Principles of Biology
2nd Edition
ISBN: 9781259875120
Author: Robert Brooker, Eric P. Widmaier Dr., Linda Graham Dr. Ph.D., Peter Stiling Dr. Ph.D.
Publisher: McGraw-Hill Education
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Chapter 9.4, Problem 1TYK
Summary Introduction
Introduction:
The
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rdentify the statement that best interprets the results of the chi-square analysis. Refer
to the chi-square distribution table to identify the statement that best interprets the
chi-square results.
a) It is not unusual that a heterozygous man produced 16 out of 25 offspring with
heterochromia
b) A total number of normal offspring is significantly lower than expected
c) It is unusual that a man with heterochromia had 16 out of 25 offspring with
heterochromia
d) There is a significant difference between the observed number of offspring with
heterochromia and the number of offspring that were expected to have
heterochromia
8. Suppose two parents, a father with the genotype AaBbCcDdee and a mother with the
genotype aaBbCCDdEe, want to have children. Assume each locus follows Mendelian
inheritance patterns for dominance. What proportion of offspring will have each of the
specified characteristics? Round your answers to two decimal places.
a. Same genotype as father%3D
b. Same genotype as…
Using the product rule, what is the total frequency of the profile, given the following genotype frequencies for each of the loci:
D3S1358 = 0.04453
vWA = 0.02725
D5S818 = 0.07534
0.008406
0.0000914
0.14712
10,491
0.914208
you know that 1.1OU=1um. you have an organism that measures at 12 O.U at 10x. How long is your organism? assume O.U were calibrated at 1000x.
Chapter 9 Solutions
Principles of Biology
Ch. 9.1 - Look ahead to Figure 17.10. How does bacterial...Ch. 9.1 - Prob. 1TYKCh. 9.2 - Prob. 1CCCh. 9.2 - Prob. 2CCCh. 9.2 - Prob. 3CCCh. 9.2 - A nucleotide composed of deoxyribose, phosphate,...Ch. 9.2 - Prob. 2TYKCh. 9.2 - Prob. 3TYKCh. 9.3 - Prob. 1TYKCh. 9.3 - To determine the structure of DNA, Watson and...
Ch. 9.4 - Prob. 1CCCh. 9.4 - Prob. 1TYKCh. 9.4 - Prob. 2TYKCh. 9.5 - Prob. 1CCCh. 9.5 - Prob. 1TYKCh. 9.5 - Prob. 2TYKCh. 9.5 - Prob. 3TYKCh. 9.6 - Prob. 1CCCh. 9.6 - A nucleosome is composed of 146 bp or 147 bp of...Ch. 9.6 - After they have replicated and become compacted in...Ch. 9.6 - Prob. 1BCCh. 9.6 - Which of the following is the correct order for...Ch. 9 - What is/are the main component(s) of chromosomes?...Ch. 9 - Prob. 2TYCh. 9 - Prob. 3TYCh. 9 - Prob. 4TYCh. 9 - Of the following statements, which is correct when...Ch. 9 - Prob. 6TYCh. 9 - Prob. 7TYCh. 9 - Prob. 8TYCh. 9 - Prob. 9TYCh. 9 - The conversion of euchromatin into heterochromatin...Ch. 9 - What are the four criteria that the genetic...Ch. 9 - What are the key features of DNA that allow it to...Ch. 9 - PRINCIPLES A principle of bioloy is that structure...Ch. 9 - Prob. 1CBQCh. 9 - Prob. 2CBQ
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- A conservation biologist studied four generations of a population of rare Ethiopian jackals. When the study began, there were 47 jackals in the population, and microsatellite analysis showed a heterozygosity of 0.55. In the second generation, an outbreak of distemper occurred in the population, and only 17 animals survived to adulthood. These jackals produced 20 surviving offspring, which in turn gave rise to 35 progeny in the fourth generation. a) What was the effective population size for the four generations of this study? b) Based on its effective population size (use the rounded off value you obtained in a), what is the heterozygosity of the jackal population in generation 4 (t=4)? c) What is the inbreeding coefficient in generation 4, assuming an inbreeding coefficient of F = O at the beginning of the study (t=1), no change in microsatellite allele frequencies in the gene pool, and random mating in all generations?arrow_forwardA geneticist selects for increased body weight in a population of fruit flies that she is raising in her laboratory. She measures body weight in her population and selects the five heaviest males and the five heaviest females and uses them as the parents for the next generation. From the progeny produced by these parents, she selects the five heaviest males and five heaviest females and mates them. She repeats this procedure each generation. The average body weight of flies in the original population was 1.1 mg. The flies respond to selection, and their body weight steadily increases. After 20 generations of selection, the average body weight is 2.3 mg. However, after about 20 generations, the response to selection in subsequent generations levels off, and the average body weight of the flies no longer increases. At this point, the geneticist takes a long vacation; while she is gone, the fruit flies in her population interbreed randomly. When she returns from vacation, she finds that…arrow_forwardA geneticist selects for increased body weight in a population of fruit flies that she is raising in her laboratory. She measures body weight in her population and selects the five heaviest males and the five heaviest females and uses them as the parents for the next generation. From the progeny produced by these parents, she selects the five heaviest males and five heaviest females and mates them. She repeats this procedure each generation. The average body weight of flies in the original population was 1.1 mg. The flies respond to selection, and their body weight steadily increases. After 20 generations of selection, the average body weight is 2.3 mg. However, after about 20 generations, the response to selection in subsequent generations levels off, and the average body weight of the flies no longer increases…Why is this?arrow_forward
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