow_forward•• You view a nearby tree in a concave mirror. The inverted imageof the tree is 4.8 cm high and is located 7.0 cm in front of the mirror.If the tree is 28 m from the mirror, what is its height?arrow_forward•4 In Fig. 35-32a, a beam of light in material 1 is incident on a boundary at an angle of 30°. The extent to which the light is ben due to refraction depends, in part, on the index of refraction n, o material 2. Figure 35-32b gives the angle of refraction Oz versus n for a range of possible n2 values, from n, = 1.30 to n, = 1.90. Wha is the speed of light in material 1? в, 40° 300! 30° в, 20° по (a) (b)arrow_forward
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