Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 25, Problem 71P
(a)
To determine
To Show:The equivalent resistance between “a” and “b” is R.
(b)
To determine
The effect of adding a fifth resistor between “c” and “d” on the equivalent resistance between “a” and b”.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
How long will it take a charged 80-uF capacitor to lose 30% of its initial energy when it is
allowed to discharge through a 45-2 resistor?
Is it possible to connect a group of resistors of value R in such a waythat the equivalent resistance is less than R? If so, give a specificexample
Te-Learning Portal
Courses -
Reports
e-Services ▼
Academic Departments -
ETC -
CIMS
Salim
During an experiment to verify Ohm's law, the voltage supplied and the current through a circuit are measured.
[Voltage is measured in Volt (V) and current in Ampere (A)].
ww
R
on
Battery
The measured value of the current is I = 3.1 ± 0.2 A and that of the voltage is V = 14 0.5 V. The resistance of
the circuit (in N) can be calculated using the formula, R = V/I,
Calculate the,
a) Resistance (in 2) =
b) Fractional uncertainty in the resistance =
c) Absolute uncertainty (in 2) in the resistance=
Chapter 25 Solutions
Physics for Scientists and Engineers
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- 27-1. In Figure, the ideal batteries have emfs E,= 10.0 V and Ez = 0.500 E, , and the resistances are each 4.00 2. What is the current in (a) resistance 2 and (b) resistance 3? ww R +18, 8,arrow_forward-37 In Fig. 27-48, the resistances are R, = 2.00 N, R, = 5.00 N, and the battery is ideal. What value of R3 Ra R3 maximizes the dissipation rate in resistance 3? wwarrow_forwardMany important devices incorporate circuits in which capacitors are altermately charged ane discharged. These include heart pacemakers, flashing traffic lights, automobile turn signals Activity 11 atano In the circuit shown in the figure below, find o -A erti ni 0 VA oR (a) the current in resistor R;-) berlosen aesd episo 1otios1eit.omil (b) the resistance R; and (c) the unknown emf ɛ.uotio erli to upa emit sulsy is ww riobexelen 10 inslenoo emd erl 4,00 A fiuonio 0-A 1ol Instenco amit x 6.00 6.00 A ww 3.00 0 ot19s9 eli lsme ai eonslaleen ert oiup aeperlo R-C Circuits ema al1 abnopee ni ei 1 to linu erni vDup eierio 10tiosqeo er brns woll ot in and electronic flash units. Understanding what happens in such circuits is of great practica Importo ert nelle acdniuarrow_forward
- 14 O In Fig. 27-32a, both batteries have emf & = 1.20 V and the external resistance R is a variable resistor. Figure 27-32b gives the electric potentials V between the terminals of each battery as func- tions of R: Curve 1 corresponds to battery 1, and curve 2 corre- sponds to battery 2. The horizontal scale is set by R, = 0.20 2. What is the internal resistance of (a) battery 1 and (b) battery 2? 0.5 -0.3 R (2) (a) (6) (A)Aarrow_forward(b) Determine the voltage across resistor 2.5 Q , v (show full calculation) 60 Q 12 Q + v - 2.5 Q 80 Q 40 V 15 Q 20 2arrow_forward(6) Suppose two electrical resistors with resistance R₁> 0 and R₂ > 0 are wired in parallel in a circuit: R₁ ww R₂ 1 1 1 + Then the combined resistance R, measured in ohms (2), is given by R R₁ R₂ ƏR ƏR (a) Find and after solving for R (e.g., R= ...). ƏR₁ ƏR₂ (b) Describe how an increase in R₁ with R₂ held constant will change R. (Will R increase or decrease?) (c) Describe how a decrease in R₂ with R₁ held constant will hange R. (Will R increase or decrease?)arrow_forward
- () THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE, R3 ww The emf source, E = 2.1 V, of the circuit shown in the figure has negligible internal resistance. The resistors have resistances R = 1.91 and R = 5.9N. The capacitor has a capacitance C = 5.8 uF. R1 B) What is the charge Q on the capacitor in units of microcoulomb? Answer:arrow_forward(b) 1. A platinum resistance sensor has a resistance of 100 2 at 0 °C and a temperature coefficient of resistance (oc) of 4 x 10 "C. If the resistance of the sensor is 125 O, find the corresponding temperature of the sensor. ii. A variable dielectric capacitive displacement sensor consists of two square metal plates of side 5 cm, separated by a gap of 1 mm. A sheet of dielectric material 1 mm thick and of the same area as the plates can be slide between them as shown in Figure Q.4b. Given that the dielectric constant of air is 1 and that of the dielectric material is 4, calculate the capacitance of the sensor when the input displacement x-0.0 cm, 2.5 cm and 5,0 cm. Figure Q4barrow_forward(b) Suppose node fin Figure 2 is connected to ground, and the elements in the circuit have the values & = 12 V, & = 4 V, 1= 1=10, R =R, =50 and R; =4 0, find the potentials at points 9. b and c, the powerdelivered by e.m.f. source &and the power dissipated in resistors , and R1. R1 R2 Battery 1 Battery 2 R3 Figure 2arrow_forward
- (a) When measuring the voltage across a resistor and the current through it, the voltmeter and the ammeter should be connected in respectively, to the resistor. series and series series and parallel O parallel and series O parallel and parallel (b) The resistances of an ideal voltmeter and ammeter should be infinity and zero infinity and infinity zero and infinity zero and zero respectively. Hint: Voltage is the measure of difference of the potential between two different points. Current is the measure of the flow of electrons.arrow_forwardThis is a physics question kindly solve it The 16-gauge copper wire with radius 5.1 x 10-4 m and its area of cross section is 8.20 x 10-7 m2 The amount of electric current is 1.67 ampere passing through in it. Calculate(a) The magnitude of electric field in the wire(b) The electric potential difference between two points 50 x 103 m apart.(c) What is the resistance of 50 m length of copper wire? Whereas the resistivity of copper wire is 1.72 x10-8 Ωarrow_forward(9) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 3 m and cross-sectional area A = 4.5 mm² lies along the x-axis between x = 0 and x = L. The material obeys Ohm's law, and its (1-#) resistivity varies along the rod according to p = po where po = 5 x 10-4 SN · m. The end of the rod at x = 0 is at a potential Vo 10 V greater than the end at x = L. L² A) What is the total resistance, in units of 2, of the rod? Answer: B) What is the current, in units of miliamperes, in the rod? Answer: C) What is the electric potential, in units of Volt, in the rod at x = L/2? Answer: D) What is the electric-field magnitude E, in units of V/m, in the rod at x = L/2? Answer:arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
DC Series circuits explained - The basics working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=VV6tZ3Aqfuc;License: Standard YouTube License, CC-BY