General Chemistry: Atoms First
General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Chapter 20, Problem 20.33SP

(a)

Interpretation Introduction

Interpretation:

Electronic configuration should be determined for given elements.

Concept Introduction:

Electronic configuration:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. (1) Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. (2) The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. (3) In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

(b)

Interpretation Introduction

Interpretation:

Electronic configuration should be determined for given elements.

Concept Introduction:

Electronic configuration:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. (1) Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. (2) The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. (3) In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

(c)

Interpretation Introduction

Interpretation:

Electronic configuration should be determined for the given atom.

Concept Introduction:

Electronic configuration:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. (1) Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. (2) The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. (3) In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

(d)

Interpretation Introduction

Interpretation:

Electronic configuration should be determined for the given elements.

Concept Introduction:

Electronic configuration:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. (1) Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. (2) The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. (3) In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

(e)

Interpretation Introduction

Interpretation:

Electronic configuration should be determined for the given elements.

Concept Introduction:

Electronic configuration:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. (1) Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. (2) The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. (3) In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

(f)

Interpretation Introduction

Interpretation:

Electronic configuration should be determined for given elements.

Concept Introduction:

Electronic configuration:

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

  1. (1) Electrons occupy the lowest energy orbitals. The increasing order of orbital energy is s, p, d and f. The lowest energy orbital is 1s. The energy order of the orbital for the first three period is given below,

    1s, 2s, 2p, 3s,and 3p.

  2. (2) The orbital which is closer to the nucleus has lower energy, therefore the 2s is lower in energy than 3s. Accordingly 2s is lower in energy than 2p and 4s is lower in energy than 3d.
  3. (3) In general, the orbitals can hold maximum of two electrons, the two electrons must have opposite spin.

The subshell ordering by Aufbau principle is given below, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 8s, ...

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Chapter 20 Solutions

General Chemistry: Atoms First

Ch. 20.8 - Prob. 20.11PCh. 20.8 - Prob. 20.12CPCh. 20.9 - Prob. 20.13PCh. 20.9 - Prob. 20.14CPCh. 20.9 - Prob. 20.15PCh. 20.10 - Prob. 20.16PCh. 20.11 - Prob. 20.17PCh. 20.12 - Prob. 20.18PCh. 20.12 - Prob. 20.19PCh. 20.12 - Prob. 20.20PCh. 20.12 - Prob. 20.21PCh. 20 - Prob. 20.22CPCh. 20 - Prob. 20.23CPCh. 20 - Prob. 20.24CPCh. 20 - Prob. 20.25CPCh. 20 - What is the systematic name for each of the...Ch. 20 - Prob. 20.27CPCh. 20 - Prob. 20.28CPCh. 20 - Prob. 20.29CPCh. 20 - Predict the crystal field energy-level diagram for...Ch. 20 - Prob. 20.31CPCh. 20 - Use the periodic table to give the electron...Ch. 20 - Prob. 20.33SPCh. 20 - Prob. 20.34SPCh. 20 - Prob. 20.35SPCh. 20 - Prob. 20.36SPCh. 20 - Prob. 20.37SPCh. 20 - Prob. 20.38SPCh. 20 - Prob. 20.39SPCh. 20 - What is the lanthanide contraction, and why does...Ch. 20 - The atomic radii of zirconium and hafnium are...Ch. 20 - Calculate the sum of the first two ionization...Ch. 20 - Prob. 20.43SPCh. 20 - Prob. 20.44SPCh. 20 - Prob. 20.45SPCh. 20 - Prob. 20.46SPCh. 20 - Prob. 20.47SPCh. 20 - Prob. 20.48SPCh. 20 - Prob. 20.49SPCh. 20 - Prob. 20.50SPCh. 20 - Prob. 20.51SPCh. 20 - Prob. 20.52SPCh. 20 - Prob. 20.53SPCh. 20 - Prob. 20.54SPCh. 20 - Prob. 20.55SPCh. 20 - Write a balanced equation for the industrial...Ch. 20 - Prob. 20.57SPCh. 20 - Prob. 20.58SPCh. 20 - Prob. 20.59SPCh. 20 - Prob. 20.60SPCh. 20 - Prob. 20.61SPCh. 20 - Prob. 20.62SPCh. 20 - Prob. 20.63SPCh. 20 - Prob. 20.64SPCh. 20 - Prob. 20.65SPCh. 20 - Prob. 20.66SPCh. 20 - Prob. 20.67SPCh. 20 - Prob. 20.68SPCh. 20 - Prob. 20.69SPCh. 20 - Prob. 20.70SPCh. 20 - Prob. 20.71SPCh. 20 - Prob. 20.72SPCh. 20 - Prob. 20.73SPCh. 20 - What is the formula of a complex that has each of...Ch. 20 - What is the formula, including the charge, for...Ch. 20 - Prob. 20.76SPCh. 20 - Prob. 20.77SPCh. 20 - Prob. 20.78SPCh. 20 - Prob. 20.79SPCh. 20 - Prob. 20.80SPCh. 20 - Prob. 20.81SPCh. 20 - What is the systematic name for each of the...Ch. 20 - Prob. 20.83SPCh. 20 - Prob. 20.84SPCh. 20 - Prob. 20.85SPCh. 20 - Prob. 20.86SPCh. 20 - Prob. 20.87SPCh. 20 - Prob. 20.88SPCh. 20 - Tell how many diastereoisomers are possible for...Ch. 20 - Which of the following complexes are chiral? (a)...Ch. 20 - Prob. 20.91SPCh. 20 - Prob. 20.92SPCh. 20 - Prob. 20.93SPCh. 20 - Prob. 20.94SPCh. 20 - Prob. 20.95SPCh. 20 - Prob. 20.96SPCh. 20 - Prob. 20.97SPCh. 20 - Prob. 20.98SPCh. 20 - Prob. 20.99SPCh. 20 - Prob. 20.100SPCh. 20 - Prob. 20.101SPCh. 20 - Prob. 20.102SPCh. 20 - Prob. 20.103SPCh. 20 - Prob. 20.104SPCh. 20 - Prob. 20.105SPCh. 20 - For each of the following complexes, draw a...Ch. 20 - Prob. 20.107SPCh. 20 - Prob. 20.108SPCh. 20 - Prob. 20.109SPCh. 20 - Prob. 20.110SPCh. 20 - Prob. 20.111SPCh. 20 - Prob. 20.112SPCh. 20 - Prob. 20.113SPCh. 20 - Prob. 20.114CHPCh. 20 - Prob. 20.115CHPCh. 20 - Prob. 20.116CHPCh. 20 - Prob. 20.117CHPCh. 20 - Prob. 20.118CHPCh. 20 - Prob. 20.119CHPCh. 20 - Prob. 20.120CHPCh. 20 - Prob. 20.121CHPCh. 20 - Prob. 20.122CHPCh. 20 - Prob. 20.123CHPCh. 20 - Prob. 20.124CHPCh. 20 - Draw a crystal field energy-level diagram, and...Ch. 20 - Prob. 20.126CHPCh. 20 - Prob. 20.127CHPCh. 20 - Prob. 20.128CHPCh. 20 - Prob. 20.129CHPCh. 20 - Prob. 20.130CHPCh. 20 - Look at the colors of the isomeric complexes in...Ch. 20 - The amount of paramagnetism for a first-series...Ch. 20 - Prob. 20.133CHPCh. 20 - Prob. 20.134CHPCh. 20 - Prob. 20.135CHPCh. 20 - For each of the following, (i) give the systematic...Ch. 20 - Prob. 20.137CHPCh. 20 - Prob. 20.138CHPCh. 20 - Prob. 20.139MPCh. 20 - Formation constants for the ammonia and...Ch. 20 - Prob. 20.141MPCh. 20 - Prob. 20.143MPCh. 20 - An alternative to cyanide leaching of gold ores is...
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