Organic Chemistry
Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 19, Problem 19.69AP
Interpretation Introduction

(a)

Interpretation:

The synthesis of isotopically labelled alcohol using H2O18 is to be stated.

Concept introduction:

Elements which have the same atomic number but different atomic mass are known as isotopes. Due to the difference in the mass numbers, their natural abundance also differs. The chemical properties of isotopes are similar.

Interpretation Introduction

(b)

Interpretation:

The synthesis of the isotopically labelled alcohol using LiAlD4 is to be stated.

Concept introduction:

Elements which have the same atomic number but different atomic mass are known as isotopes. Due to the difference in the mass numbers, their natural abundance also differs. The chemical properties of isotopes are similar.

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(a) Draw the three isomers of benzenedicarboxylic acid.(b) The isomers have melting points of 210 °C, 343 °C, and 427 °C. Nitration of the isomers at all possible positions was once used to determine their structures. The isomer that melts at 210 °C gives two mononitro isomers. The isomer that melts at 343 °C gives three mononitro isomers. The isomer that melts at 427 °C gives only one mononitro isomer. Show which isomer has which melting point.
Biphenyl has the following structure.(a) Is biphenyl a (fused) polynuclear aromatic hydrocarbon?(b) How many pi electrons are there in the two aromatic rings of biphenyl? How does this number compare with that for naphthalene?(c) The heat of hydrogenation for biphenyl is about 418 kJ>mol (100 kcal>mol). Calculate theresonance energy of biphenyl.(d) Compare the resonance energy of biphenyl with that of naphthalene and with that of two benzene rings. Explain thedifference in the resonance energies of naphthalene and biphenyl.
Refer to the list of compounds shown below when answering questions 4(a) to 4(j) (a) A 50:50 mixture of structure VI with what other compound would lead to a racemic mixture?(b) Identify one compound that is identical to structure IV.  (c) Identify one compound that is identical to structure V.  (d) Identify one compound that is expected to have identical physical properties as structure II.  (e) Other than structures III and VI, identify a stereoisomer with a different boiling point from that of structure II.  (f) Other than structures IV, identify one diastereomer of structure I.  (g) How many stereoisomers may be derived from structure V?  (h) Specify the absolute (R/S) configuration of the amino group in structure IV. (i) If the substituents in structures I, IV and V were identical (all OH or all NH2), which structure would result in a meso compound?  (j) If each hydroxy group for structures I, II and VI were replaced with another amino group, which compound would be made optically…

Chapter 19 Solutions

Organic Chemistry

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