Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Question
Chapter 5, Problem 5.38AP
Interpretation Introduction
Interpretation:
The propagation step of free-radical chain mechanism for the given reaction by using fishhook notation is to be stated.
Concept introduction:
The general steps followed by free-radical addition reaction are stated below:
- First step is initiation that involves formation of radical.
- Second step is propagation.
- Third step is the termination that involves the formation of stable bond
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The rate law for addition of Br2 to an alkene is first order in Br2 and first order in the alkene. Does this information suggest that the mechanism of addition of Br2 to an alkene proceeds in the same manner as for addition of HBr? Explain.
The rate law for addition of Br2 to an alkenes is first order in Br2 and first order in the alkene. Does this information suggest that the mechanism of addition of Br2 to an alkene proceeds in the same matter as for addition of HBr? Explain.
Consider the compound 2,4-dimethyl-3-isopropylpentane. How many unique radical structures can be derived from this hydrocarbon when it undergoes free radical substitution? Write the number of free radicals formed.
Chapter 5 Solutions
Organic Chemistry
Ch. 5 - Prob. 5.1PCh. 5 - Prob. 5.2PCh. 5 - Prob. 5.3PCh. 5 - Prob. 5.4PCh. 5 - Prob. 5.5PCh. 5 - Prob. 5.6PCh. 5 - Prob. 5.7PCh. 5 - Prob. 5.8PCh. 5 - Prob. 5.9PCh. 5 - Prob. 5.10P
Ch. 5 - Prob. 5.11PCh. 5 - Prob. 5.12PCh. 5 - Prob. 5.13PCh. 5 - Prob. 5.14PCh. 5 - Prob. 5.15PCh. 5 - Prob. 5.16PCh. 5 - Prob. 5.17PCh. 5 - Prob. 5.18PCh. 5 - Prob. 5.19PCh. 5 - Prob. 5.20PCh. 5 - Prob. 5.21PCh. 5 - Prob. 5.22PCh. 5 - Prob. 5.23PCh. 5 - Prob. 5.24PCh. 5 - Prob. 5.25PCh. 5 - Prob. 5.26PCh. 5 - Prob. 5.27APCh. 5 - Prob. 5.28APCh. 5 - Prob. 5.29APCh. 5 - Prob. 5.30APCh. 5 - Prob. 5.31APCh. 5 - Prob. 5.32APCh. 5 - Prob. 5.33APCh. 5 - Prob. 5.34APCh. 5 - Prob. 5.35APCh. 5 - Prob. 5.36APCh. 5 - Prob. 5.37APCh. 5 - Prob. 5.38APCh. 5 - Prob. 5.39APCh. 5 - Prob. 5.40APCh. 5 - Prob. 5.41APCh. 5 - Prob. 5.42APCh. 5 - Prob. 5.43APCh. 5 - Prob. 5.44APCh. 5 - Prob. 5.45APCh. 5 - Prob. 5.46APCh. 5 - Prob. 5.47APCh. 5 - Prob. 5.48APCh. 5 - Prob. 5.49APCh. 5 - Prob. 5.50APCh. 5 - Prob. 5.51APCh. 5 - Prob. 5.52APCh. 5 - Prob. 5.53APCh. 5 - Prob. 5.54AP
Knowledge Booster
Similar questions
- Ethane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below. CH3CH3 + Cl2 → CH3CH2Cl + HCl Describe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes placearrow_forwardEthane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below. CH3CH3 + Cl2 → CH3CH2Cl + HCl Describe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish.arrow_forwardEthane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below. CH3CH3 + Cl2 → CH3CH2Cl + HCl Describe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish. Would this reaction (question 34(c)) give a high yield of 1-chloroethanearrow_forward
- In a time-resolved picosecond spectroscopy experiment, Sheps, Crowther, Carrier, and Crim (Journal of Physical Chemistry A, Vol. 110, 2006; pp. 30873092) generated chlorine atoms in the presence of pentane. The pentane was dissolved in dichloromethane, CH2C12. The chlorine atoms are free radicals and are very reactive. After a nanosecond the chlorine atoms have reacted with pentane molecules, removing a hydrogen atom to form HCl and leaving behind a pentane radical with a single unpaired electron. The equation is Cl (dcm) + C5H12(dcm) HCl(dcm) + C5H11 (dcm) where (dcm) indicates that a substance is dissolved in dichloromethane. Measurements of the concentration of chlorine atoms were made as a function of time at three different concentrations of pentane in the dichloromethane. These results are shown in the table. (a) Determine the order of the reaction with respect to chlorine. (b) Determine whether the reaction rate depends on the concentration of pentane in dichloromethane. If so, determine the order of the reaction with respect to pentane. (c) Explain why the concentration of pentane in dichloromethane does not affect the data analysis that you performed in part (a). (d) Write the rate law for the reaction and calculate the rate of reaction for a concentration of chlorine atoms equal to 1.0 M and a pentane concentration of 0.23 M. (e) Sheps, Crowther, Carrier, and Crim found that the rate of formation of HCl matched the rate of disappearance of Cl. From this they concluded that there were no intermediates and side reactions were not important. Explain the basis for this conclusion.arrow_forwardWith the catalyst AlCl3 present, which reactant is needed to convert benzene to ethylbenzene?arrow_forwardEthane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below.CH3CH3+ Cl2→ CH3CH2Cl+ HClDescribe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish.arrow_forward
- Write the hydrohalogenation reaction of butene where the halogen is bromine.arrow_forwardThe major product formed when methylenecyclohexane is treated with NBS in dichloromethane is 1-(bromomethyl)cyclohexene. Account for the formation of this product.arrow_forwardBromine and dichloromethane react with what classes of hydrocarbons? Please explain the mechanisms involve.arrow_forward
- Describe a sequence of reactions by which cis-2-pentene could be prepared from acetylene.arrow_forwardCompounds X and Y have the formula C6H₁2. Both X and Y react with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2-methylpentane. The heat of hydrogenation of X is less than that of Y. X and Y react with HBr to form a mixture of the same bromoalkanes, and they both undergo hydroboration/oxidation to give a mixture of the same alcohols. What is the structure of Y? • In cases where there is more than one answer, just draw one. MAVI Sn [F ? ChemDoodlearrow_forwardCompounds X and Y have the formula C6H12. Both X and Y react with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2-methylpentane. The heat of hydrogenation of X is less than that of Y. X and Y react with HBr to form a mixture of the same bromoalkanes, and they both undergo hydroboration/oxidation to give a mixture of the same alcohols. What is the structure of Y? • In cases where there is more than one answer, just draw one. + ChemDoodlearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning