Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 19, Problem 19.72AP
Interpretation Introduction
Interpretation:
A suitable structure for compound A having the molecular formular
Concept introduction:
Spectroscopy method is used to identify the structure of the molecule. It is based on the interactions between matter and
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The 1H-NMR spectrum of compound B,C7H14O , consists of the following signals: δ 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H).
Draw the structural formula of compound B.
A compound (C7H14O) has a strong peak in its IR spectrum at 1710 cm–1. Its 1H NMR spectrum consists of three singlets in the ratio 9:3:2 at δ 1.0, 2.1, and 2.3, respectively. Identify the compound.
An unknown compound C3H2NCl shows moderately strong IR absorptions around 1650 cm-1 and 2200 cm-1. Its NMR spectrum consists of two doublets (J = 14 Hz) at δ 5.9 and δ 7.1. Propose a structure consistent with this data?
Chapter 19 Solutions
Organic Chemistry
Ch. 19 - Prob. 19.1PCh. 19 - Prob. 19.2PCh. 19 - Prob. 19.3PCh. 19 - Prob. 19.4PCh. 19 - Prob. 19.5PCh. 19 - Prob. 19.6PCh. 19 - Prob. 19.7PCh. 19 - Prob. 19.8PCh. 19 - Prob. 19.9PCh. 19 - Prob. 19.10P
Ch. 19 - Prob. 19.11PCh. 19 - Prob. 19.12PCh. 19 - Prob. 19.13PCh. 19 - Prob. 19.14PCh. 19 - Prob. 19.15PCh. 19 - Prob. 19.16PCh. 19 - Prob. 19.17PCh. 19 - Prob. 19.18PCh. 19 - Prob. 19.19PCh. 19 - Prob. 19.20PCh. 19 - Prob. 19.21PCh. 19 - Prob. 19.22PCh. 19 - Prob. 19.23PCh. 19 - Prob. 19.24PCh. 19 - Prob. 19.25PCh. 19 - Prob. 19.26PCh. 19 - Prob. 19.27PCh. 19 - Prob. 19.28PCh. 19 - Prob. 19.29PCh. 19 - Prob. 19.30PCh. 19 - Prob. 19.31PCh. 19 - Prob. 19.32PCh. 19 - Prob. 19.33PCh. 19 - Prob. 19.34PCh. 19 - Prob. 19.35PCh. 19 - Prob. 19.36PCh. 19 - Prob. 19.37PCh. 19 - Prob. 19.38PCh. 19 - Prob. 19.39PCh. 19 - Prob. 19.40APCh. 19 - Prob. 19.41APCh. 19 - Prob. 19.42APCh. 19 - Prob. 19.43APCh. 19 - Prob. 19.44APCh. 19 - Prob. 19.45APCh. 19 - Prob. 19.46APCh. 19 - Prob. 19.47APCh. 19 - Prob. 19.48APCh. 19 - Prob. 19.49APCh. 19 - Prob. 19.50APCh. 19 - Prob. 19.51APCh. 19 - Prob. 19.53APCh. 19 - Prob. 19.54APCh. 19 - Prob. 19.55APCh. 19 - Prob. 19.56APCh. 19 - Prob. 19.57APCh. 19 - Prob. 19.58APCh. 19 - Prob. 19.59APCh. 19 - Prob. 19.60APCh. 19 - Prob. 19.61APCh. 19 - Prob. 19.62APCh. 19 - Prob. 19.63APCh. 19 - Prob. 19.64APCh. 19 - Prob. 19.65APCh. 19 - Prob. 19.66APCh. 19 - Prob. 19.67APCh. 19 - Prob. 19.68APCh. 19 - Prob. 19.69APCh. 19 - Prob. 19.70APCh. 19 - Prob. 19.71APCh. 19 - Prob. 19.72AP
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- Compound 2 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Provide structure for compound 2, explain how you reached your conclusion.arrow_forwardDraw the structure for C5H10O with 1H NMR signals: δ 1.2 (s, 6H), 2.1 (bs, 1H), 5.0 (dd, 1H), 5.2 (dd, 1H), and 5.9 (dd, 1H).arrow_forwardCompound X (molecular formula C10H12O) was treated with NH2NH2, −OH to yield compound Y (molecular formula C10H14). Based on the 1HNMR spectra of X and Y given below, what are the structures of X and Y?arrow_forward
- Shown below are carbon NMR spectra for various isomers of C5H11Br. Assign structures for the compound that would produce each spectrum.arrow_forwardThe following 1H NMR spectra are for four compounds, each with molecular formula of C6H12O2. Identify the compounds.arrow_forwardThe 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forward
- Indicate two basic differences that exist between the spectra of 1H y 13C in NMR.arrow_forwardCompound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forwardAnalyze the 13C-NMR spectrum of C8H9NO given below and draw the structure of the compound.arrow_forward
- Identify the compound with molecular formula C7H14O that gives the following proton-coupled 13C NMR spectrum:arrow_forwardDetermine the correct structure of the compound, which shows following 13C NMR DEPT-135 data is 13C NMR DEPT-135: negative peaks at δ30.2, 31.9, 61.8, 114.7 ppm; positive peak at 130.4 ppm.arrow_forwardPropose a structure given the 1H and 13C NMR spectra of the unknown compound. Assign chemical shifts to corresponding hydrogen and carbon atoms Molecular Formula: C5H10O3arrow_forward
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