Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Question
Chapter 25, Problem 11P
To determine
The power delivered to the resistor.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A capacitor of capacitance C= 10 µF is connected to a
resistance R = 2 2 and a battery of emf E= 5 V of negligible
internal resistance. After 20 µs of completing the circuit, find
C
HH
R
WW
E
(a) power delivered by the battery
(b) power dissipated as heat
(c) rate of energy stored in the capacitor
(!) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
R
ww
The emf source, E
R, = 5.6 N. The capacitor has a capacitance C = 3.7 µF.
2.1 V, of the circuit shown in the figure has negligible internal resistance. The resistors have resistances R, = 2.6N and
3.
R1
A) Determine the time constant T, in units of microseconds for charging the capacitor.
Answer:
B) What is the charge Q on the capacitor in units of microcoulomb?
Answer.
Three resistors A, B, and C are connected parallel and take a total of 7.9 A. Resistor A takes 2.5 A and has a resistance of 48 ; also, the current through B is twice as much as that through C. Calculate (a) la and Ic, (b) the line voltage, (c) Rs and Re..
Chapter 25 Solutions
Physics for Scientists and Engineers
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?arrow_forwardPower P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?arrow_forwardA 4.60 mF capacitor that is initially uncharged is connected inseries with a 7.50 kΩ resistor and an emf source with E = 245 V andnegligible internal resistance. Just after the circuit is completed, whatare the current through the resistor?arrow_forward
- (A) (in A) V Hill power (B) (in ohm) I Assume these parameter values: V = 9 volt and P = 20 W. (A) What is the electric current? (B) What is the resistance? "flashlight" schematic OA: 1.778 OB: 2.222 OC: 2.778 OD: 3.472 OE: 4.340 OF: 5.425 OG: 6.782 OH: 8.477 OA: 0.436 OB: 0.632 OC: 0.916 OD: 1.328 OE: 1.926 OF: 2.793 OG: 4.050 OH: 5.873arrow_forward(a) In the figure what value must R have if the current in the circuit is to be 1.3 mA? Take ₁ = 2.7 V, 8₂-5.3 V, and r₁ r2 = 3.9 Q. (b) What is the rate at which thermal energy appears in R? www.i R (a) Number (b) Number ww MI -48₂ i N Units Units <arrow_forward(A) (B) Pmax R Figure 2: 2. In figure 2A the power consumed by the resistor R is (a) : P = 12R = (True, False) (R+ r)2 (b) A qualitative plot of the power consumed by the variable resistor R is given in figure 2B (True, False) (c) For a variable resistor R the maximum power delivered to the variable resistor R can be found as follows: dP = 0 - dR r - R (R+r)3 = 0 - R = r - Pmag = 4r (True, False) (d) The power delivered by the battery for part(c) is and power consumed by each resistor isarrow_forward
- In an automobile, the system voltage varies from about12 V when the car is off to about 13.8 V when the car is onand the charging system is in operation, a difference of15%. By what percentage does the power delivered to theheadlights vary as the voltage changes from 12 V to 13.8 V?Assume the headlight resistance remains constant.arrow_forward() THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE, R3 ww The emf source, E = 2.1 V, of the circuit shown in the figure has negligible internal resistance. The resistors have resistances R = 1.91 and R = 5.9N. The capacitor has a capacitance C = 5.8 uF. R1 B) What is the charge Q on the capacitor in units of microcoulomb? Answer:arrow_forwardFor the circuit shown in Fig. both volt meter and ammeter are idealized, the battery has no appreciable internal resistance, and the ammeter reads 5 A. (a) What does the voltmeter V read? (b) What is the total current I of the circuit? (b) What is the total voltage Vofthe battery? (c) What is the total resistance R of the circuit? 25.0 0 V ww A 15.00 45.00 15.0 0 10.0 N +1 35.0Q V = ?arrow_forward
- For the circuit shown in Fig. both volt meter and ammeter are idealized, the battery has no appreciable intemal resistance, and the ammeter reads 5 A. (a) What does the voltmeter V read? (b) What is the total current I of the circuit? (b) What is the total voltage Vof the battery? (c) What is the total resistance R of the circuit? 25.0 N A 15.0N V 45.00 15.0N 10.0 It 35.0 V = ? %3Darrow_forward(LEGIBLY PLS) In the given circuit, find (a) the current through the 8.0ohm resistor and (b) the total rate ofdissipation of electrical energy in the 8-ohm resistor and in the internal resistance of the batteries. (c) What is the rate of production of electrical energy and (d) the rate of consumption of electrical energy?arrow_forward(a) In the figure the battery has an emf of 10 V and an internal resistance of 4.3 0. What is the value of the resistance R for which the rate of energy dissipation is maximum? (b) Calculate this maximum rate. Real battery (a) Number (b) Number Units Unitsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
DC Series circuits explained - The basics working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=VV6tZ3Aqfuc;License: Standard YouTube License, CC-BY