Organic Chemistry
Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
bartleby

Concept explainers

Question
Book Icon
Chapter 7.SE, Problem 46AP
Interpretation Introduction

a)

Organic Chemistry, Chapter 7.SE, Problem 46AP , additional homework tip  1

Interpretation:

To assign E or Z configuration for the compound given.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom of the two substituents separately. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms away from double bond are considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms. The isomer that has the higher ranked groups on each carbon are on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on opposite sides, the alkene is said to have E configuration.

To assign:

The configuration for the compound given as E or Z.

Interpretation Introduction

b)

Organic Chemistry, Chapter 7.SE, Problem 46AP , additional homework tip  2

Interpretation:

To assign E or Z configuration for the compound given.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom of the two substituents separately. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms away from double bond are considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms. The isomer that has the higher ranked groups on each carbon are on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on opposite sides, the alkene is said to have E configuration.

To assign:

The configuration for the compound given as E or Z.

Interpretation Introduction

c)

Organic Chemistry, Chapter 7.SE, Problem 46AP , additional homework tip  3

Interpretation:

To assign E or Z configuration for the compound given.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom of the two substituents separately. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms away from double bond are considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms. The isomer that has the higher ranked groups on each carbon are on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on opposite sides, the alkene is said to have E configuration.

To assign:

The configuration for the compound given as E or Z.

Interpretation Introduction

d)

Organic Chemistry, Chapter 7.SE, Problem 46AP , additional homework tip  4

Interpretation:

To assign E or Z configuration for the compound given.

Concept introduction:

The member that ranks higher can be determined by considering the atomic number of the first atom of the two substituents separately. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms away from double bond are considered until the first difference is found. Multiple bonded atoms are considered as equivalent to the same number of single bonded atoms. The isomer that has the higher ranked groups on each carbon are on the same side of the double bond is said to have Z configuration. If the higher ranked groups are on opposite sides, the alkene is said to have E configuration.

To assign:

The configuration for the compound given as E or Z.

Blurred answer
Students have asked these similar questions
Assign E or Z configuration to each of the following compounds:
Rank each set of compounds in order of decreasing λmax:
Classify the following pair of compounds as the same compound, enantiomers, diastereomers, constitutional isomers, or not isomeric. Also, select the correct IUPAC name, including the correct (R) or (S) designation, for each same compound enantiomers Н Н diastereomers с constitutional isomers not isomeric The correct IUPAC names are: Compound I: (2s,3S)-2,3-dichlorobutane, Compound I: (2R,3R)-2,3-dichlorobutane Compound I: (2R,3S)-2,3-dichlorobutane, Compound ll: (2s,3R)-2,3-dchlorobutane Compound I: (2R3R)-2,3-dichlorobutane, Compound l: (2R,3S)-2,3-dichlorobutane Compound I: (2S,3R)-2,3-dichlorobutane, Compound I: (2R,3S)-2,3-dichlorobutane

Chapter 7 Solutions

Organic Chemistry

Ch. 7.5 - Which member in each of the following sets ranks...Ch. 7.5 - Prob. 12PCh. 7.5 - Prob. 13PCh. 7.5 - Prob. 14PCh. 7.6 - Prob. 15PCh. 7.8 - Prob. 16PCh. 7.8 - Prob. 17PCh. 7.9 - Show the structures of the carbocation...Ch. 7.9 - Draw a skeletal structure of the following...Ch. 7.10 - Prob. 20PCh. 7.11 - On treatment with HBr, vinylcyclohexane undergoes...Ch. 7.SE - Prob. 22VCCh. 7.SE - Prob. 23VCCh. 7.SE - The following carbocation is an intermediate in...Ch. 7.SE - Prob. 25VCCh. 7.SE - Predict the major product and show the complete...Ch. 7.SE - Prob. 27MPCh. 7.SE - When 1, 3-butadiene reacts with one mole of HBr,...Ch. 7.SE - When methyl vinyl ether reacts with a strong acid,...Ch. 7.SE - Addition of HCl to 1-isopropylcyclohexene yields a...Ch. 7.SE - Addition of HCl to...Ch. 7.SE - Limonene, a fragrant hydrocarbon found in lemons...Ch. 7.SE - Prob. 33MPCh. 7.SE - Calculate the degree of unsaturation in the...Ch. 7.SE - Prob. 35APCh. 7.SE - Prob. 36APCh. 7.SE - Name the following alkenes:Ch. 7.SE - Draw structures corresponding to the following...Ch. 7.SE - Prob. 39APCh. 7.SE - Prob. 40APCh. 7.SE - Prob. 41APCh. 7.SE - Prob. 42APCh. 7.SE - Prob. 43APCh. 7.SE - Draw and name the 17 alkene isomers, C6H12,...Ch. 7.SE - Prob. 45APCh. 7.SE - Prob. 46APCh. 7.SE - Which of the following E, Z designations are...Ch. 7.SE - Prob. 48APCh. 7.SE - trans-2-Butene is more stable than cis-2-butene by...Ch. 7.SE - Prob. 50APCh. 7.SE - Normally, a trans alkene is more stable than its...Ch. 7.SE - trans-Cyclooctene is less stable than...Ch. 7.SE - Prob. 53APCh. 7.SE - Prob. 54APCh. 7.SE - Use Hammond’s Postulate to determine which...Ch. 7.SE - Prob. 56APCh. 7.SE - Predict the major product in each of the following...Ch. 7.SE - Prob. 58APCh. 7.SE - Prob. 59APCh. 7.SE - Prob. 60APCh. 7.SE - Allene (1,2-propadiene), H2C=C=CH2, has two...Ch. 7.SE - The heat of hydrogenation for allene (Problem...Ch. 7.SE - Retin A, or retinoic acid, is a medication...Ch. 7.SE - Prob. 64APCh. 7.SE - tert-Butyl esters [RC02C(CH3)3] are converted into...Ch. 7.SE - Vinylcyclopropane reacts with HBr to yield a...Ch. 7.SE - Prob. 67APCh. 7.SE - Prob. 68APCh. 7.SE - Prob. 69APCh. 7.SE - Prob. 70APCh. 7.SE - Prob. 71APCh. 7.SE - Reaction of 2, 3-dimethyl-l-butene with HBr leads...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning